Concept explainers
Interpretation:
The reason for the statement, “carbon atom is oxidized in the given reaction,” is to be explained.
Concept Introduction:
Oxidation is the addition of an electronegative element or the removal of an electropositive element in a
Reduction is the addition of an electropositive element or the removal of an electronegative element in a chemical reaction.
A chemical reaction in which oxidation process and reduction process take place simultaneously is called a
An oxidizing agent is a substance that has the capacity to oxidize other substances and get reduced in a chemical reaction.
A reducing agent is a substance that has the capacity to reduce other substances and get oxidized in a chemical reaction.
Carbon atoms have four valence electrons. Carbon is the less electronegative element. The carbon atom partially loses its valence electrons to attain the noble gas configuration. The carbon atom is oxidized.
Sulfur is the more electronegative element. The sulphur atom gains electrons to attain the noble gas configuration.
The carbon atom partially shares the valence electrons with the sulphur atom to form a carbon-sulphur covalent bond.
Want to see the full answer?
Check out a sample textbook solutionChapter 14 Solutions
Chemistry In Focus
- Pt + H₂ Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Templ 9 2 0 © 120arrow_forwardComplete boxes in the flow chart. Draw the structure of the organic compound foundin each layer after adding 3M NaOH and extraction. Make sure to include any charges. Provide explanation on answers.arrow_forward== Vid4Q2 Unanswered ☑ Provide IUPAC name of product in the reaction below A 3,4-dimethylcyclohexene B 1,2-dimethylcyclohexane C 1,2-dimethylcyclohexene D 3,4-dimethylcyclohexane H₂ Pdarrow_forward
- 5. Use the MS data to answer the questions on the next page. 14.0 1.4 15.0 8.1 100- MS-IW-5644 26.0 2.8 27.0 6.7 28.0 1.8 29.0 80 4.4 38.0 1.0 39.0 1.5 41.0 1.2 42.0 11.2 43.0 100.0 44.0 4.3 79.0 1.9 80.0 2.6 Relative Intensity 40 81.0 1.9 82.0 2.5 93.0 8.7 20- 95.0 8.2 121.0 2.0 123.0 2.0 136.0 11.8 0 138.0 11.5 20 40 8. 60 a. Br - 0 80 100 120 140 160 180 200 220 m/z Identify the m/z of the base peak and molecular ion. 2 b. Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0, 95.0, 136.0, and 138.0 m/z. C. Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to fragment 43.0 m/z. Be sure to include all electrons and formal charges. 6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium ion (CsH6N) and show your work.arrow_forwardNonearrow_forwardStereochemistry: Three possible answers- diastereomers, enantiomers OH CH₂OH I -c=0 21108 1101 41745 HOR CH₂OH IL Но CH₂OH TIL a. Compounds I and III have this relationship with each other: enantiomers b. Compounds II and IV have this relationship with each other: c. Compounds I and II have this relationship with each other: d. *Draw one structure that is a stereoisomer of II, but neither a diastereomer nor an enantiomer. (more than one correct answer)arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning