Chapter 14, Problem 82E

Interpretation Introduction

Interpretation:

For each given solution, the $\text{pOH}$ value is to be determined.

Concept Introduction:

The $\text{pH}$ of the solution is given by the negative of the logarithm of $\left[{\text{H}}_{\text{3}}{\text{O}}^{+}\right]$.

Mathematically, it is written as follows:

$\text{pH}=-\log \left[{\text{H}}_{\text{3}}{\text{O}}^{+}\right]$ …… (1)

Similarly, the $\text{pOH}$ value of the solution is the negative of the logarithm of $\left[{\text{OH}}^{-}\right]$.

Mathematically, it is written as follows:

$\text{pOH}=-\log \left[{\text{OH}}^{-}\right]$ …… (2)

The sum of $\text{pH}$ and $\text{pOH}$ at $25{}^{°}\text{C}$ is equaled to 14 and it can be shown mathematically as follows:

$\text{pH}+\text{pOH}=\text{14}$ …… (3)