The terminal speed of the protein of radius 3.0 × 10 − 9 m , when it falls through a tube of water with viscosity 1.0 × 10 − 3 N ⋅ s/m 2 and under a constant downward force of 3.0 × 10 − 22 N exerted by earth, assuming no buoyant forces are acting on it.

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Answer 1

Question

Chapter 14, Problem 41P

(a)

To determine

The terminal speed of the protein of radius 3.0×10−9 m, when it falls through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by earth, assuming no buoyant forces are acting on it.

(b)

To determine

The time, in hours, required for the protein of radius 3.0×10−9 m, when it falls 0.10 m through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by the earth, assuming no buoyant forces are acting on it.

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Answer 2

Question

Chapter 14, Problem 41P

(a)

To determine

The terminal speed of the protein of radius 3.0×10−9 m, when it falls through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by earth, assuming no buoyant forces are acting on it.

(b)

To determine

The time, in hours, required for the protein of radius 3.0×10−9 m, when it falls 0.10 m through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by the earth, assuming no buoyant forces are acting on it.

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Answer 3

Question

Chapter 14, Problem 41P

(a)

To determine

The terminal speed of the protein of radius 3.0×10−9 m, when it falls through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by earth, assuming no buoyant forces are acting on it.

(b)

To determine

The time, in hours, required for the protein of radius 3.0×10−9 m, when it falls 0.10 m through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by the earth, assuming no buoyant forces are acting on it.

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Answer 4

Question

Chapter 14, Problem 41P

(a)

To determine

The terminal speed of the protein of radius 3.0×10−9 m, when it falls through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by earth, assuming no buoyant forces are acting on it.

(b)

To determine

The time, in hours, required for the protein of radius 3.0×10−9 m, when it falls 0.10 m through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by the earth, assuming no buoyant forces are acting on it.

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Answer 5

Chapter 14, Problem 41P

(a)

To determine

The terminal speed of the protein of radius 3.0×10−9 m, when it falls through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by earth, assuming no buoyant forces are acting on it.

(b)

To determine

The time, in hours, required for the protein of radius 3.0×10−9 m, when it falls 0.10 m through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by the earth, assuming no buoyant forces are acting on it.

Answer 6

Chapter 14, Problem 41P

(a)

To determine

The terminal speed of the protein of radius 3.0×10−9 m, when it falls through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by earth, assuming no buoyant forces are acting on it.

Answer 7

Chapter 14, Problem 41P

(a)

To determine

The terminal speed of the protein of radius 3.0×10−9 m, when it falls through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by earth, assuming no buoyant forces are acting on it.

Answer 8

(b)

To determine

The time, in hours, required for the protein of radius 3.0×10−9 m, when it falls 0.10 m through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by the earth, assuming no buoyant forces are acting on it.

Answer 9

(b)

To determine

The time, in hours, required for the protein of radius 3.0×10−9 m, when it falls 0.10 m through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by the earth, assuming no buoyant forces are acting on it.

Answer 10

Expert Solution & Answer

Answer 11

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Answer 12

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Answer 13

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The terminal speed of the protein of radius 3.0 × 10 − 9 m , when it falls through a tube of water with viscosity 1.0 × 10 − 3 N ⋅ s/m 2 and under a constant downward force of 3.0 × 10 − 22 N exerted by earth, assuming no buoyant forces are acting on it.

Concept explainers

The terminal speed of the protein of radius 3.0×10−9 m, when it falls through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by earth, assuming no buoyant forces are acting on it.

The time, in hours, required for the protein of radius 3.0×10−9 m, when it falls 0.10 m through a tube of water with viscosity 1.0×10−3 N⋅s/m2 and under a constant downward force of 3.0×10−22 N exerted by the earth, assuming no buoyant forces are acting on it.

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