Interpretation:
The number of monochlorination products obtained from the radical chlorination of 2-methylbutane including all stereoisomers should be given.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
In a halogenation reaction, one or more halogen atoms are introduced into an organic compound. Generally, these reactions are initiated in the presence of light or heat.
Chlorination:
2-methylpropane undergoes radical chlorination which yields the 2-chloro-2-methylpropane and 1-chloro-2-methylpropane.
Chiral: Four different atoms attached to a carbon atom is called chiral molecule.
Stereoisomers: Stereoisomers are molecules that have the same molecular formula and they differ only in arrangement of atom in three-dimensional space.
Enantiomers: A compound which is non-superimposable mirror image is called enantiomers.
Diastereomers: A compound which is non-superimposable and non-mirror image is called enantiomers
Total number of stereoisomers = 2n
Where n is the number of chiral centers.
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Chapter 14 Solutions
EP ESSENTIAL ORG.CHEM.-MOD.MASTERING
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- Don't used hand raiting and show all reactionsarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardIX) By writing the appropriate electron configurations and orbital box diagrams briefly EXPLAIN in your own words each one of the following questions: a) The bond length of the Br2 molecule is 2.28 Å, while the bond length of the compound KBr is 3.34 Å. The radius of K✶ is 1.52 Å. Determine the atomic radius in Å of the bromine atom and of the bromide ion. Br = Br b) Explain why there is a large difference in the atomic sizes or radius of the two (Br and Br). Tarrow_forward
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