Explanation Given: The passing point is ( − 1 , 6 ) and the line is perpendicular to the line that passes through origin and have slope 0.5. Concept used: The relation between the slopes of two perpendicular lines is; m 1 × m 2 = − 1 Calculation: The slope of the perpendicular line is 0.5. The slope of the other line is; m 1 × m 2 = − 1 m 2 = − 1 0.5 m 2 = − 2 Thus, the required slope of line passing through the point ( − 1 , 6 ) is − 2

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 1.3, Problem 14PS

To determine

The equation of line in standard form.

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Chapter 1.3, Problem 13PS

Chapter 1.3, Problem 15PS

Chapter 1 Solutions

Calculus

Ch. 1.1 - Prob. 1PS Ch. 1.1 - Prob. 2PS Ch. 1.1 - Prob. 3PS Ch. 1.1 - Prob. 4PS Ch. 1.1 - Prob. 5PS Ch. 1.1 - Prob. 6PS Ch. 1.1 - Prob. 7PS Ch. 1.1 - Prob. 8PS Ch. 1.1 - Prob. 9PS Ch. 1.1 - Prob. 10PS

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The equation of line in standard form.

Solution Summary: The author explains the equation of line in standard form, which is y=-2x+4.

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The equation of line in standard form.

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Chapter 1 Solutions