Chapter 14.5, Problem 39ES

Express each integral as an equivalent integral in which the $z\text{-<x-custom-btb-me data-me-id="1678" class="microExplainerHighlight">integration</x-custom-btb-me>}$ is performed first, the $y\text{-integration}$ second, and the $x\text{-integration}$ last.

$\begin{array}{l}\left(\text{a}\right){\displaystyle {\int }_0^5{\displaystyle {\int }_0^2{\displaystyle {\int }_0^{\sqrt{4-y^2}}f\left(x,y,z\right)dxdydz}}}\\ \left(\text{b}\right){\displaystyle {\int }_0^9{\displaystyle {\int }_0^{3-\sqrt{x}}{\displaystyle {\int }_0^{z}f\left(x,y,z\right)dydzdx}}}\\ \left(\text{c}\right){\displaystyle {\int }_0^4{\displaystyle {\int }_y^{8-y}{\displaystyle {\int }_0^{\sqrt{4-y}}f\left(x,y,z\right)}dxdzdy}}\end{array}$