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Concept explainers
Every 10 years, the United States takes a census. The census tries to count every resident. There have been two forms, known as the “short form,” answered by most people, and the “long form,” slogged through by about one in six or seven households chosen at random. (For the 2010 Census, the long form was replaced by the American Community Survey.) According to the Census Bureau (www.census.gov), “. . . each estimate based on the long form responses has an associated confidence interval.”
The Census Bureau goes on to say, “These confidence intervals are wider . . . for geographic areas with smaller populations and for characteristics that occur less frequently in the area being examined (such as the proportion of people in poverty in a middle-income neighborhood).”
To deal with this problem, the Census Bureau reports long-form data only for “. . . geographic areas from which about two hundred or more long forms were completed—which are large enough to produce good quality estimates. If smaller weighting areas had been used, the confidence intervals around the estimates would have been significantly wider, rendering many estimates less useful. . . .”
4. Suppose the Census Bureau decided to report on areas from which only 50 long forms were completed. What effect would that have on a 95% confidence interval for, say, the mean cost of housing? Specifically, which values used in the formula for the margin of error would change? Which would change a lot and which would change only slightly?
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Chapter 14 Solutions
Intro Stats, Books a la carte Plus NEW MyLab Statistics with Pearson eText -- Access Card Package (5th Edition)
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- solve this on paperarrow_forwardApply STATA commands & submit the output for each question only when indicated below i. Apply the command egen to create a variable called "wyd" which is the rowtotal function on variables bwght & faminc. ii. Apply the list command for the first 10 observations to show that the code in part i worked. Include the outcome of this code iii. Apply the egen command to create a new variable called "bwghtsum" using the sum function on variable bwght by the variable high_faminc (Note: need to apply the bysort' statement) iv. Apply the "by high_faminc" statement to find the V. descriptive statistics of bwght and bwghtsum Include the output of this code. Why is there a difference between the standard deviations of bwght and bwghtsum from part iv of this question?arrow_forwardAccording to a health information website, the distribution of adults’ diastolic blood pressure (in millimeters of mercury, mmHg) can be modeled by a normal distribution with mean 70 mmHg and standard deviation 20 mmHg. b. Above what diastolic pressure would classify someone in the highest 1% of blood pressures? Show all calculations used.arrow_forward
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