(a) Interpretation: The molarity of a solution of HClO 4 of amount 25.00mL is to be determined by the student. The student is also using 0.731M KOH. He forgets to add the indicator in solution after the addition of KOH of volume 42.35 mL into the solution. At this condition, he takes the pH of the solution which is 12.39. It has to be determined if the student go beyond equivalence point or not. Concept introduction: The titration is described as the process by which the concentration of the dissolved substance is to be determined in terms of the smallest amount of reagent of a given concentration. It can also be known as volumetric titration.
(a) Interpretation: The molarity of a solution of HClO 4 of amount 25.00mL is to be determined by the student. The student is also using 0.731M KOH. He forgets to add the indicator in solution after the addition of KOH of volume 42.35 mL into the solution. At this condition, he takes the pH of the solution which is 12.39. It has to be determined if the student go beyond equivalence point or not. Concept introduction: The titration is described as the process by which the concentration of the dissolved substance is to be determined in terms of the smallest amount of reagent of a given concentration. It can also be known as volumetric titration.
Solution Summary: The author explains how the molarity of HClO 4 is to be determined by the student, who forgets to add the indicator in the solution.
The molarity of a solution of HClO4 of amount 25.00mL is to be determined by the student. The student is also using 0.731M KOH. He forgets to add the indicator in solution after the addition of KOH of volume 42.35 mL into the solution. At this condition, he takes the pH of the solution which is 12.39. It has to be determined if the student go beyond equivalence point or not.
Concept introduction:
The titration is described as the process by which the concentration of the dissolved substance is to be determined in terms of the smallest amount of reagent of a given concentration. It can also be known as volumetric titration.
Interpretation Introduction
(b)
Interpretation:
The molarity of strong acid is to be determined.
Concept introduction:
The molarity can be calculated as follows:
molarity=number of moles of solute volume of solution(L)
The relation between pH and pOH is as follows:
pH+pOH=14
The pOH can be calculated as follows:
pOH=−log10[OH−]
Interpretation Introduction
(c)
Interpretation:
The volume of KOH is to be determined which is added in excess if he added. Or the volume of KOH is to be determined which is required to add if he didn’t add.
Blocking Group are use to put 2 large sterically repulsive group ortho. Show the correct sequence toconnect the reagent to product with the highest yield possible. * see image **NOTE: The compound on the left is the starting point, and the compound on the right is the final product. Please show the steps in between to get from start to final, please. These are not two different compounds that need to be worked.
I dont understand this.
Can you please explain this prooblem to me, show me how the conjugation is added, did I add them in the correct places and if so please show me. Thanks!
Chapter 14 Solutions
OWLv2 for Masterton/Hurley's Chemistry: Principles and Reactions, 8th Edition, [Instant Access], 1 term (6 months)
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