COMPTIA A+ GUIDE TO IT TECH SUPPORT
COMPTIA A+ GUIDE TO IT TECH SUPPORT
10th Edition
ISBN: 9780357466810
Author: ANDREWS
Publisher: CENGAGE L
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Chapter 14, Problem 7TC

Explanation of Solution

Given:

Application error.

To find: The method to eliminate the chances that an application error is caused by another application or due to some background process.

Solution:

1) To eliminate background programs or services as a source of the problem, run the application after booting into Safe Mode...

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> Comparable Method - methodName: String -priority: int + Method() + Method(methodName: String, priority: int) + abstract specificWay(): void + Getters and setters for all fields compareTo(otherMethod: Method): int + toString(): String ReadMethod - language: String + ReadMethod() + ReadMethod(methodName: String, priority: int, language: String) + specificWay(): void + Getters and setters for language + toString(): String Part 1.1. Implement the abstract class Method implements Comparable interface according to its UML diagram. Add comments stating where data fields, constructors, toString(), and other methods are (if any). Neither method should have an empty body unless abstract methods. 1. two constructors (default and the constructor with all fields) 2. getters and setters for all fields (methodName and priority). 3. toString() method: modify by yourself to match the example output. 4. Abstract method void specificWay(). 5. Implement compara To(Method otherMethod) to compare…
Exercise 1 Function and Structure [30 pts] Please debug the following program and answer the following questions. There is a cycle in a linked list if some node in the list can be reached again by continuously following the next pointer. #include typedef struct node { int value; struct node *next; } node; int ll_has_cycle (node *first) if (first NULL) return 0; node *head = first%;B while (head->next != NULL) { } if (head first) { return 1; } head = head->next;B return 0; void test_11_has_cycle() { int i; node nodes [6] ; for (i = 0; i < 6; i++) { nodes [i] .next = NULL; nodes [i].value i; nodes [0] .next = &nodes [1]; nodes [1] .next = &nodes [2]; nodes [2] .next &nodes [3]; nodes [3] .next nodes [4] .next & nodes [4]; NULL; nodes [5] .next &nodes [0]; printf("1. Checking first list for cycles. \n Function 11_has_cycle says it has %s cycle\n\n", 11_has_cycle (&nodes[0])?"a":"no"); printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle says it has %s cycle\n\n",…
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