Chapter 14, Problem 76QAP

Interpretation Introduction

(a)

Interpretation:

The molarity of H₂ SO₄ solution is 0.1500M. The value of pH of this solution is to be determined when ionization of HSO₄ - is ignored.

Concept introduction:

The formula for the pH of the solution is −

$\text{pH}=-{\log }_{10}[{\text{H}}^{+}]$

Here, $[{\text{H}}^{+}]$ is the concentration of hydrogen ions in the solution.

Interpretation Introduction

(b)

Interpretation:

The molarity of the H₂ SO₄ solution is 0.1500M. The value of pH of this solution is to be determined when ionization of HSO₄ - is not ignored. The equilibrium constant of acid for HSO₄ - is 1.1×10-2.

Concept introduction:

The formula for the pH of the solution is −

$\text{pH}=-{\log }_{10}[{\text{H}}^{+}]$

Here, $[{\text{H}}^{+}]$ is the concentration of hydrogen ions in the solution.