
Bundle: Chemistry in Focus, Loose-leaf Version, 7th + OWLv2, 1 term (6 months) Printed Access Card
7th Edition
ISBN: 9781337812269
Author: Nivaldo J. Tro
Publisher: Cengage Learning
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Textbook Question
Chapter 14, Problem 3SC
Closely examine Figure 14.1 and explain why no reaction occurs in part d.
Because copper ions have a greater affinity for electrons than zinc ions.
Because zinc ions have a greater affinity for electrons than copper ions.
Because the temperature is too warm for a reaction to occur.
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10.
Stereochemistry. Assign R/S stereochemistry for the chiral center indicated on the
following compound. In order to recieve full credit, you MUST SHOW YOUR WORK!
H₂N
CI
OH
CI
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11. () Stereochemistry. Draw all possible stereoisomers of the following compound. Assign
R/S configurations for all stereoisomers and indicate the relationship between each as
enantiomer, diastereomer, or meso.
NH2
H
HNH,
-18
b)
8.
Indicate whether the following carbocation rearrangements are likely to occur
Please explain your rational using 10 words or less
not likely to occur
• The double bond is still in the
Same position
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Likely
to oc
occur
WHY?
-3
H3C
Brave
Chair Conformers. Draw the chair conformer of the following substituted
cyclohexane. Peform a RING FLIP and indicate the most stable
conformation and briefly explain why using 20 words or less.
CI
2
-cobs ??
MUST INDICATE H -2
-2
Br
EQ
Cl
OR
AT
Br
H&
most stable
WHY?
- 4
CH
12
Conformational Analysis. Draw all 6 conformers (one above each letter) of the
compound below looking down the indicated bond. Write the letter of the
conformer with the HIGHEST and LOWEST in energies on the lines provided.
NOTE: Conformer A MUST be the specific conformer of the structure as drawn below
-4 NOT
HOH
OH
3
Conformer A:
Br
OH
A
Samo
Br H
04
Br
H
H3
CH₂
H
anti
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Br CH
clipsed
H
Brott
H
IV
H
MISSING 2
-2
B
C
D
E
F
X
6
Conformer with HIGHEST ENERGY:
13. (1
structure
LOWEST ENERGY:
Nomenclature. a) Give the systematic (IUPAC) name structure. b) Draw the
corresponding to this name. HINT: Do not forget to indicate stereochemistry
when applicable.
a)
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Parent name (noname)
4 Bromo
Sub = 2-methylethyl-4 Bromo nonane
b) (3R,4S)-3-chloro-4-ethyl-2,7-dimethyloctane
# -2
-2
Chapter 14 Solutions
Bundle: Chemistry in Focus, Loose-leaf Version, 7th + OWLv2, 1 term (6 months) Printed Access Card
Ch. 14 - For the following redox reaction, identify the...Ch. 14 - Prob. 14.2YTCh. 14 - Prob. 1SCCh. 14 - The respiration reaction is shown below. Identify...Ch. 14 - Closely examine Figure 14.1 and explain why no...Ch. 14 - Prob. 1ECh. 14 - Explain the basic principle involved common...Ch. 14 - Prob. 3ECh. 14 - Prob. 4ECh. 14 - Prob. 5E
Ch. 14 - Can an oxidation reaction occur without a...Ch. 14 - Prob. 7ECh. 14 - Why is bromine reduced in the following reaction...Ch. 14 - What is an oxidizing agent? A reducing agent?Ch. 14 - Prob. 10ECh. 14 - Write equations for respiration and...Ch. 14 - Prob. 12ECh. 14 - Prob. 13ECh. 14 - Prob. 14ECh. 14 - Prob. 15ECh. 14 - Give a thermodynamic argument for why it is more...Ch. 14 - Prob. 17ECh. 14 - Use chemical equations to explain how the molten...Ch. 14 - Prob. 19ECh. 14 - Prob. 20ECh. 14 - Prob. 21ECh. 14 - Prob. 22ECh. 14 - Prob. 23ECh. 14 - Prob. 24ECh. 14 - Draw Lewis structures for each chemical reaction,...Ch. 14 - Draw Lewis structures for each chemical reaction,...Ch. 14 - Prob. 27ECh. 14 - For each reaction, indicate which elements are...Ch. 14 - For each reaction, indicate which elements are...Ch. 14 - For each reaction, indicate which elements are...Ch. 14 - For each reaction, identify the oxidizing agent...Ch. 14 - Prob. 32ECh. 14 - Prob. 33ECh. 14 - Prob. 34ECh. 14 - Which would you expect to be a better oxidizing...Ch. 14 - Prob. 36ECh. 14 - Prob. 37ECh. 14 - Sum each of the following oxidation and reduction...Ch. 14 - Prob. 39ECh. 14 - Prob. 40ECh. 14 - Which of the following factors might affect the...Ch. 14 - Prob. 42ECh. 14 - Prob. 43ECh. 14 - Fossil fuel, nuclear, and hydroelectric power...Ch. 14 - The following diagram shows an electrochemical...Ch. 14 - The following diagram shows a molecular view of...
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