Concept explainers
(a)
Interpretation: The Lewis structure of Otezla needs to be completed.
Concept Introduction:
Lewis structure shows the arrangement of total number of valence electrons in a molecule. The electrons involved in bonding are known as bonding electrons and these are represented as bonds or line between two atoms (bonded together). On the other hand, electrons which are not involved in the bonding are known as lone pair of electrons. They are represented as dots (in pair) on symbol of an atom.
(a)
Explanation of Solution
The given structure is as follows:
Here, C, N, O and S atoms are present. The number of valence electrons of C, N, O and S atom is 4, 5, 6 and 6 respectively.
In the given molecule, C atom will form 4 covalent bonds so all its electrons will be represented as bond pairs, O atom will form 2 lone pair and 2 bond pair of electrons, S atom will have all the valence electrons involved in bonding and N atom will have 1 lone pair of electrons and 3 bond pairs.
The distribution of valence electrons is represented as follows:
Here, all the oxygen atoms will have 2 lone pair of electrons, N atom will have 1 lone pair of electrons and there will be no valence electrons on S atom.
(b)
Interpretation:In the structure of Otezla, the atom which is exception to octet rule needs to be identified.
Concept Introduction:
In the Lewis structure of a molecule, total number of valence electrons are distributed such that all the atoms have complete octets. In complete octet, atoms have 8 valance electrons in their outermost shell (except H which has 2 electrons).
(b)
Explanation of Solution
The complete Lewis structure of Otezla is as follows:
Here, all the valence electrons of C atoms are involved in bonding, oxygen atom has 2 lone pair of electrons and 2 bond pairs, N atom has 1 lone pair of electrons and 3 bond pairs. Thus, C, O and N atoms have complete octet. The only atom with exception to the octet rule is S. The total number of valence electrons on S atom is 6 thus, it can share 2 electrons with other atoms to complete the octet like O atom but, here S is involved in 2 double bonds with 2 O atoms and 2 single bonds with 2 C atom. The total number of electrons involved will be 12 which is exception to octet rule.
(c)
Interpretation: The valence-shell electron-pair repulsion model needs to be used to predict all the bond angles in Otezla.
Concept Introduction:
The valence-shell electron pair repulsion model is used to determine the hybridization, geometry and bond angles of central atoms in given structure.
To determine the hybridization, total number of bond pairs and lone pair of electrons are determined for a central atom. Depending on the total number of electron pair, hybridization is decided. Each hybridization corresponds to a geometry and respective bond angle.
(c)
Explanation of Solution
The complete Lewis structure of Otezla is as follows:
T
Here, the C atom with 4 single bonds is
All the bond angles are represented in Lewis structure as follows:
(d)
Interpretation: Whether Otezla is polar or non-polar needs to be explained.
Concept Introduction: In a molecule, if there is difference in electronegativity between atoms then it is said to be polar in nature. In other way, if polar bonds are present in the molecule, then it is considered as a polar molecule.
(d)
Explanation of Solution
A molecule is said to be polar if there are polar bonds present in it. A bond is said to be polar if there is difference in electronegativity value of two bonded atoms.
The given structure is as follows:
There is no electronegativity difference between C and H atom. The electronegative atoms in the above molecule are N, O and S atom.
Thus, N-C, N-H, C-O and C-S are polar bonds and molecule will be polar in nature.
(e)
Interpretation: The two resonance structures of Otezla needs to be drawn.
Concept Introduction: The resonance structures are possible in a molecule if there are lone pair of electrons and alternate pi bonds are present.
(e)
Explanation of Solution
The complete Lewis structure of Otezla is as follows:
Two resonance structures are as follows:
(f)
Interpretation: The molecular formula of Otezla needs to be determined.
Concept Introduction: The molecular formula of a molecule can be determined from its structure. Total number of atoms of same atoms can be determined from the structure and formula can be determined.
(f)
Explanation of Solution
The complete Lewis structure of Otezla is as follows:
In the above structure, there are C, H, N, O and S atoms. By calculating the total number of atoms in the molecule, molecular formula can be calculated.
The molecular formula of the molecule will be
(g)
Interpretation: The intermolecular forces present between Otezla molecules needs to be determined.
Concept Introduction: The intermolecular forces are type of interactions between the molecules. Non-polar molecules only have London dispersion forces and polar molecules can have other interactions as well like hydrogen bonding, dipole-dipole interactions, Van der Waals forces etc.
(g)
Explanation of Solution
The complete Lewis structure of Otezla is as follows:
Due to the presence of non-polar bonds, London dispersion forces are present in the molecules. Also due to N-H bond, hydrogen bonding is possible between the molecules.
(h)
Interpretation: The stereocenter of Otezla needs to be identified as R or S.
Concept Introduction:
The Cahn-Ingold-Prelog system is a set of rules that allows us to unambiguously define the stereochemical configuration of any stereocenter, using the designations 'R ' (from the Latin rectus, meaning right-handed) or ' S ' (from the Latin sinister, meaning left-handed).
In the first step, priority is given to 4 different groups attached to the stereocenter. The direction of 4th priority group should be away from the observer. In the second step, direction from 1 to 3 priority group is determined. If the direction is clockwise, the configuration will be R and if it is anticlockwise, the configuration will be S.
(h)
Explanation of Solution
The complete Lewis structure is represented as follows:
The stereocenter is point where 4 different substituents are present on a carbon atom. Molecules with stereocenter are known as chiral molecules.
The chiral center is labelled as follows:
The numbering according to priority rules will be:
The direction from 1 to 3 priority group is anticlockwise thus, the configuration is S.
(i)
Interpretation: The enantiomer of Otezla needs to be drawn.
Concept Introduction:
The chirality in a group in a molecule results in the formation of two enantiomers. These enantiomers are non-superimposable mirror image of each other.
(i)
Explanation of Solution
The enantiomer of Otezla will be R configuration and it is represented as follows:
Want to see more full solutions like this?
Chapter 14 Solutions
Introduction to General, Organic and Biochemistry
- 3. The skeleton of chloromethane is __________________ The central carbon atom is bonded to each of the other atoms by a shared electron pair (represented by a straight line, ___) giving Now, each hydrogen has two electrons and the carbon atom has eight. However, chlorine must be provided with unshared electrons (represented by pairs of dots, ) to complete its octet, thusarrow_forwardGiven the bonds C N, C H, C Br, and S O, (a) which atom in each is the more electronegative? (b) which of these bonds is the most polar?arrow_forwardWrite the Lewis structure for nitrosyl fluoride, FNO. Using only a periodic table, identify (a) which is the longer bond. (b) which is the stronger bond. (c) which is the more polar bond.arrow_forward
- The two compounds nitrogen dioxide and dinitrogen tetraoxide are introduced in Section 3.13. (a) NO2 is an odd-electron compound. Draw the best Lewis diagrams possible for it, recognizing that one atom cannot achieve an octet configuration. Use formal charges to decide whether that should be the (central) nitrogen atom or one of the oxygen atoms. (b) Draw resonance forms for N2O4 that obey the octet rule. The two N atoms are bonded in this molecule.arrow_forwardWrite the Lewis structure for each molecule. These molecules do not follow the octet rule.(a) BCl3(b) NO2(c) BH3arrow_forwardfuricacid, H2SO4 (each H is bonded to an O). (a) WhatLewis structure(s) would you draw to satisfy the octet rule?(b) What Lewis structure(s) would you draw to minimizeformal charge?arrow_forward
- In developing the concept of electronegativity, Pauling used the term excess bond energy for the difference between the actual bond energy of X¬Y and the average bond energies of X¬X and Y¬Y (see text discussion for the case of HF). Based on the values as shown, which of the following substances contains bonds with no excess bond energy?(a) PH3 (b) CS2 (c) BrCl (d) BH3 (e) Se8arrow_forwardThere are many Lewis structures you could draw for sulfuricacid, H2SO4 (each H is bonded to an O). (a) WhatLewis structure(s) would you draw to satisfy the octet rule?(b) What Lewis structure(s) would you draw to minimizeformal charge?arrow_forwardDraw Lewis diagrams for the following ions. In the formula the symbol of the central atom is given first. (Hint:The valence octet may be expanded for the central atom.)(a) BrO4 - (b) PCl6 - (c) XeF6+arrow_forward
- The Lewis structure for sulfuric acid (each H is bonded to an O) can be drawn in many ways. (a) Draw the Lewis structure that would satisfy the octet rule. (b) Draw the Lewis structure that would minimize formal charges.arrow_forwardCyanogen (CN)2 is known as pseodohalogen because it has some properties like halogens. It is composed of two CN’s joined together.(i) Draw the Lewis structure for all the possible combination for (CN)2.(ii) Calculate the formal charge and determine which one of the structures that you have drawn is most stable.(iii) For the stable structure, determine the geometry around the two central atoms.(iv) For the stable structure, draw the dipole arrows for the bonds.(v) Base on the stable structure, determine the polarity of molecule and state your reason.arrow_forwardWrite resonance forms that describe the distribution of electrons in each of these molecules or ions. (a) selenium dioxide, OSeo (b) nitrate ion, NO3 (c) nitric acid, HNO3 (N is bonded to an OH group and two O atoms) (d) benzene, CGH5: H (e) the formate ion:arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning