Explanation Given: The given function is d r ( cos θ ) d θ , r ( s ) = 〈 s , 2 s , s 2 〉 Calculation: We know that the derivative of a real valued function r ( t ) = 〈 x ( t ) , y ( t ) , z ( t ) 〉 is given by r ′ ( t ) = d ( r ( t ) ) d t = 〈 x ′ ( t ) , y ′ ( t ) , z ′ ( t ) 〉 We know that the derivative of a real valued function x n i s g i v e n b y n x n − 1 . Using chain rule, we know that d r ( g ( t ) ) d t = g ′ ( t ) r ′ ( g ( t ) ) d r ( cos θ ) d θ , r ( s ) = 〈 s , 2 s , s 2 〉 (I) r ( g ( s ) ) = r ( cos θ ) = 〈 cos θ , 2 cos θ , cos 2 θ 〉 l e t x ( θ ) = cos θ x ′ ( θ ) = d ( cos θ ) d θ x

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Chapter 14, Problem 10CRE

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To find:The derivative of given function $\frac{d r (\cos θ)}{d θ}, r (s) = 〈 s, 2 s, s^{2} 〉$

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Chapter 14, Problem 9CRE

Chapter 14, Problem 11CRE

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Chapter 14 Solutions

CALCULUS W/SAPLING ACCESS >IC<

Ch. 14.1 - Prob. 1PQ Ch. 14.1 - Prob. 2PQ Ch. 14.1 - Prob. 3PQ Ch. 14.1 - Prob. 4PQ Ch. 14.1 - Prob. 5PQ Ch. 14.1 - Prob. 6PQ Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E

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The derivative of given function d r ( cos θ ) d θ , r ( s ) = 〈 s , 2 s , s 2 〉

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To find:The derivative of given function dr(cosθ)dθ , r(s)=〈s,2s,s2〉

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Chapter 14 Solutions

To find:The derivative of given function $\frac{d r (\cos θ)}{d θ}, r (s) = 〈 s, 2 s, s^{2} 〉$