Explanation Given information: The function is f ( x + 3 ) = f ( x ) − 1 f ( x ) + 1 and f ( 11 ) = 11 for all x. Calculation: The function f ( x + 3 ) = f ( x ) − 1 f ( x ) + 1 is f ( x + 3 ) = f ( x ) − 1 f ( x ) + 1 ⇒ f ( x − 3 ) − 1 f ( x + 3 ) + 1 And now, The function is express as f ( x + 3 ) = f ( x − 3 ) − 1 f ( x + 3 ) + 1 − 1 f ( x − 3 ) − 1 f ( x + 3 ) + 1 + 1 f ( x + 3 ) = − 1 f ( x − 3 ) But the function for f ( x − 3 ) is f ( x − 3 ) = f ( x − 6 ) − 1 f ( x − 6 ) + 1 , then f ( x − 3 ) = f (

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Question

Chapter 1.4, Problem 59PS

To determine

To find f(2018) for the given function.

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Chapter 1.4, Problem 58PS

Chapter 1.4, Problem 60PS

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Chapter 1 Solutions

Calculus

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To find f ( 2018 ) for the given function.

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Chapter 1 Solutions