Fundamentals Of Thermal-fluid Sciences In Si Units
Fundamentals Of Thermal-fluid Sciences In Si Units
5th Edition
ISBN: 9789814720953
Author: Yunus Cengel, Robert Turner, John Cimbala
Publisher: McGraw-Hill Education
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Chapter 14, Problem 85P
To determine

The flow rate through pipe B.

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Problem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/s
Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4
Problem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…

Chapter 14 Solutions

Fundamentals Of Thermal-fluid Sciences In Si Units

Ch. 14 - Shown here is a cool picture of water being...Ch. 14 - Someone claims that the volume flow rate in a...Ch. 14 - Someone claims that the average velocity in a...Ch. 14 - Someone claims that the shear stress at the center...Ch. 14 - Someone claims that in fully developed turbulent...Ch. 14 - How does the wall shear stress τw vary along the...Ch. 14 - In the fully developed region of flow in a...Ch. 14 - How is the friction factor for flow in a pipe...Ch. 14 - Discuss whether fully developed pipe flow is one-,...Ch. 14 - Consider fully developed flow in a circular pipe...Ch. 14 - Consider fully developed laminar flow in a...Ch. 14 - Explain why the friction factor is independent of...Ch. 14 - What is turbulent viscosity? What causes it? Ch. 14 - Consider fully developed laminar flow in a...Ch. 14 - How is head loss related to pressure loss? For a...Ch. 14 - Consider laminar flow of air in a circular pipe...Ch. 14 - What is the physical mechanism that causes the...Ch. 14 - The velocity profile for the fully developed...Ch. 14 - Water flows steadily through a reducing pipe...Ch. 14 - Water at 10°C (ρ = 999.7 kg/m3 and μ = 1.307 ×...Ch. 14 - Consider an air solar collector that is 1 m wide...Ch. 14 - Heated air at 1 atm and 100°F is to be transported...Ch. 14 - In fully developed laminar flow in a circular...Ch. 14 - The velocity profile in fully developed laminar...Ch. 14 - Repeat Prob. 14–34 for a pipe of inner radius 7...Ch. 14 - Water at 15°C (ρ = 999.1 kg/m3 and μ = 1.138 ×...Ch. 14 - Consider laminar flow of a fluid through a square...Ch. 14 - Repeat Prob. 14–37 for turbulent flow in smooth...Ch. 14 - Air enters a 10-m-long section of a rectangular...Ch. 14 - Water at 70°F passes through...Ch. 14 - Oil with ρ = 876 kg/m3 and μ = 0.24 kg/m·s is...Ch. 14 - Glycerin at 40°C with ρ = 1252 kg/m3 and μ = 0.27...Ch. 14 - Air at 1 atm and 60°F is flowing through a 1 ft ×...Ch. 14 - Prob. 44PCh. 14 - Prob. 45PCh. 14 - Oil with a density of 850 kg/m3 and kinematic...Ch. 14 - Prob. 47PCh. 14 - Prob. 48PCh. 14 - Prob. 50PCh. 14 - Prob. 51PCh. 14 - Prob. 52PCh. 14 - Prob. 53PCh. 14 - Prob. 54PCh. 14 - Prob. 55PCh. 14 - Prob. 56PCh. 14 - Prob. 57PCh. 14 - Water is to be withdrawn from an 8-m-high water...Ch. 14 - Prob. 59PCh. 14 - Prob. 60PCh. 14 - Prob. 61PCh. 14 - Prob. 62PCh. 14 - Prob. 63PCh. 14 - Prob. 64PCh. 14 - Consider two identical 2-m-high open tanks filled...Ch. 14 - A piping system involves two pipes of different...Ch. 14 - Prob. 67PCh. 14 - Prob. 68PCh. 14 - Prob. 69PCh. 14 - Prob. 70PCh. 14 - The water needs of a small farm are to be met by...Ch. 14 - Prob. 72PCh. 14 - Prob. 73PCh. 14 - Prob. 74PCh. 14 - Prob. 75PCh. 14 - Prob. 76PCh. 14 - Prob. 77PCh. 14 - Prob. 78PCh. 14 - Prob. 80PCh. 14 - Prob. 81PCh. 14 - A vented tanker is to be filled with fuel oil with...Ch. 14 - Two pipes of identical length and material are...Ch. 14 - Prob. 84PCh. 14 - Prob. 85PCh. 14 - Prob. 86PCh. 14 - Prob. 87PCh. 14 - Prob. 88PCh. 14 - Prob. 90PCh. 14 - Prob. 91PCh. 14 - Prob. 92PCh. 14 - Prob. 93PCh. 14 - Prob. 94RQCh. 14 - Prob. 95RQCh. 14 - Prob. 96RQCh. 14 - Prob. 97RQCh. 14 - Prob. 98RQCh. 14 - Prob. 99RQCh. 14 - Repeat Prob. 14–99E assuming the pipe is inclined...Ch. 14 - Prob. 101RQCh. 14 - Prob. 102RQCh. 14 - Prob. 103RQCh. 14 - Prob. 104RQCh. 14 - Two pipes of identical diameter and material are...Ch. 14 - Prob. 106RQCh. 14 - Prob. 107RQCh. 14 - Prob. 108RQCh. 14 - Prob. 109RQCh. 14 - Prob. 110RQCh. 14 - Prob. 111RQCh. 14 - Prob. 112RQCh. 14 - Prob. 114RQCh. 14 - Prob. 115RQCh. 14 - Prob. 116RQCh. 14 - Prob. 118RQ
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Fluid Mechanics - Viscosity and Shear Strain Rate in 9 Minutes!; Author: Less Boring Lectures;https://www.youtube.com/watch?v=_0aaRDAdPTY;License: Standard youtube license