Explanation Given info. Radius of helix = 10 A 0 Height of helix = 34 A 0 Concept used: The parametric equation of a helix is x = a cos t y = a sin t z = b t Here: a radius of the helix, 2 π b : height of full turn of the helix. Calculation: Substitute a = 10 A 0 x = 10 cos t y = 10 sin t Substitute height of helix To determine (b) The arc length of one full turn of helix.

4th Edition

ISBN: 9781319323394

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 14.3, Problem 22E

To determine

(a)

Show that the helix can be parameterized by

$r (t) = 〈 10 \cos t, 10 \sin t, \frac{34 t}{2 π} 〉$

To determine

(b)

The arc length of one full turn of helix.

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Chapter 14.3, Problem 21E

Chapter 14.3, Problem 23E

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Chapter 14 Solutions

CALCULUS W/SAPLING ACCESS >IC<

Ch. 14.1 - Prob. 1PQ Ch. 14.1 - Prob. 2PQ Ch. 14.1 - Prob. 3PQ Ch. 14.1 - Prob. 4PQ Ch. 14.1 - Prob. 5PQ Ch. 14.1 - Prob. 6PQ Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E

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(a) Show that the helix can be parameterized by r ( t ) = 〈 10 cos t , 10 sin t , 34 t 2 π 〉

Solution Summary: The author explains that the helix can be parameterized by r (t) = 10 cos t, 10 sin

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(a)

Show that the helix can be parameterized by

$r (t) = 〈 10 \cos t, 10 \sin t, \frac{34 t}{2 π} 〉$

(b)

The arc length of one full turn of helix.

Want to see the full answer?

Chapter 14 Solutions

(a) Show that the helix can be parameterized by r ( t ) = 〈 10 cos t , 10 sin t , 34 t 2 π 〉

Solution Summary: The author explains that the helix can be parameterized by r (t) = 10 cos t, 10 sin

Concept explainers

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(a) Show that the helix can be parameterized by r(t)=〈10cost,10sint,34t2π〉

(b) The arc length of one full turn of helix.

Want to see the full answer?

Chapter 14 Solutions

(a)

Show that the helix can be parameterized by

$r (t) = 〈 10 \cos t, 10 \sin t, \frac{34 t}{2 π} 〉$

(b)

The arc length of one full turn of helix.