2 CIO2 (aq) + 2 OH- (aq) CIO3- (aq) + CI02- (aq) + H2O (1) > Experiment Number [CIO2] (M) | [OH-] (M) |Initial Rate (M/s) 1 0.060 0.030 0.0248 0.020 0.030 0.00276 3 0.020 0.090 0.00828
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The data in the table were obtained for the reaction shown in the image. What is the order of the reaction with respect to ClO2?
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- NH4+ {aq) + NO2(aq) -> N2(g) +2H2O{l} Data Initial [NH4+] Initial [NO2-] rate 1 0.0100 0.200 5.4 x10-7 2 0.0200 0.200 10.8x10-7 3 0.0400 0.200 21.5x10-7 4 0.200 0.0202 10.8x10-7 5 0.200 0.0404 21.6x10-7 6 0.200 0.0808 43.3x10-7 Find x,y,kFor an enzyme -catalyzed reaction, KM=10.0 mmol dm-3, vmax=0.250 mmol dm²³ s-'; [E]o= 2.3 x 10-6 mmol dm-3. Calculate the catalytic efficiency (=kb/KM) of the enzyme. 0.920 dm³ mol-l s-1 3.1 x 107 dm³ mol-1 s-1 1.1 x107 dm³ mol-l s-1 0.250 dm³ mol-l s-1Expt. 1 2 3 NH; (aq) + NO; (aq) >Nz (aq) + 2 H2O (l) [NO₂] Rate (at 298 K) 0.020 M/s 0.020 M 0.020 M 0.030 M/s 0.010 M 0.0050 M/s [NH+] 0.010 M 0.015 M 0.010 M Determine the complete rate law (rate law and rate constant) for the reaction. Show all work. What is the initial rate of this reaction if the concentrations in Expt. 2 above are tripled. Show work. What is the rate of H₂O formation in Expt. 1? A 4th trial is conducted at 273 K, using the concentrations from Expt. 1. If the rate was found to be 0.016 M/s, calculate the activation energy of this reaction.
- Time (sec) PH [RX] [H30+] Ln[RX] 0.000 7.000 0.00002344 0.0000001 -10.6610666 15.000 6.400 0.00001954 0.00000039 -10.8430469 30.000 5.410 0.00001955 0.00000389 -10.8425353 45.000 5.230 0.00001756 0.00000588 -10.94988696 60.000 5.070 0.00001493 0.00000851 -11.11213794 75.000 4.920 0.00001142 0.00001202 -11.3801444 90.000 4.840 0.00000899 0.00001445 -11.6193977 105.000 | 4.780 0.00000685 0.00001659 -11.8912619 120.000 4.750 0.00000566 0.00001778 -12.08208666 135.000 4.720 0.00000439 0.00001905 -12.33618133 150.000 4.700 0.00000349 0.00001995 -12.56569882 165.000 4.670 0.00000207 0.00002137 -13.08796195 180.000 4.670 0.00000207 0.00002137 -13.08796195 195.000 4.660 0.00000157 0.00002187 -13.3644349 210.000 4.650 0.00000061 0.00002283 -14.30980687 225.000 4.650 0.00000061 0.00002283 -14.30980687 240.000 4.640 0.00000061 0.0000229 -14.30980687 255.000 4.640 0.00000061 0.0000229 -14.30980687 270.000 4.640 0.00000061 0.0000229 -14.30980687 285.000 4.630 0.00002344 Undefined 300.000 4.630…Time (sec) pH [RX] [H30+] Ln[RX] 0.000 7.000 0.00002344 0.0000001 -10.6610666 15.000 6.400 0.00001954 0.00000039 -10.8430469 30.000 5.410 0.00001955 0.00000389 -10.8425353 45.000 5.230 0.00001756 0.00000588 -10.94988696 60.000 5.070 0.00001493 0.00000851 -11.11213794 75.000 4.920 0.00001142 0.00001202 -11.3801444 90.000 4.840 0.00000899 0.00001445 -11.6193977 105.000 | 4.780 0.00000685 0.00001659 -11.8912619 120.000 4.750 0.00000566 0.00001778 -12.08208666 135.000 4.720 0.00000439 0.00001905 -12.33618133 150.000 4.700 0.00000349 0.00001995 -12.56569882 165.000 4.670 0.00000207 0.00002137 -13.08796195 180.000 4.670 0.00000207 0.00002137 -13.08796195 195.000 4.660 0.00000157 0.00002187 -13.3644349 210.000 4.650 0.00000061 0.00002283 -14.30980687 225.000 4.650 0.00000061 0.00002283 -14.30980687 240.000 4.640 0.00000061 0.0000229 -14.30980687 255.000 4.640 0.00000061 0.0000229 -14.30980687 270.000 4.640 0.00000061 0.0000229 -14.30980687 285.000 4.630 0.00002344 Undefined 300.000 | 4.630…E PAP Chem G diagram sh x H PAP Chemi x G Reactions t x K PAP Chemi: x I PAP Chemi x b ar-2903012.agilixbuzz.com/student/135113422/activity/c412d902-b23e-4202-b813-76alf9f4c196 I Student Ap x Session Tir X Mp Rocking WX Mastery Assess It_8 200% + Reset PAP Chemistry-2903012-42100. Enrique Solis All changes saved 3. Reactions that occur in the gaseous state are affected by changing the volume of the container. Which choice best describes what will happen to the reaction if the volume of the container is decreased? The reaction will speed up. The reaction will shift left. The reaction will not change. SAVE & EXIT NEXT The reaction will shift right. 3 of 25 PREVIOUS
- Reaction Conc, Na,d O3| Cune. HCI 4Als. | AIme (3) Rabe I1.3085840 0.10M •30M 0.4563/64 |0.028 F0913 15 M 12267196 | 0,01870913 30M 1.5360817 0.300349 2 65.56796607 5. 11431671 O.10 M 3 0.050 M 4 0.025 M 0:30M 1.54866|1 1.007568 1,358380874 4. Use experimental data and the rate law to calculate a rate constant for each reaction 1, 2, 3, 4. How do the rate constants compare? Should they be the same or different? Discuss in your conclusions. Report the average value of your calculations. Be sure to include units in your rate constant. -1-4 -2:5 Rate= k [ Naz s03] [Hc1]p.edu.jo/moodle/mod/quiz/attempt.php?attempt=10165&cmid3D21667 Fortal v أنظمة التعم الإلكترونی Old Courses Time left 0:59:08 A student dissolve 1.0 g of a mixture containing benzoic acid, p-methylaniline and cholobenzene in 20.0 mL of 10% HCL solution. After separating two layers, he added 10% red NaOH to the aqueos layer until basic to litmus paper. The Precipitate formed is: 1.00 on O a. chlorobenzene O b. p-methylaniline and benzoic acid O c. p-methylaniline Od benzoic acid NEXT PAGE Jump to.. Announcements ©PUELC. All rights reserved. EN INS DE %24 & V 8 9. BA Y I G Hi J J-K FIAn experiment was performed in a similar manner as Experiment 4 (The Hydrolysis of t-Butyl Chloride). The following data was obtained: Total Time (s) Volume NaOH Titrant used (mL) 46 2.01 91 3.97 131 5.98 175 8.03 220 10.00 266 11.99 311 14.01 357 15.97 401 17.98 450 20.02 Final Volume NaOH to fully react sample: 85.01 mL Assume the proposed reaction mechanism in the experimental procedure is correct. Based on the above measurements, how many minutes would it take for the solution to reach 81.0% completion? Round your final answer to two decimal places.
- Assessment-Chem 18-Gen (X 80 $ 54 R UCI General Chemistry Peer Tu X 65.2% Use the molar bond enthalpy data in the table to estimate the value of AHin for the equation CCI, (g) + 2 F₂ (g) →→→ CF₂(g) + 2Cl₂(g) The bonding in the molecules is shown. ΔΗ; = 888 F4 ++++ % 5 FS F-F A 6 New Tab MacBook Air ܀ T Y F6 & 7 CICI CI-CI A4 F7 * 8 ∞ Resources Average molar bond enthalpics. (Hond) kJ. mol Bond 464 C=N 142 N-H 351 N-N 502 N=N 730 N=N 347 F-F 615 811 414 439 331 276 293 615 Bond O-H 0-0 C-0 0=0 C=0 C-C C=C C=C C-H C-F C-CI C-Br C-N C=N DII FB 69 DD F9 kJ Question Source: McQuarrie, Rock, And Gallogly 4e-General Chemistry Publisher: University Science Books 1 0 ) CI-CI Br-Br H-H H-F H-CI H-Br H-S S-S 0 A F10 I' Check Answer P kJ. mol-1 890 390 159 418 945 155 243 192 435 565 431 368 364 225 3 F11 0 + Show All 411) F12 X }the mean time, the rate, [S₂O3] in the reaction may label clear outliers the mean) as such and e calculation. on mixtures NH4)2SO4 (NH4)2S2O8| (mL) (mL) 1.50 0.50 1.50 0.50 1.00 1.00 1.00 1.00 following reagents are um iodide ium persulfate m thiosulfate um nitrate ium sulfate odide in the solution in the Answer: 0.050 M • Determination of the rate law follows the protocol in ref. (5). with one difference. A reactant order (rate law exponent) will be calculated twice using two different pairs of determinations (e.g. determinations 1 & 2 and determinations 3 & 4). Then the mean is taken of both values and reported as order. This is done for each reactant. This additional step allows us to include more data and reduce experimental error. Practice Problem 2: The rate of a reaction CO(g) +3H₂(g)→ CH4(g) + H₂O(g) was determined at 25 °C. From the following data, determine a) the mean reaction order with respect to CO b) the mean reaction order with respect to H₂ c) the overall rate order d)…analyte concentration(C)(mg/ml) injection volume (ul) elution time (time) peak DAD signal(mAU) caffeine 1 1 4.67 302.85 aspartame 5 1 7.53 15.83 benzoic acid 1 1 8.14 89.98 saccharin 1 1 1.91 84.86 mixture(add everything above with 1:1:1:1 ratio) 1 4.47 69.58 How to get the concentration of the mixture in this case?