For each of the given solution, the pH of the solution is to be determined from the given pOH values and based on the pH value, each solution is to be classified as acidic, basic or neutral. Concept introduction: The sum of pH and pOH in a solution is always equals to a constant at a constant temperature. At 25 ° C , the sum is equal to 14.00 and it can be shown mathematically as follows: pH + pOH = 14 .0 The pH scale is used to classify the solution as follows: The solution having pH value less than 7 is acidic. The solution having pH value greater than 7 is basic. If the solution has pH equal to 7, then it is neutral.
For each of the given solution, the pH of the solution is to be determined from the given pOH values and based on the pH value, each solution is to be classified as acidic, basic or neutral. Concept introduction: The sum of pH and pOH in a solution is always equals to a constant at a constant temperature. At 25 ° C , the sum is equal to 14.00 and it can be shown mathematically as follows: pH + pOH = 14 .0 The pH scale is used to classify the solution as follows: The solution having pH value less than 7 is acidic. The solution having pH value greater than 7 is basic. If the solution has pH equal to 7, then it is neutral.
Solution Summary: The author explains how the pH scale is used to classify the solution as acidic, basic or neutral.
For each of the given solution, the pH of the solution is to be determined from the given pOH values and based on the pH value, each solution is to be classified as acidic, basic or neutral.
Concept introduction:
The sum of pH and pOH in a solution is always equals to a constant at a constant temperature. At 25°C, the sum is equal to 14.00 and it can be shown mathematically as follows:
pH+pOH=14.0
The pH scale is used to classify the solution as follows:
The solution having pH value less than 7 is acidic.
The solution having pH value greater than 7 is basic.
If the solution has pH equal to 7, then it is neutral.
4. Calculate the total number of sigma bonds and total number of pi bonds in each of the following
compounds.
a.
HH :D:
+1
I
H-N-C-C-O-H
I
H
b.
HH H
Н
:N=C-C-C=C-CEC-H
:0:
total o
H-C-H
H-C = `C-H
I
H.
11
H-C = C=
CH
H
total o
total π
total π
1
H
In the following reaction, what quantity in moles of CH₃OH are required to give off 4111 kJ of heat? 2 CH₃OH (l) + 3 O₂ (g) → 2 CO₂ (g) + 4 H₂O(g) ∆H° = -1280. kJ
Indicate the processes in the dismutation of Cu2O.
Chapter 14 Solutions
Introductory Chemistry Plus Mastering Chemistry with Pearson eText -- Access Card Package (6th Edition) (New Chemistry Titles from Niva Tro)
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