Calculus
6th Edition
ISBN: 9781465208880
Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE
Publisher: Kendall Hunt Publishing
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Chapter 14.3, Problem 8PS
To determine
To solve:The trial solution for given differential equation.
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4. Use the method of undetermined coefficients to find a general solution of the equation
y" - 2y" - 4y + 8y = 6.xe²
1.2 Find the general solution of
dy
-2x6
dr +y =
y-4
11. Solve the problem
Chapter 14 Solutions
Calculus
Ch. 14.1 - Prob. 1PSCh. 14.1 - Prob. 2PSCh. 14.1 - Prob. 3PSCh. 14.1 - Prob. 4PSCh. 14.1 - Prob. 5PSCh. 14.1 - Prob. 6PSCh. 14.1 - Prob. 7PSCh. 14.1 - Prob. 8PSCh. 14.1 - Prob. 9PSCh. 14.1 - Prob. 10PS
Ch. 14.1 - Prob. 11PSCh. 14.1 - Prob. 12PSCh. 14.1 - Prob. 13PSCh. 14.1 - Prob. 14PSCh. 14.1 - Prob. 15PSCh. 14.1 - Prob. 16PSCh. 14.1 - Prob. 17PSCh. 14.1 - Prob. 18PSCh. 14.1 - Prob. 19PSCh. 14.1 - Prob. 20PSCh. 14.1 - Prob. 21PSCh. 14.1 - Prob. 22PSCh. 14.1 - Prob. 23PSCh. 14.1 - Prob. 24PSCh. 14.1 - Prob. 25PSCh. 14.1 - Prob. 26PSCh. 14.1 - Prob. 27PSCh. 14.1 - Prob. 28PSCh. 14.1 - Prob. 29PSCh. 14.1 - Prob. 30PSCh. 14.1 - Prob. 31PSCh. 14.1 - Prob. 32PSCh. 14.1 - Prob. 33PSCh. 14.1 - Prob. 34PSCh. 14.1 - Prob. 35PSCh. 14.1 - Prob. 36PSCh. 14.1 - Prob. 37PSCh. 14.1 - Prob. 38PSCh. 14.1 - Prob. 39PSCh. 14.1 - Prob. 40PSCh. 14.1 - Prob. 41PSCh. 14.1 - Prob. 42PSCh. 14.1 - Prob. 43PSCh. 14.1 - Prob. 44PSCh. 14.1 - Prob. 45PSCh. 14.1 - Prob. 46PSCh. 14.1 - Prob. 47PSCh. 14.1 - Prob. 48PSCh. 14.1 - Prob. 49PSCh. 14.1 - Prob. 50PSCh. 14.1 - Prob. 51PSCh. 14.1 - Prob. 52PSCh. 14.1 - Prob. 53PSCh. 14.1 - Prob. 54PSCh. 14.1 - Prob. 55PSCh. 14.1 - Prob. 56PSCh. 14.1 - Prob. 57PSCh. 14.1 - Prob. 58PSCh. 14.1 - Prob. 59PSCh. 14.1 - Prob. 60PSCh. 14.2 - Prob. 1PSCh. 14.2 - Prob. 2PSCh. 14.2 - Prob. 3PSCh. 14.2 - Prob. 4PSCh. 14.2 - Prob. 5PSCh. 14.2 - Prob. 6PSCh. 14.2 - Prob. 7PSCh. 14.2 - Prob. 8PSCh. 14.2 - Prob. 9PSCh. 14.2 - Prob. 10PSCh. 14.2 - Prob. 11PSCh. 14.2 - Prob. 12PSCh. 14.2 - Prob. 13PSCh. 14.2 - Prob. 14PSCh. 14.2 - Prob. 15PSCh. 14.2 - Prob. 16PSCh. 14.2 - Prob. 17PSCh. 14.2 - Prob. 18PSCh. 14.2 - Prob. 19PSCh. 14.2 - Prob. 20PSCh. 14.2 - Prob. 21PSCh. 14.2 - Prob. 22PSCh. 14.2 - Prob. 23PSCh. 14.2 - Prob. 24PSCh. 14.2 - Prob. 25PSCh. 14.2 - Prob. 26PSCh. 14.2 - Prob. 27PSCh. 14.2 - Prob. 28PSCh. 14.2 - Prob. 29PSCh. 14.2 - Prob. 30PSCh. 14.2 - Prob. 31PSCh. 14.2 - Prob. 32PSCh. 14.2 - Prob. 33PSCh. 14.2 - Prob. 34PSCh. 14.2 - Prob. 35PSCh. 14.2 - Prob. 36PSCh. 14.2 - Prob. 37PSCh. 14.2 - Prob. 38PSCh. 14.2 - Prob. 39PSCh. 14.2 - Prob. 40PSCh. 14.2 - Prob. 41PSCh. 14.2 - Prob. 42PSCh. 14.2 - Prob. 43PSCh. 14.2 - Prob. 44PSCh. 14.2 - Prob. 45PSCh. 14.2 - Prob. 46PSCh. 14.2 - Prob. 47PSCh. 14.2 - Prob. 48PSCh. 14.2 - Prob. 49PSCh. 14.2 - Prob. 50PSCh. 14.2 - Prob. 51PSCh. 14.2 - Prob. 52PSCh. 14.2 - Prob. 53PSCh. 14.2 - Prob. 54PSCh. 14.2 - Prob. 55PSCh. 14.2 - Prob. 56PSCh. 14.2 - Prob. 57PSCh. 14.2 - Prob. 58PSCh. 14.2 - Prob. 59PSCh. 14.2 - Prob. 60PSCh. 14.3 - Prob. 1PSCh. 14.3 - Prob. 2PSCh. 14.3 - Prob. 3PSCh. 14.3 - Prob. 4PSCh. 14.3 - Prob. 5PSCh. 14.3 - Prob. 6PSCh. 14.3 - Prob. 7PSCh. 14.3 - Prob. 8PSCh. 14.3 - Prob. 9PSCh. 14.3 - Prob. 10PSCh. 14.3 - Prob. 11PSCh. 14.3 - Prob. 12PSCh. 14.3 - Prob. 13PSCh. 14.3 - Prob. 14PSCh. 14.3 - Prob. 15PSCh. 14.3 - Prob. 16PSCh. 14.3 - Prob. 17PSCh. 14.3 - Prob. 18PSCh. 14.3 - Prob. 19PSCh. 14.3 - Prob. 20PSCh. 14.3 - Prob. 21PSCh. 14.3 - Prob. 22PSCh. 14.3 - Prob. 23PSCh. 14.3 - Prob. 24PSCh. 14.3 - Prob. 25PSCh. 14.3 - Prob. 26PSCh. 14.3 - Prob. 27PSCh. 14.3 - Prob. 28PSCh. 14.3 - Prob. 29PSCh. 14.3 - Prob. 30PSCh. 14.3 - Prob. 31PSCh. 14.3 - Prob. 32PSCh. 14.3 - Prob. 33PSCh. 14.3 - Prob. 34PSCh. 14.3 - Prob. 35PSCh. 14.3 - Prob. 36PSCh. 14.3 - Prob. 37PSCh. 14.3 - Prob. 38PSCh. 14.3 - Prob. 39PSCh. 14.3 - Prob. 40PSCh. 14.3 - Prob. 41PSCh. 14.3 - Prob. 42PSCh. 14.3 - Prob. 43PSCh. 14.3 - Prob. 44PSCh. 14.3 - Prob. 45PSCh. 14.3 - Prob. 46PSCh. 14.3 - Prob. 47PSCh. 14.3 - Prob. 48PSCh. 14.3 - Prob. 49PSCh. 14.3 - Prob. 50PSCh. 14.3 - Prob. 51PSCh. 14.3 - Prob. 52PSCh. 14.3 - Prob. 53PSCh. 14.3 - Prob. 54PSCh. 14.3 - Prob. 55PSCh. 14.3 - Prob. 56PSCh. 14.3 - Prob. 57PSCh. 14.3 - Prob. 58PSCh. 14.3 - Prob. 59PSCh. 14.3 - Prob. 60PSCh. 14 - Prob. 1PECh. 14 - Prob. 2PECh. 14 - Prob. 3PECh. 14 - Prob. 4PECh. 14 - Prob. 5PECh. 14 - Prob. 6PECh. 14 - Prob. 7PECh. 14 - Prob. 8PECh. 14 - Prob. 9PECh. 14 - Prob. 10PECh. 14 - Prob. 11PECh. 14 - Prob. 12PECh. 14 - Prob. 13PECh. 14 - Prob. 14PECh. 14 - Prob. 15PECh. 14 - Prob. 16PECh. 14 - Prob. 17PECh. 14 - Prob. 18PECh. 14 - Prob. 19PECh. 14 - Prob. 20PECh. 14 - Prob. 1SPCh. 14 - Prob. 2SPCh. 14 - Prob. 3SPCh. 14 - Prob. 4SPCh. 14 - Prob. 5SPCh. 14 - Prob. 6SPCh. 14 - Prob. 7SPCh. 14 - Prob. 8SPCh. 14 - Prob. 9SPCh. 14 - Prob. 10SPCh. 14 - Prob. 11SPCh. 14 - Prob. 12SPCh. 14 - Prob. 13SPCh. 14 - Prob. 14SPCh. 14 - Prob. 15SPCh. 14 - Prob. 16SPCh. 14 - Prob. 17SPCh. 14 - Prob. 18SPCh. 14 - Prob. 19SPCh. 14 - Prob. 20SPCh. 14 - Prob. 21SPCh. 14 - Prob. 22SPCh. 14 - Prob. 23SPCh. 14 - Prob. 24SPCh. 14 - Prob. 25SPCh. 14 - Prob. 26SPCh. 14 - Prob. 27SPCh. 14 - Prob. 28SPCh. 14 - Prob. 29SPCh. 14 - Prob. 30SPCh. 14 - Prob. 31SPCh. 14 - Prob. 32SPCh. 14 - Prob. 33SPCh. 14 - Prob. 34SPCh. 14 - Prob. 35SPCh. 14 - Prob. 36SPCh. 14 - Prob. 37SPCh. 14 - Prob. 38SPCh. 14 - Prob. 39SPCh. 14 - Prob. 40SPCh. 14 - Prob. 41SPCh. 14 - Prob. 42SPCh. 14 - Prob. 43SPCh. 14 - Prob. 44SPCh. 14 - Prob. 45SPCh. 14 - Prob. 46SPCh. 14 - Prob. 47SPCh. 14 - Prob. 48SPCh. 14 - Prob. 49SPCh. 14 - Prob. 50SPCh. 14 - Prob. 51SPCh. 14 - Prob. 52SPCh. 14 - Prob. 53SPCh. 14 - Prob. 54SPCh. 14 - Prob. 55SPCh. 14 - Prob. 56SPCh. 14 - Prob. 57SPCh. 14 - Prob. 58SPCh. 14 - Prob. 59SPCh. 14 - Prob. 60SP
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- Find the general solution to y = (1 – x)y² + (2x – 1)y – x. - Note that you can find an obvious solution to the equation.arrow_forwardFind a particular solution to y" + 7y + 10y = 1te". Yp =arrow_forward5. Some equations which do not appear to be separable can be made so by means of a suitable substitution. By means of the substitution z = y/x solve the equation dy y² Y + +1 dx x² x L aarrow_forward
- 1. Determine and sketch the solution to 2ä (t)+2x(t) + 32x(t) = 0 x (0) à (0) = -1. = 1 On the same plot, sketch the solution if the coefficient of , 2, is reduced slightly, say to 1.5 and also plot if the same term is increased slightly, say to 2.5. Clearly indicate on your plot what changes in the solution. Do not re-solve the equation.arrow_forwardFind a particular solution to y" +7y + 10y = 16te".arrow_forwardSolve the initial value problem. 2x²-x dy dx O B. = -x-5 (x + 1)(y + 1)' Begin by separating the variables. Choose the correct answer below. O C. A. (y + 1)dy=- y(1)=2 2x²-x-5 x²(x+1) x²(x+1) dy 2x²-x-5 -= dx x²(x+1)(y+1) -dx 2x² 1 -dy= -dx -X-5 y + 1 D. The equation is already separated. The solution is (Type an implicit solution. Type an equation using x and y as the variables.)arrow_forward
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