EBK PRE-ALGEBRA
12th Edition
ISBN: 9780358403685
Author: Larson
Publisher: HM CC
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Question
Chapter 1.4, Problem 5C
To determine
To State: the absolute value and opposite of the number.
Expert Solution & Answer
Answer to Problem 5C
The absolute value of
Explanation of Solution
Given information:
Consider, the integer,
Concept used:
The absolute value is defined as the distance of a number from 0 on a number line.
Two numbers are opposite if they have the same absolute value but different signs.
The absolute value is obtained as:
The distance between
The opposite number is obtained as:
The opposite of
Chapter 1 Solutions
EBK PRE-ALGEBRA
Ch. 1.1 - Prob. 1CCh. 1.1 - Prob. 2CCh. 1.1 - Prob. 3CCh. 1.1 - Prob. 4CCh. 1.1 - Prob. 1ECh. 1.1 - Prob. 2ECh. 1.1 - Prob. 3ECh. 1.1 - Prob. 4ECh. 1.1 - Prob. 5ECh. 1.1 - Prob. 6E
Ch. 1.1 - Prob. 7ECh. 1.1 - Prob. 8ECh. 1.1 - Prob. 9ECh. 1.1 - Prob. 10ECh. 1.1 - Prob. 11ECh. 1.1 - Prob. 12ECh. 1.1 - Prob. 13ECh. 1.1 - Prob. 14ECh. 1.1 - Prob. 15ECh. 1.1 - Prob. 16ECh. 1.1 - Prob. 17ECh. 1.1 - Prob. 18ECh. 1.1 - Prob. 19ECh. 1.1 - Prob. 20ECh. 1.1 - Prob. 21ECh. 1.1 - Prob. 22ECh. 1.1 - Prob. 23ECh. 1.1 - Prob. 24ECh. 1.1 - Prob. 25ECh. 1.1 - Prob. 26ECh. 1.1 - Prob. 27ECh. 1.1 - Prob. 28ECh. 1.1 - Prob. 29ECh. 1.1 - Prob. 30ECh. 1.1 - Prob. 31ECh. 1.1 - Prob. 32ECh. 1.1 - Prob. 33ECh. 1.1 - Prob. 34ECh. 1.1 - Prob. 35ECh. 1.1 - Prob. 36ECh. 1.1 - Prob. 37ECh. 1.1 - Prob. 38ECh. 1.1 - Prob. 39ECh. 1.1 - Prob. 40ECh. 1.1 - Prob. 41ECh. 1.1 - Prob. 42ECh. 1.1 - Prob. 43ECh. 1.1 - Prob. 44ECh. 1.1 - Prob. 45ECh. 1.1 - Prob. 46ECh. 1.1 - Prob. 47ECh. 1.1 - Prob. 48ECh. 1.1 - Prob. 49ECh. 1.1 - Prob. 50ECh. 1.1 - Prob. 51ECh. 1.1 - Prob. 52ECh. 1.1 - Prob. 53ECh. 1.1 - Prob. 54ECh. 1.1 - Prob. 55ECh. 1.1 - Prob. 56ECh. 1.1 - Prob. 57ECh. 1.1 - Prob. 58ECh. 1.1 - Prob. 59ECh. 1.1 - Prob. 60ECh. 1.1 - Prob. 61ECh. 1.1 - Prob. 62ECh. 1.1 - Prob. 63ECh. 1.1 - Prob. 64ECh. 1.1 - Prob. 65ECh. 1.1 - Prob. 66ECh. 1.1 - Prob. 67ECh. 1.2 - Prob. 1CCh. 1.2 - Prob. 2CCh. 1.2 - Prob. 3CCh. 1.2 - Prob. 4CCh. 1.2 - Prob. 5CCh. 1.2 - Prob. 6CCh. 1.2 - Prob. 7CCh. 1.2 - Prob. 8CCh. 1.2 - Prob. 9CCh. 1.2 - Prob. 10CCh. 1.2 - Prob. 11CCh. 1.2 - Prob. 1ECh. 1.2 - Prob. 2ECh. 1.2 - Prob. 3ECh. 1.2 - Prob. 4ECh. 1.2 - Prob. 5ECh. 1.2 - Prob. 6ECh. 1.2 - Prob. 7ECh. 1.2 - Prob. 8ECh. 1.2 - Prob. 9ECh. 1.2 - Prob. 10ECh. 1.2 - Prob. 11ECh. 1.2 - Prob. 12ECh. 1.2 - Prob. 13ECh. 1.2 - Prob. 14ECh. 1.2 - Prob. 15ECh. 1.2 - Prob. 16ECh. 1.2 - Prob. 17ECh. 1.2 - Prob. 18ECh. 1.2 - Prob. 19ECh. 1.2 - Prob. 20ECh. 1.2 - Prob. 21ECh. 1.2 - Prob. 22ECh. 1.2 - Prob. 23ECh. 1.2 - Prob. 24ECh. 1.2 - Prob. 25ECh. 1.2 - Prob. 26ECh. 1.2 - Prob. 27ECh. 1.2 - Prob. 28ECh. 1.2 - Prob. 29ECh. 1.2 - Prob. 30ECh. 1.2 - Prob. 31ECh. 1.2 - Prob. 32ECh. 1.2 - Prob. 33ECh. 1.2 - Prob. 34ECh. 1.2 - Prob. 35ECh. 1.2 - Prob. 36ECh. 1.2 - Prob. 37ECh. 1.2 - Prob. 38ECh. 1.2 - Prob. 39ECh. 1.2 - Prob. 40ECh. 1.2 - Prob. 41ECh. 1.2 - Prob. 42ECh. 1.2 - Prob. 43ECh. 1.2 - Prob. 44ECh. 1.2 - Prob. 45ECh. 1.2 - Prob. 46ECh. 1.2 - Prob. 47ECh. 1.2 - Prob. 48ECh. 1.2 - Prob. 49ECh. 1.3 - Prob. 1CCh. 1.3 - Prob. 2CCh. 1.3 - Prob. 3CCh. 1.3 - Prob. 4CCh. 1.3 - Prob. 5CCh. 1.3 - Prob. 6CCh. 1.3 - Prob. 7CCh. 1.3 - Prob. 8CCh. 1.3 - Prob. 9CCh. 1.3 - Prob. 10CCh. 1.3 - Prob. 11CCh. 1.3 - Prob. 12CCh. 1.3 - Prob. 1ECh. 1.3 - Prob. 2ECh. 1.3 - Prob. 3ECh. 1.3 - Prob. 4ECh. 1.3 - Prob. 5ECh. 1.3 - Prob. 6ECh. 1.3 - Prob. 7ECh. 1.3 - Prob. 8ECh. 1.3 - Prob. 9ECh. 1.3 - Prob. 10ECh. 1.3 - Prob. 11ECh. 1.3 - Prob. 12ECh. 1.3 - Prob. 13ECh. 1.3 - Prob. 14ECh. 1.3 - Prob. 15ECh. 1.3 - Prob. 16ECh. 1.3 - Prob. 17ECh. 1.3 - Prob. 18ECh. 1.3 - Prob. 19ECh. 1.3 - Prob. 20ECh. 1.3 - Prob. 21ECh. 1.3 - Prob. 22ECh. 1.3 - Prob. 23ECh. 1.3 - Prob. 24ECh. 1.3 - Prob. 25ECh. 1.3 - Prob. 26ECh. 1.3 - Prob. 27ECh. 1.3 - Prob. 28ECh. 1.3 - Prob. 29ECh. 1.3 - Prob. 30ECh. 1.3 - Prob. 31ECh. 1.3 - Prob. 32ECh. 1.3 - Prob. 33ECh. 1.3 - Prob. 34ECh. 1.3 - Prob. 35ECh. 1.3 - Prob. 36ECh. 1.3 - Prob. 37ECh. 1.3 - Prob. 38ECh. 1.3 - Prob. 39ECh. 1.3 - Prob. 40ECh. 1.3 - Prob. 41ECh. 1.3 - Prob. 42ECh. 1.3 - Prob. 43ECh. 1.3 - Prob. 44ECh. 1.4 - Prob. 1CCh. 1.4 - Prob. 2CCh. 1.4 - Prob. 3CCh. 1.4 - Prob. 4CCh. 1.4 - Prob. 5CCh. 1.4 - Prob. 6CCh. 1.4 - Prob. 7CCh. 1.4 - Prob. 8CCh. 1.4 - Prob. 9CCh. 1.4 - Prob. 1ECh. 1.4 - Prob. 2ECh. 1.4 - Prob. 3ECh. 1.4 - Prob. 4ECh. 1.4 - Prob. 5ECh. 1.4 - Prob. 6ECh. 1.4 - Prob. 7ECh. 1.4 - Prob. 8ECh. 1.4 - Prob. 9ECh. 1.4 - Prob. 10ECh. 1.4 - Prob. 11ECh. 1.4 - Prob. 12ECh. 1.4 - Prob. 13ECh. 1.4 - Prob. 14ECh. 1.4 - Prob. 15ECh. 1.4 - Prob. 16ECh. 1.4 - Prob. 17ECh. 1.4 - Prob. 18ECh. 1.4 - Prob. 19ECh. 1.4 - Prob. 20ECh. 1.4 - Prob. 21ECh. 1.4 - Prob. 22ECh. 1.4 - Prob. 23ECh. 1.4 - Prob. 24ECh. 1.4 - Prob. 25ECh. 1.4 - Prob. 26ECh. 1.4 - Prob. 27ECh. 1.4 - Prob. 28ECh. 1.4 - Prob. 29ECh. 1.4 - Prob. 30ECh. 1.4 - Prob. 31ECh. 1.4 - Prob. 32ECh. 1.4 - Prob. 33ECh. 1.4 - Prob. 34ECh. 1.4 - Prob. 35ECh. 1.4 - Prob. 36ECh. 1.4 - Prob. 37ECh. 1.4 - Prob. 38ECh. 1.4 - Prob. 39ECh. 1.4 - Prob. 40ECh. 1.4 - Prob. 41ECh. 1.4 - Prob. 42ECh. 1.4 - Prob. 43ECh. 1.4 - Prob. 44ECh. 1.4 - Prob. 45ECh. 1.4 - Prob. 46ECh. 1.4 - Prob. 47ECh. 1.4 - Prob. 48ECh. 1.4 - Prob. 49ECh. 1.4 - Prob. 50ECh. 1.4 - Prob. 51ECh. 1.4 - Prob. 52ECh. 1.4 - Prob. 53ECh. 1.4 - Prob. 54ECh. 1.4 - Prob. 55ECh. 1.4 - Prob. 56ECh. 1.4 - Prob. 57ECh. 1.4 - Prob. 58ECh. 1.4 - Prob. 59ECh. 1.4 - Prob. 60ECh. 1.4 - Prob. 61ECh. 1.4 - Prob. 62ECh. 1.4 - Prob. 63ECh. 1.4 - Prob. 64ECh. 1.4 - Prob. 65ECh. 1.4 - Prob. 66ECh. 1.4 - Prob. 67ECh. 1.4 - Prob. 68ECh. 1.4 - Prob. 69ECh. 1.4 - Prob. 70ECh. 1.4 - Prob. 71ECh. 1.4 - Prob. 72ECh. 1.4 - Prob. 73ECh. 1.4 - Prob. 74ECh. 1.4 - Prob. 75ECh. 1.4 - Prob. 76ECh. 1.5 - Prob. 1CCh. 1.5 - Prob. 2CCh. 1.5 - Prob. 3CCh. 1.5 - Prob. 4CCh. 1.5 - Prob. 5CCh. 1.5 - Prob. 6CCh. 1.5 - Prob. 7CCh. 1.5 - Prob. 8CCh. 1.5 - Prob. 9CCh. 1.5 - Prob. 1ECh. 1.5 - Prob. 2ECh. 1.5 - Prob. 3ECh. 1.5 - Prob. 4ECh. 1.5 - Prob. 5ECh. 1.5 - Prob. 6ECh. 1.5 - Prob. 7ECh. 1.5 - Prob. 8ECh. 1.5 - Prob. 9ECh. 1.5 - Prob. 10ECh. 1.5 - Prob. 11ECh. 1.5 - Prob. 12ECh. 1.5 - Prob. 13ECh. 1.5 - Prob. 14ECh. 1.5 - Prob. 15ECh. 1.5 - Prob. 16ECh. 1.5 - Prob. 17ECh. 1.5 - Prob. 18ECh. 1.5 - Prob. 19ECh. 1.5 - Prob. 20ECh. 1.5 - Prob. 21ECh. 1.5 - Prob. 22ECh. 1.5 - Prob. 23ECh. 1.5 - Prob. 24ECh. 1.5 - Prob. 25ECh. 1.5 - Prob. 26ECh. 1.5 - Prob. 27ECh. 1.5 - Prob. 28ECh. 1.5 - Prob. 29ECh. 1.5 - Prob. 30ECh. 1.5 - Prob. 31ECh. 1.5 - Prob. 32ECh. 1.5 - Prob. 33ECh. 1.5 - Prob. 34ECh. 1.5 - Prob. 35ECh. 1.5 - Prob. 36ECh. 1.5 - Prob. 37ECh. 1.5 - Prob. 38ECh. 1.5 - Prob. 39ECh. 1.5 - Prob. 40ECh. 1.5 - Prob. 41ECh. 1.5 - Prob. 42ECh. 1.5 - Prob. 43ECh. 1.5 - Prob. 44ECh. 1.5 - Prob. 45ECh. 1.5 - Prob. 46ECh. 1.5 - Prob. 47ECh. 1.5 - Prob. 48ECh. 1.5 - Prob. 49ECh. 1.5 - Prob. 50ECh. 1.5 - Prob. 51ECh. 1.5 - Prob. 52ECh. 1.5 - Prob. 53ECh. 1.5 - Prob. 54ECh. 1.5 - Prob. 55ECh. 1.5 - Prob. 56ECh. 1.5 - Prob. 57ECh. 1.5 - Prob. 58ECh. 1.5 - Prob. 59ECh. 1.5 - Prob. 60ECh. 1.5 - Prob. 61ECh. 1.5 - Prob. 62ECh. 1.5 - Prob. 63ECh. 1.5 - Prob. 64ECh. 1.5 - Prob. 65ECh. 1.5 - Prob. 66ECh. 1.5 - Prob. 67ECh. 1.5 - Prob. 68ECh. 1.5 - Prob. 69ECh. 1.6 - Prob. 1CCh. 1.6 - Prob. 2CCh. 1.6 - Prob. 3CCh. 1.6 - Prob. 4CCh. 1.6 - Prob. 5CCh. 1.6 - Prob. 6CCh. 1.6 - Prob. 7CCh. 1.6 - Prob. 8CCh. 1.6 - Prob. 9CCh. 1.6 - Prob. 10CCh. 1.6 - Prob. 11CCh. 1.6 - Prob. 12CCh. 1.6 - Prob. 1ECh. 1.6 - Prob. 2ECh. 1.6 - Prob. 3ECh. 1.6 - Prob. 4ECh. 1.6 - Prob. 5ECh. 1.6 - Prob. 6ECh. 1.6 - Prob. 7ECh. 1.6 - Prob. 8ECh. 1.6 - Prob. 9ECh. 1.6 - Prob. 10ECh. 1.6 - Prob. 11ECh. 1.6 - Prob. 12ECh. 1.6 - Prob. 13ECh. 1.6 - Prob. 14ECh. 1.6 - Prob. 15ECh. 1.6 - Prob. 16ECh. 1.6 - Prob. 17ECh. 1.6 - Prob. 18ECh. 1.6 - Prob. 19ECh. 1.6 - Prob. 20ECh. 1.6 - Prob. 21ECh. 1.6 - Prob. 22ECh. 1.6 - Prob. 23ECh. 1.6 - Prob. 24ECh. 1.6 - Prob. 25ECh. 1.6 - Prob. 26ECh. 1.6 - Prob. 27ECh. 1.6 - Prob. 28ECh. 1.6 - Prob. 29ECh. 1.6 - Prob. 30ECh. 1.6 - Prob. 31ECh. 1.6 - Prob. 32ECh. 1.6 - Prob. 33ECh. 1.6 - Prob. 34ECh. 1.6 - Prob. 35ECh. 1.6 - Prob. 36ECh. 1.6 - Prob. 37ECh. 1.6 - Prob. 38ECh. 1.6 - Prob. 39ECh. 1.6 - Prob. 40ECh. 1.6 - Prob. 41ECh. 1.6 - Prob. 42ECh. 1.6 - Prob. 43ECh. 1.6 - Prob. 44ECh. 1.6 - Prob. 45ECh. 1.6 - Prob. 46ECh. 1.6 - Prob. 47ECh. 1.6 - Prob. 48ECh. 1.6 - Prob. 49ECh. 1.6 - Prob. 50ECh. 1.6 - Prob. 51ECh. 1.6 - Prob. 52ECh. 1.6 - Prob. 53ECh. 1.6 - Prob. 54ECh. 1.6 - Prob. 55ECh. 1.6 - Prob. 56ECh. 1.6 - Prob. 57ECh. 1.6 - Prob. 58ECh. 1.6 - Prob. 59ECh. 1.6 - Prob. 60ECh. 1.6 - Prob. 61ECh. 1.6 - Prob. 62ECh. 1.6 - Prob. 63ECh. 1.6 - Prob. 64ECh. 1.6 - Prob. 65ECh. 1.6 - Prob. 66ECh. 1.7 - Prob. 1CCh. 1.7 - Prob. 2CCh. 1.7 - Prob. 3CCh. 1.7 - Prob. 4CCh. 1.7 - Prob. 5CCh. 1.7 - Prob. 6CCh. 1.7 - Prob. 7CCh. 1.7 - Prob. 8CCh. 1.7 - Prob. 1ECh. 1.7 - Prob. 2ECh. 1.7 - Prob. 3ECh. 1.7 - Prob. 4ECh. 1.7 - Prob. 5ECh. 1.7 - Prob. 6ECh. 1.7 - Prob. 7ECh. 1.7 - Prob. 8ECh. 1.7 - Prob. 9ECh. 1.7 - Prob. 10ECh. 1.7 - Prob. 11ECh. 1.7 - Prob. 12ECh. 1.7 - Prob. 13ECh. 1.7 - Prob. 14ECh. 1.7 - Prob. 15ECh. 1.7 - Prob. 16ECh. 1.7 - Prob. 17ECh. 1.7 - Prob. 18ECh. 1.7 - Prob. 19ECh. 1.7 - Prob. 20ECh. 1.7 - Prob. 21ECh. 1.7 - Prob. 22ECh. 1.7 - Prob. 23ECh. 1.7 - Prob. 24ECh. 1.7 - Prob. 25ECh. 1.7 - Prob. 26ECh. 1.7 - Prob. 27ECh. 1.7 - Prob. 28ECh. 1.7 - Prob. 29ECh. 1.7 - Prob. 30ECh. 1.7 - Prob. 31ECh. 1.7 - Prob. 32ECh. 1.7 - Prob. 33ECh. 1.7 - Prob. 34ECh. 1.7 - Prob. 35ECh. 1.7 - Prob. 36ECh. 1.7 - Prob. 37ECh. 1.7 - Prob. 38ECh. 1.7 - Prob. 39ECh. 1.7 - Prob. 40ECh. 1.7 - Prob. 41ECh. 1.7 - Prob. 42ECh. 1.7 - Prob. 43ECh. 1.7 - Prob. 44ECh. 1.7 - Prob. 45ECh. 1.7 - Prob. 46ECh. 1.7 - Prob. 47ECh. 1.7 - Prob. 48ECh. 1.7 - Prob. 49ECh. 1.7 - Prob. 50ECh. 1.7 - Prob. 51ECh. 1.7 - Prob. 52ECh. 1.8 - Prob. 1CCh. 1.8 - Prob. 2CCh. 1.8 - Prob. 3CCh. 1.8 - Prob. 4CCh. 1.8 - Prob. 5CCh. 1.8 - Prob. 6CCh. 1.8 - Prob. 7CCh. 1.8 - Prob. 1ECh. 1.8 - Prob. 2ECh. 1.8 - Prob. 3ECh. 1.8 - Prob. 4ECh. 1.8 - Prob. 5ECh. 1.8 - Prob. 6ECh. 1.8 - Prob. 7ECh. 1.8 - Prob. 8ECh. 1.8 - Prob. 9ECh. 1.8 - Prob. 10ECh. 1.8 - Prob. 11ECh. 1.8 - Prob. 12ECh. 1.8 - Prob. 13ECh. 1.8 - Prob. 14ECh. 1.8 - Prob. 15ECh. 1.8 - Prob. 16ECh. 1.8 - Prob. 17ECh. 1.8 - Prob. 18ECh. 1.8 - Prob. 19ECh. 1.8 - Prob. 20ECh. 1.8 - Prob. 21ECh. 1.8 - Prob. 22ECh. 1.8 - Prob. 23ECh. 1.8 - Prob. 24ECh. 1.8 - Prob. 25ECh. 1.8 - Prob. 26ECh. 1.8 - Prob. 27ECh. 1.8 - Prob. 28ECh. 1.8 - Prob. 29ECh. 1.8 - Prob. 30ECh. 1.8 - Prob. 31ECh. 1.8 - Prob. 32ECh. 1.8 - Prob. 33ECh. 1.8 - Prob. 34ECh. 1.8 - Prob. 35ECh. 1.8 - Prob. 36ECh. 1.8 - Prob. 37ECh. 1.8 - Prob. 38ECh. 1.8 - Prob. 39ECh. 1.8 - Prob. 40ECh. 1.8 - Prob. 41ECh. 1.8 - Prob. 42ECh. 1.8 - Prob. 43ECh. 1.8 - Prob. 44ECh. 1 - Prob. 1PSQCh. 1 - Prob. 2PSQCh. 1 - Prob. 3PSQCh. 1 - Prob. 4PSQCh. 1 - Prob. 5PSQCh. 1 - Prob. 6PSQCh. 1 - Prob. 7PSQCh. 1 - Prob. 8PSQCh. 1 - Prob. 9PSQCh. 1 - Prob. 10PSQCh. 1 - Prob. 1MCQCh. 1 - Prob. 2MCQCh. 1 - Prob. 3MCQCh. 1 - Prob. 4MCQCh. 1 - Prob. 5MCQCh. 1 - Prob. 6MCQCh. 1 - Prob. 7MCQCh. 1 - Prob. 8MCQCh. 1 - Prob. 9MCQCh. 1 - Prob. 10MCQCh. 1 - Prob. 11MCQCh. 1 - Prob. 12MCQCh. 1 - Prob. 13MCQCh. 1 - Prob. 14MCQCh. 1 - Prob. 15MCQCh. 1 - Prob. 16MCQCh. 1 - Prob. 17MCQCh. 1 - Prob. 18MCQCh. 1 - Prob. 19MCQCh. 1 - Prob. 20MCQCh. 1 - Prob. 21MCQCh. 1 - Prob. 22MCQCh. 1 - Prob. 23MCQCh. 1 - Prob. 1CRCh. 1 - Prob. 2CRCh. 1 - Prob. 3CRCh. 1 - Prob. 4CRCh. 1 - Prob. 5CRCh. 1 - Prob. 6CRCh. 1 - Prob. 7CRCh. 1 - Prob. 8CRCh. 1 - Prob. 9CRCh. 1 - Prob. 10CRCh. 1 - Prob. 11CRCh. 1 - Prob. 12CRCh. 1 - Prob. 13CRCh. 1 - Prob. 14CRCh. 1 - Prob. 15CRCh. 1 - Prob. 16CRCh. 1 - Prob. 17CRCh. 1 - Prob. 18CRCh. 1 - Prob. 19CRCh. 1 - Prob. 20CRCh. 1 - Prob. 21CRCh. 1 - Prob. 22CRCh. 1 - Prob. 23CRCh. 1 - Prob. 24CRCh. 1 - Prob. 25CRCh. 1 - Prob. 26CRCh. 1 - Prob. 27CRCh. 1 - Prob. 28CRCh. 1 - Prob. 29CRCh. 1 - Prob. 30CRCh. 1 - Prob. 31CRCh. 1 - Prob. 32CRCh. 1 - Prob. 33CRCh. 1 - Prob. 34CRCh. 1 - Prob. 35CRCh. 1 - Prob. 36CRCh. 1 - Prob. 37CRCh. 1 - Prob. 38CRCh. 1 - Prob. 39CRCh. 1 - Prob. 40CRCh. 1 - Prob. 41CRCh. 1 - Prob. 42CRCh. 1 - Prob. 43CRCh. 1 - Prob. 44CRCh. 1 - Prob. 45CRCh. 1 - Prob. 46CRCh. 1 - Prob. 47CRCh. 1 - Prob. 48CRCh. 1 - Prob. 49CRCh. 1 - Prob. 50CRCh. 1 - Prob. 51CRCh. 1 - Prob. 52CRCh. 1 - Prob. 53CRCh. 1 - Prob. 54CRCh. 1 - Prob. 55CRCh. 1 - Prob. 56CRCh. 1 - Prob. 57CRCh. 1 - Prob. 58CRCh. 1 - Prob. 59CRCh. 1 - Prob. 60CRCh. 1 - Prob. 61CRCh. 1 - Prob. 62CRCh. 1 - Prob. 63CRCh. 1 - Prob. 64CRCh. 1 - Prob. 1CTCh. 1 - Prob. 2CTCh. 1 - Prob. 3CTCh. 1 - Prob. 4CTCh. 1 - Prob. 5CTCh. 1 - Prob. 6CTCh. 1 - Prob. 7CTCh. 1 - Prob. 8CTCh. 1 - Prob. 9CTCh. 1 - Prob. 10CTCh. 1 - Prob. 11CTCh. 1 - Prob. 12CTCh. 1 - Prob. 13CTCh. 1 - Prob. 14CTCh. 1 - Prob. 15CTCh. 1 - Prob. 16CTCh. 1 - Prob. 17CTCh. 1 - Prob. 18CTCh. 1 - Prob. 19CTCh. 1 - Prob. 20CTCh. 1 - Prob. 21CTCh. 1 - Prob. 22CTCh. 1 - Prob. 23CTCh. 1 - Prob. 24CTCh. 1 - Prob. 25CTCh. 1 - Prob. 26CTCh. 1 - Prob. 27CTCh. 1 - Prob. 28CTCh. 1 - Prob. 29CTCh. 1 - Prob. 30CTCh. 1 - Prob. 31CTCh. 1 - Prob. 32CTCh. 1 - Prob. 33CTCh. 1 - Prob. 34CTCh. 1 - Prob. 35CTCh. 1 - Prob. 36CTCh. 1 - Prob. 37CTCh. 1 - Prob. 38CTCh. 1 - Prob. 39CTCh. 1 - Prob. 1CSTCh. 1 - Prob. 2CSTCh. 1 - Prob. 3CSTCh. 1 - Prob. 4CSTCh. 1 - Prob. 5CSTCh. 1 - Prob. 6CSTCh. 1 - Prob. 7CSTCh. 1 - Prob. 8CSTCh. 1 - Prob. 9CSTCh. 1 - Prob. 10CSTCh. 1 - Prob. 11CSTCh. 1 - Prob. 12CSTCh. 1 - Prob. 13CSTCh. 1 - Prob. 1PSPCh. 1 - Prob. 2PSPCh. 1 - Prob. 3PSPCh. 1 - Prob. 4PSPCh. 1 - Prob. 5PSPCh. 1 - Prob. 6PSPCh. 1 - Prob. 7PSP
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- 2. Write a system of linear equations in slope-intercept form has exactly one solution at the point (3, 4), such that both lines have negative slope (but neither one has slope of 1). Also write your system of equations with both equations written in standard form without any fractions. B 0 5 4 3 -2 1 -8-7-6-5-4-3-2 -1 12 3 -1 2 -3 -5 6 -7 -8arrow_forward4. Write a system of linear equations in slope-intercept form that has no solution, such that (3, 4), and (3,8) are solutions to the first equation, and (0, 4) is a solution to the second equation. Also write your system of equations with both equations written in standard form with out any fractions B 0 5 4 3 -2 + -8-7-6-5-4-3-2 -1 |- 1 2 3 -1 2 -3 4 -5 6 -7arrow_forwardShow how you can solve the system of equations by manipulating the algebra tiles while maintaining the balances. On this side of the page, use the addition (elimination) method. Keep track of what you did at each step by writing down the corresponding equivalent equations, as well as what you did to go from one equation to the next. 1. x + 2y = 5 x-2y=1 2. 2x+y=2 x-2y= 6arrow_forward
- e) x24 1) Which of these are equivalent to x³? For each expression that is equivalent to x², prove it by using the definition of exponents. For each that is not equivalent to x³, give an example using a specific value for x that shows that it represents a different number. a) (x5) d) f) 10-2 b) (x²) *|*arrow_forwardNow show how you can solve the system of equations by manipulating the algebra tiles while maintaining the balances, using the substitution method. Keep track of what you did at each step by writing down the corresponding equivalent equations, as well as what you did to go from one equation to the next. Δ 1. x + 2y = 5 x-2y=1 2. 2x + y = 2 x-2y= 6arrow_forward1. Write a system of two linear equations in slope-intercept form that has exactly one solution at the point (3, 4), such that both lines have positive slope (but neither one has slope of 1) Also write your system of equations with both equations written in standard form without any fractions. 8- 7 8 5 4 3 -2- + -8-7-6-5-4-3-2-1 1 2 3 -1 2 - 4 -5 -7 -8arrow_forward
- The original idea for creating this applet comes from Steve Phelps' Graph the Line applet. Directions: 1) Examine the equation shown on the right side of the screen. 2) Reposition the 2 big points so that the line is the graph of the displayed equation. 3) Click the "Check Answer" checkbox to check. If you're correct, the app will inform you. If you're not, you'll know this as well. If you're not correct, keep trying until you position the gray line correctly. 4) After correctly graphing the line, click the "Generate New Line" button.arrow_forwardProblem 1 & 2 answers 1. One diagonal has 11 squares, then total square in total for two diagonal line is 11 + 11 - 1 = 21 . 2. Each part has 5 squares.(except middle)Multiply by 4: 5 × 4 = 20.Add the middle square: 20 + 1 = 21.arrow_forward2. Now Figure out a different way you could determine how many squares there are in the figure, again without counting them all one-by-one. Briefly describe this other method:arrow_forward
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