Explanation Given: f ( x ) = 2 x 2 + 1 c = − 1 Formula used: The derivative of y = f ( x ) at c is given by: f ′ ( c ) = lim x → c f ( x ) − f ( c ) x − c Calculation: Here, f ( x ) = 2 x 2 + 1 and c = − 1 . f ( c ) = f ( − 1 ) = 2 ( − 1 ) 2 + 1 = 2 + 1 = 3 Therefore, f ′ ( − 1 ) = lim x → − 1 f ( x ) − f ( − 1 ) x − ( − 1 ) f ′ ( − 1 ) = lim x → − 1 ( 2 x 2 + 1 − 3 x + 1 ) ...

11th Edition

ISBN: 9780136845881

Author: Sullivan

Publisher: VST

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Chapter 14.4, Problem 24AYU

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To find: The derivative of $f (x) = 2 x^{2} + 1$ at $- 1$ .

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Chapter 14.4, Problem 23AYU

Chapter 14.4, Problem 25AYU

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Chapter 14 Solutions

EBK PEARSON ETEXT PRECALCULUS -- ACCESS

Ch. 14.1 - Graph f( x )={ 3x2ifx2 3ifx=2 (pp.100-102)Ch. 14.1 - Prob. 2AYU Ch. 14.1 - Prob. 3AYU Ch. 14.1 - Prob. 4AYU Ch. 14.1 - True or False lim xc f( x )=N may be described by...Ch. 14.1 - Prob. 6AYU Ch. 14.1 - lim x2 ( 4 x 3 )Ch. 14.1 - lim x3 ( 2 x 2 +1 )Ch. 14.1 - lim x0 x+1 x 2 +1 Ch. 14.1 - Prob. 10AYU

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