The value of the distance d from the observer to the plane when θ = 30 ° , if an airplane is flying at an altitude of 6 miles and θ is the angle of elevation from the observer to the plane as shown in the figure below.
The value of the distance d from the observer to the plane when θ = 30 ° , if an airplane is flying at an altitude of 6 miles and θ is the angle of elevation from the observer to the plane as shown in the figure below.
Solution Summary: The author calculates the value of the distance from the observer to the plane when theta =30°, if an airplane is flying at an altitude of 6miles and
Figure in plane geometry formed by two rays or lines that share a common endpoint, called the vertex. The angle is measured in degrees using a protractor. The different types of angles are acute, obtuse, right, straight, and reflex.
Chapter 1.4, Problem 97E
(a)
To determine
To calculate: The value of the distance d from the observer to the plane when θ=30°, if an airplane is flying at an altitude of 6 miles and θ is the angle of elevation from the observer to the plane as shown in the figure below.
(b)
To determine
To calculate: The value of the distance d from the observer to the plane when θ=90°, if an airplane is flying at an altitude of 6 miles and θ is the angle of elevation from the observer to the plane as shown in the figure below:
(c)
To determine
To calculate: The value of the distance d from the observer to the plane when θ=120°, if an airplane is flying at an altitude of 6 miles and θ is the angle of elevation from the observer to the plane as shown in the figure below,
Find the angle 8 (in radians and degrees) between the lines.
x + 3y = 3
x - 2y = -2
0
||
0 =
-10
5
y
radians
10
5
-5
-10
0
10
X
Explation of Angle
Give an exact expression for y as a function of a, angle B and angle Cif A = 45° and D = 60°.
Simplify your answer, rationalize denominators as needed.
y=
B
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