A yellow submarine traveling horizontally at 11.0 m/s uses sonar with a frequency of 5.27 × 10 3 Hz. A red submarine is in front of the yellow submarine and moving 3.00 m/s relative to the water in the same direction. A crewman in the red submarine observes sound waves (“pings”) from the yellow submarine. Take the speed of sound in seawater as 1 533 m/s. (a) Write Equation 14.12. (b) Which submarine is the source of the sound? (c) Which submarine carries the observer? (d) Does the motion of the observer’s submarine increase or decrease the time between the pressure maxima of the incoming sound waves? How does that affect the observed period? The observed frequency? (e) Should the sign of v 0 be positive or negative? (f) Does the motion of the source submarine increase or decrease the time observed between the pressure maxima? How does this motion affect the observed period? The observed frequency? (g) What sign should be chosen for v s ? (h) Substitute the appropriate numbers and obtain the frequency observed by the crewman on the red submarine.

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 14, Problem 36P

A yellow submarine traveling horizontally at 11.0 m/s uses sonar with a frequency of 5.27 × 10³ Hz. A red submarine is in front of the yellow submarine and moving 3.00 m/s relative to the water in the same direction. A crewman in the red submarine observes sound waves (“pings”) from the yellow submarine. Take the speed of sound in seawater as 1 533 m/s. (a) Write Equation 14.12. (b) Which submarine is the source of the sound? (c) Which submarine carries the observer? (d) Does the motion of the observer’s submarine increase or decrease the time between the pressure maxima of the incoming sound waves? How does that affect the observed period? The observed frequency? (e) Should the sign of v₀ be positive or negative? (f) Does the motion of the source submarine increase or decrease the time observed between the pressure maxima? How does this motion affect the observed period? The observed frequency? (g) What sign should be chosen for v_s? (h) Substitute the appropriate numbers and obtain the frequency observed by the crewman on the red submarine.

(a)

Expert Solution

To determine

The equation 14.12.

Answer to Problem 36P

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Explanation of Solution

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Conclusion:

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

(b)

Expert Solution

To determine

The submarine which is the source of sound.

Answer to Problem 36P

The source of sound is yellow submarine.

Explanation of Solution

The yellow submarine emits the sound.

Thus, the source of sound is the yellow submarine.

Conclusion:

The source of sound is yellow submarine.

(c)

Expert Solution

To determine

The submarine which is carrying the observer.

Answer to Problem 36P

The red submarine is carrying the observer.

Explanation of Solution

The observer is standing in the red submarine and observing the sound wave coming from the yellow submarine.

Thus, the red submarine is carrying the observer.

Conclusion:

The red submarine is carrying the observer.

(d)

Expert Solution

To determine

Whether the observers submarine increase or decrease the time between the pressure maxima of the incoming sound waves.

Answer to Problem 36P

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

Explanation of Solution

Since, the submarine carrying the observer is moving; the observer is also moving. The observer is moving away from the observer. So, this will increase the total time observed between the arrivals of successive pressure maxima. This effect will decrease the observed frequency and an increase in the observed period.

Thus, the observers submarine increase the time between the pressure maxima of the incoming sound waves.

Conclusion:

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

(e)

Expert Solution

To determine

The sign of the velocity of the observer relative to the medium,

$v0$ .

Answer to Problem 36P

The sign of the velocity of the observer relative to the medium (

$v0$ ) is negative.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is decreasing; the sign of the variable $v0$ should be negative in the above equation.

Thus, the sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

Conclusion:

The sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

(f)

Expert Solution

To determine

Whether the motion of the source submarine increase or decrease the time between the pressure maxima and how does this motion affect the observed period and the frequency.

Answer to Problem 36P

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Explanation of Solution

Given Info:

Since, the source submarine is moving towards the observer; the time between the arrivals of successive pressure maxima will be decreasing. Thus, the observed period will be increasing and the observed frequency will also be increasing.

Thus, the time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Conclusion:

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

(g)

Expert Solution

To determine

The sign of the source’s velocity relative to the propagating medium

( $vs$ ).

Answer to Problem 36P

The sign of the source’s velocity relative to the propagating medium (

$vs$ ) should be positive.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is increasing; the denominator of the above equation should be decreasing. Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Conclusion:

The sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

(h)

Expert Solution

To determine

The frequency observed by the crewman on the red submarine.

Answer to Problem 36P

The frequency observed by the crewman on the red submarine is

$5.30×103 Hz$ .

Explanation of Solution

Given Info:

The speed of the yellow submarine is $11.0 m/s$ .

The frequency of the sonar is $5.27×103 Hz$ .

The speed of the red submarine is $3.0 m/s$ relative to the water in the same direction.

The speed of the sound in sea water is $1533 m/s$ .

Formula to calculate the frequency of the crewman is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Substitute $5.27×103 Hz$ for $fs$ , $1533 m/s$ for v, $−3.0 m/s$ for $v0$ and $11.0 m/s$ for $vs$ to find the frequency of the crew man,

$f0=(5.27×103 Hz)(1533 m/s+(−3.0 m/s)1533 m/s−11.0 m/s)=5.30×103 Hz$

Thus, the frequency observed by the crewman on the red submarine is $5.30×103 Hz$

Conclusion:

The frequency observed by the crewman on the red submarine is $5.30×103 Hz$ .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Example Two charges, one with +10 μC of charge, and another with - 7.0 μC of charge are placed in line with each other and held at a fixed distance of 0.45 m. Where can you put a 3rd charge of +5 μC, so that the net force on the 3rd charge is zero?

* Coulomb's Law Example Three charges are positioned as seen below. Charge 1 is +2.0 μC and charge 2 is +8.0μC, and charge 3 is - 6.0MC. What is the magnitude and the direction of the force on charge 2 due to charges 1 and 3? 93 kq92 F == 2 r13 = 0.090m 91 r12 = 0.12m 92 Coulomb's Constant: k = 8.99x10+9 Nm²/C² ✓

Make sure to draw a Free Body Diagram as well

Answer 2

Textbook Question

Chapter 14, Problem 36P

A yellow submarine traveling horizontally at 11.0 m/s uses sonar with a frequency of 5.27 × 10³ Hz. A red submarine is in front of the yellow submarine and moving 3.00 m/s relative to the water in the same direction. A crewman in the red submarine observes sound waves (“pings”) from the yellow submarine. Take the speed of sound in seawater as 1 533 m/s. (a) Write Equation 14.12. (b) Which submarine is the source of the sound? (c) Which submarine carries the observer? (d) Does the motion of the observer’s submarine increase or decrease the time between the pressure maxima of the incoming sound waves? How does that affect the observed period? The observed frequency? (e) Should the sign of v₀ be positive or negative? (f) Does the motion of the source submarine increase or decrease the time observed between the pressure maxima? How does this motion affect the observed period? The observed frequency? (g) What sign should be chosen for v_s? (h) Substitute the appropriate numbers and obtain the frequency observed by the crewman on the red submarine.

(a)

Expert Solution

To determine

The equation 14.12.

Answer to Problem 36P

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Explanation of Solution

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Conclusion:

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

(b)

Expert Solution

To determine

The submarine which is the source of sound.

Answer to Problem 36P

The source of sound is yellow submarine.

Explanation of Solution

The yellow submarine emits the sound.

Thus, the source of sound is the yellow submarine.

Conclusion:

The source of sound is yellow submarine.

(c)

Expert Solution

To determine

The submarine which is carrying the observer.

Answer to Problem 36P

The red submarine is carrying the observer.

Explanation of Solution

The observer is standing in the red submarine and observing the sound wave coming from the yellow submarine.

Thus, the red submarine is carrying the observer.

Conclusion:

The red submarine is carrying the observer.

(d)

Expert Solution

To determine

Whether the observers submarine increase or decrease the time between the pressure maxima of the incoming sound waves.

Answer to Problem 36P

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

Explanation of Solution

Since, the submarine carrying the observer is moving; the observer is also moving. The observer is moving away from the observer. So, this will increase the total time observed between the arrivals of successive pressure maxima. This effect will decrease the observed frequency and an increase in the observed period.

Thus, the observers submarine increase the time between the pressure maxima of the incoming sound waves.

Conclusion:

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

(e)

Expert Solution

To determine

The sign of the velocity of the observer relative to the medium,

$v0$ .

Answer to Problem 36P

The sign of the velocity of the observer relative to the medium (

$v0$ ) is negative.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is decreasing; the sign of the variable $v0$ should be negative in the above equation.

Thus, the sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

Conclusion:

The sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

(f)

Expert Solution

To determine

Whether the motion of the source submarine increase or decrease the time between the pressure maxima and how does this motion affect the observed period and the frequency.

Answer to Problem 36P

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Explanation of Solution

Given Info:

Since, the source submarine is moving towards the observer; the time between the arrivals of successive pressure maxima will be decreasing. Thus, the observed period will be increasing and the observed frequency will also be increasing.

Thus, the time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Conclusion:

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

(g)

Expert Solution

To determine

The sign of the source’s velocity relative to the propagating medium

( $vs$ ).

Answer to Problem 36P

The sign of the source’s velocity relative to the propagating medium (

$vs$ ) should be positive.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is increasing; the denominator of the above equation should be decreasing. Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Conclusion:

The sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

(h)

Expert Solution

To determine

The frequency observed by the crewman on the red submarine.

Answer to Problem 36P

The frequency observed by the crewman on the red submarine is

$5.30×103 Hz$ .

Explanation of Solution

Given Info:

The speed of the yellow submarine is $11.0 m/s$ .

The frequency of the sonar is $5.27×103 Hz$ .

The speed of the red submarine is $3.0 m/s$ relative to the water in the same direction.

The speed of the sound in sea water is $1533 m/s$ .

Formula to calculate the frequency of the crewman is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Substitute $5.27×103 Hz$ for $fs$ , $1533 m/s$ for v, $−3.0 m/s$ for $v0$ and $11.0 m/s$ for $vs$ to find the frequency of the crew man,

$f0=(5.27×103 Hz)(1533 m/s+(−3.0 m/s)1533 m/s−11.0 m/s)=5.30×103 Hz$

Thus, the frequency observed by the crewman on the red submarine is $5.30×103 Hz$

Conclusion:

The frequency observed by the crewman on the red submarine is $5.30×103 Hz$ .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 14, Problem 36P

A yellow submarine traveling horizontally at 11.0 m/s uses sonar with a frequency of 5.27 × 10³ Hz. A red submarine is in front of the yellow submarine and moving 3.00 m/s relative to the water in the same direction. A crewman in the red submarine observes sound waves (“pings”) from the yellow submarine. Take the speed of sound in seawater as 1 533 m/s. (a) Write Equation 14.12. (b) Which submarine is the source of the sound? (c) Which submarine carries the observer? (d) Does the motion of the observer’s submarine increase or decrease the time between the pressure maxima of the incoming sound waves? How does that affect the observed period? The observed frequency? (e) Should the sign of v₀ be positive or negative? (f) Does the motion of the source submarine increase or decrease the time observed between the pressure maxima? How does this motion affect the observed period? The observed frequency? (g) What sign should be chosen for v_s? (h) Substitute the appropriate numbers and obtain the frequency observed by the crewman on the red submarine.

(a)

Expert Solution

To determine

The equation 14.12.

Answer to Problem 36P

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Explanation of Solution

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Conclusion:

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

(b)

Expert Solution

To determine

The submarine which is the source of sound.

Answer to Problem 36P

The source of sound is yellow submarine.

Explanation of Solution

The yellow submarine emits the sound.

Thus, the source of sound is the yellow submarine.

Conclusion:

The source of sound is yellow submarine.

(c)

Expert Solution

To determine

The submarine which is carrying the observer.

Answer to Problem 36P

The red submarine is carrying the observer.

Explanation of Solution

The observer is standing in the red submarine and observing the sound wave coming from the yellow submarine.

Thus, the red submarine is carrying the observer.

Conclusion:

The red submarine is carrying the observer.

(d)

Expert Solution

To determine

Whether the observers submarine increase or decrease the time between the pressure maxima of the incoming sound waves.

Answer to Problem 36P

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

Explanation of Solution

Since, the submarine carrying the observer is moving; the observer is also moving. The observer is moving away from the observer. So, this will increase the total time observed between the arrivals of successive pressure maxima. This effect will decrease the observed frequency and an increase in the observed period.

Thus, the observers submarine increase the time between the pressure maxima of the incoming sound waves.

Conclusion:

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

(e)

Expert Solution

To determine

The sign of the velocity of the observer relative to the medium,

$v0$ .

Answer to Problem 36P

The sign of the velocity of the observer relative to the medium (

$v0$ ) is negative.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is decreasing; the sign of the variable $v0$ should be negative in the above equation.

Thus, the sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

Conclusion:

The sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

(f)

Expert Solution

To determine

Whether the motion of the source submarine increase or decrease the time between the pressure maxima and how does this motion affect the observed period and the frequency.

Answer to Problem 36P

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Explanation of Solution

Given Info:

Since, the source submarine is moving towards the observer; the time between the arrivals of successive pressure maxima will be decreasing. Thus, the observed period will be increasing and the observed frequency will also be increasing.

Thus, the time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Conclusion:

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

(g)

Expert Solution

To determine

The sign of the source’s velocity relative to the propagating medium

( $vs$ ).

Answer to Problem 36P

The sign of the source’s velocity relative to the propagating medium (

$vs$ ) should be positive.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is increasing; the denominator of the above equation should be decreasing. Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Conclusion:

The sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

(h)

Expert Solution

To determine

The frequency observed by the crewman on the red submarine.

Answer to Problem 36P

The frequency observed by the crewman on the red submarine is

$5.30×103 Hz$ .

Explanation of Solution

Given Info:

The speed of the yellow submarine is $11.0 m/s$ .

The frequency of the sonar is $5.27×103 Hz$ .

The speed of the red submarine is $3.0 m/s$ relative to the water in the same direction.

The speed of the sound in sea water is $1533 m/s$ .

Formula to calculate the frequency of the crewman is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Substitute $5.27×103 Hz$ for $fs$ , $1533 m/s$ for v, $−3.0 m/s$ for $v0$ and $11.0 m/s$ for $vs$ to find the frequency of the crew man,

$f0=(5.27×103 Hz)(1533 m/s+(−3.0 m/s)1533 m/s−11.0 m/s)=5.30×103 Hz$

Thus, the frequency observed by the crewman on the red submarine is $5.30×103 Hz$

Conclusion:

The frequency observed by the crewman on the red submarine is $5.30×103 Hz$ .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 14, Problem 36P

A yellow submarine traveling horizontally at 11.0 m/s uses sonar with a frequency of 5.27 × 10³ Hz. A red submarine is in front of the yellow submarine and moving 3.00 m/s relative to the water in the same direction. A crewman in the red submarine observes sound waves (“pings”) from the yellow submarine. Take the speed of sound in seawater as 1 533 m/s. (a) Write Equation 14.12. (b) Which submarine is the source of the sound? (c) Which submarine carries the observer? (d) Does the motion of the observer’s submarine increase or decrease the time between the pressure maxima of the incoming sound waves? How does that affect the observed period? The observed frequency? (e) Should the sign of v₀ be positive or negative? (f) Does the motion of the source submarine increase or decrease the time observed between the pressure maxima? How does this motion affect the observed period? The observed frequency? (g) What sign should be chosen for v_s? (h) Substitute the appropriate numbers and obtain the frequency observed by the crewman on the red submarine.

(a)

Expert Solution

To determine

The equation 14.12.

Answer to Problem 36P

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Explanation of Solution

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Conclusion:

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

(b)

Expert Solution

To determine

The submarine which is the source of sound.

Answer to Problem 36P

The source of sound is yellow submarine.

Explanation of Solution

The yellow submarine emits the sound.

Thus, the source of sound is the yellow submarine.

Conclusion:

The source of sound is yellow submarine.

(c)

Expert Solution

To determine

The submarine which is carrying the observer.

Answer to Problem 36P

The red submarine is carrying the observer.

Explanation of Solution

The observer is standing in the red submarine and observing the sound wave coming from the yellow submarine.

Thus, the red submarine is carrying the observer.

Conclusion:

The red submarine is carrying the observer.

(d)

Expert Solution

To determine

Whether the observers submarine increase or decrease the time between the pressure maxima of the incoming sound waves.

Answer to Problem 36P

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

Explanation of Solution

Since, the submarine carrying the observer is moving; the observer is also moving. The observer is moving away from the observer. So, this will increase the total time observed between the arrivals of successive pressure maxima. This effect will decrease the observed frequency and an increase in the observed period.

Thus, the observers submarine increase the time between the pressure maxima of the incoming sound waves.

Conclusion:

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

(e)

Expert Solution

To determine

The sign of the velocity of the observer relative to the medium,

$v0$ .

Answer to Problem 36P

The sign of the velocity of the observer relative to the medium (

$v0$ ) is negative.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is decreasing; the sign of the variable $v0$ should be negative in the above equation.

Thus, the sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

Conclusion:

The sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

(f)

Expert Solution

To determine

Whether the motion of the source submarine increase or decrease the time between the pressure maxima and how does this motion affect the observed period and the frequency.

Answer to Problem 36P

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Explanation of Solution

Given Info:

Since, the source submarine is moving towards the observer; the time between the arrivals of successive pressure maxima will be decreasing. Thus, the observed period will be increasing and the observed frequency will also be increasing.

Thus, the time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Conclusion:

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

(g)

Expert Solution

To determine

The sign of the source’s velocity relative to the propagating medium

( $vs$ ).

Answer to Problem 36P

The sign of the source’s velocity relative to the propagating medium (

$vs$ ) should be positive.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is increasing; the denominator of the above equation should be decreasing. Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Conclusion:

The sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

(h)

Expert Solution

To determine

The frequency observed by the crewman on the red submarine.

Answer to Problem 36P

The frequency observed by the crewman on the red submarine is

$5.30×103 Hz$ .

Explanation of Solution

Given Info:

The speed of the yellow submarine is $11.0 m/s$ .

The frequency of the sonar is $5.27×103 Hz$ .

The speed of the red submarine is $3.0 m/s$ relative to the water in the same direction.

The speed of the sound in sea water is $1533 m/s$ .

Formula to calculate the frequency of the crewman is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Substitute $5.27×103 Hz$ for $fs$ , $1533 m/s$ for v, $−3.0 m/s$ for $v0$ and $11.0 m/s$ for $vs$ to find the frequency of the crew man,

$f0=(5.27×103 Hz)(1533 m/s+(−3.0 m/s)1533 m/s−11.0 m/s)=5.30×103 Hz$

Thus, the frequency observed by the crewman on the red submarine is $5.30×103 Hz$

Conclusion:

The frequency observed by the crewman on the red submarine is $5.30×103 Hz$ .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(a)

Expert Solution

To determine

The equation 14.12.

Answer to Problem 36P

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Explanation of Solution

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Conclusion:

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

(b)

Expert Solution

To determine

The submarine which is the source of sound.

Answer to Problem 36P

The source of sound is yellow submarine.

Explanation of Solution

The yellow submarine emits the sound.

Thus, the source of sound is the yellow submarine.

Conclusion:

The source of sound is yellow submarine.

(c)

Expert Solution

To determine

The submarine which is carrying the observer.

Answer to Problem 36P

The red submarine is carrying the observer.

Explanation of Solution

The observer is standing in the red submarine and observing the sound wave coming from the yellow submarine.

Thus, the red submarine is carrying the observer.

Conclusion:

The red submarine is carrying the observer.

(d)

Expert Solution

To determine

Whether the observers submarine increase or decrease the time between the pressure maxima of the incoming sound waves.

Answer to Problem 36P

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

Explanation of Solution

Since, the submarine carrying the observer is moving; the observer is also moving. The observer is moving away from the observer. So, this will increase the total time observed between the arrivals of successive pressure maxima. This effect will decrease the observed frequency and an increase in the observed period.

Thus, the observers submarine increase the time between the pressure maxima of the incoming sound waves.

Conclusion:

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

(e)

Expert Solution

To determine

The sign of the velocity of the observer relative to the medium,

$v0$ .

Answer to Problem 36P

The sign of the velocity of the observer relative to the medium (

$v0$ ) is negative.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is decreasing; the sign of the variable $v0$ should be negative in the above equation.

Thus, the sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

Conclusion:

The sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

(f)

Expert Solution

To determine

Whether the motion of the source submarine increase or decrease the time between the pressure maxima and how does this motion affect the observed period and the frequency.

Answer to Problem 36P

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Explanation of Solution

Given Info:

Since, the source submarine is moving towards the observer; the time between the arrivals of successive pressure maxima will be decreasing. Thus, the observed period will be increasing and the observed frequency will also be increasing.

Thus, the time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Conclusion:

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

(g)

Expert Solution

To determine

The sign of the source’s velocity relative to the propagating medium

( $vs$ ).

Answer to Problem 36P

The sign of the source’s velocity relative to the propagating medium (

$vs$ ) should be positive.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is increasing; the denominator of the above equation should be decreasing. Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Conclusion:

The sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

(h)

Expert Solution

To determine

The frequency observed by the crewman on the red submarine.

Answer to Problem 36P

The frequency observed by the crewman on the red submarine is

$5.30×103 Hz$ .

Explanation of Solution

Given Info:

The speed of the yellow submarine is $11.0 m/s$ .

The frequency of the sonar is $5.27×103 Hz$ .

The speed of the red submarine is $3.0 m/s$ relative to the water in the same direction.

The speed of the sound in sea water is $1533 m/s$ .

Formula to calculate the frequency of the crewman is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Substitute $5.27×103 Hz$ for $fs$ , $1533 m/s$ for v, $−3.0 m/s$ for $v0$ and $11.0 m/s$ for $vs$ to find the frequency of the crew man,

$f0=(5.27×103 Hz)(1533 m/s+(−3.0 m/s)1533 m/s−11.0 m/s)=5.30×103 Hz$

Thus, the frequency observed by the crewman on the red submarine is $5.30×103 Hz$

Conclusion:

The frequency observed by the crewman on the red submarine is $5.30×103 Hz$ .

Answer 8

(a)

Expert Solution

To determine

The equation 14.12.

Answer to Problem 36P

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Explanation of Solution

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Conclusion:

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

The equation 14.12.

Answer 13

Answer to Problem 36P

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Answer 14

Explanation of Solution

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Conclusion:

The equation 14.12 in the text book is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Answer 15

(b)

Expert Solution

To determine

The submarine which is the source of sound.

Answer to Problem 36P

The source of sound is yellow submarine.

Explanation of Solution

The yellow submarine emits the sound.

Thus, the source of sound is the yellow submarine.

Conclusion:

The source of sound is yellow submarine.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

The submarine which is the source of sound.

Answer 20

Answer to Problem 36P

The source of sound is yellow submarine.

Answer 21

Explanation of Solution

The yellow submarine emits the sound.

Thus, the source of sound is the yellow submarine.

Conclusion:

The source of sound is yellow submarine.

Answer 22

(c)

Expert Solution

To determine

The submarine which is carrying the observer.

Answer to Problem 36P

The red submarine is carrying the observer.

Explanation of Solution

The observer is standing in the red submarine and observing the sound wave coming from the yellow submarine.

Thus, the red submarine is carrying the observer.

Conclusion:

The red submarine is carrying the observer.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

To determine

The submarine which is carrying the observer.

Answer 27

Answer to Problem 36P

The red submarine is carrying the observer.

Answer 28

Explanation of Solution

The observer is standing in the red submarine and observing the sound wave coming from the yellow submarine.

Thus, the red submarine is carrying the observer.

Conclusion:

The red submarine is carrying the observer.

Answer 29

(d)

Expert Solution

To determine

Whether the observers submarine increase or decrease the time between the pressure maxima of the incoming sound waves.

Answer to Problem 36P

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

Explanation of Solution

Since, the submarine carrying the observer is moving; the observer is also moving. The observer is moving away from the observer. So, this will increase the total time observed between the arrivals of successive pressure maxima. This effect will decrease the observed frequency and an increase in the observed period.

Thus, the observers submarine increase the time between the pressure maxima of the incoming sound waves.

Conclusion:

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

To determine

Whether the observers submarine increase or decrease the time between the pressure maxima of the incoming sound waves.

Answer 34

Answer to Problem 36P

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

Answer 35

Explanation of Solution

Since, the submarine carrying the observer is moving; the observer is also moving. The observer is moving away from the observer. So, this will increase the total time observed between the arrivals of successive pressure maxima. This effect will decrease the observed frequency and an increase in the observed period.

Thus, the observers submarine increase the time between the pressure maxima of the incoming sound waves.

Conclusion:

The observers submarine increase the time between the pressure maxima of the incoming sound waves.

Answer 36

(e)

Expert Solution

To determine

The sign of the velocity of the observer relative to the medium,

$v0$ .

Answer to Problem 36P

The sign of the velocity of the observer relative to the medium (

$v0$ ) is negative.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is decreasing; the sign of the variable $v0$ should be negative in the above equation.

Thus, the sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

Conclusion:

The sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

Answer 37

(e)

Expert Solution

Answer 38

(e)

Expert Solution

Answer 39

Expert Solution

Answer 40

To determine

The sign of the velocity of the observer relative to the medium,

$v0$ .

Answer 41

Answer to Problem 36P

The sign of the velocity of the observer relative to the medium (

$v0$ ) is negative.

Answer 42

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is decreasing; the sign of the variable $v0$ should be negative in the above equation.

Thus, the sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

Conclusion:

The sign of the velocity of the observer relative to the medium ( $v0$ ) is negative.

Answer 43

(f)

Expert Solution

To determine

Whether the motion of the source submarine increase or decrease the time between the pressure maxima and how does this motion affect the observed period and the frequency.

Answer to Problem 36P

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Explanation of Solution

Given Info:

Since, the source submarine is moving towards the observer; the time between the arrivals of successive pressure maxima will be decreasing. Thus, the observed period will be increasing and the observed frequency will also be increasing.

Thus, the time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Conclusion:

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Answer 44

(f)

Expert Solution

Answer 45

(f)

Expert Solution

Answer 46

Expert Solution

Answer 47

To determine

Whether the motion of the source submarine increase or decrease the time between the pressure maxima and how does this motion affect the observed period and the frequency.

Answer 48

Answer to Problem 36P

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Answer 49

Explanation of Solution

Given Info:

Since, the source submarine is moving towards the observer; the time between the arrivals of successive pressure maxima will be decreasing. Thus, the observed period will be increasing and the observed frequency will also be increasing.

Thus, the time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Conclusion:

The time between the arrivals of the successive pressure maxima will decrease. The observed period and the frequency will be increasing.

Answer 50

(g)

Expert Solution

To determine

The sign of the source’s velocity relative to the propagating medium

( $vs$ ).

Answer to Problem 36P

The sign of the source’s velocity relative to the propagating medium (

$vs$ ) should be positive.

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is increasing; the denominator of the above equation should be decreasing. Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Conclusion:

The sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Answer 51

(g)

Expert Solution

Answer 52

(g)

Expert Solution

Answer 53

Expert Solution

Answer 54

To determine

The sign of the source’s velocity relative to the propagating medium

( $vs$ ).

Answer 55

Answer to Problem 36P

The sign of the source’s velocity relative to the propagating medium (

$vs$ ) should be positive.

Answer 56

Explanation of Solution

Given Info:

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Since, the observed frequency is increasing; the denominator of the above equation should be decreasing. Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Thus, the sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Conclusion:

The sign of the source’s velocity relative to the propagating medium ( $vs$ ) should be positive.

Answer 57

(h)

Expert Solution

To determine

The frequency observed by the crewman on the red submarine.

Answer to Problem 36P

The frequency observed by the crewman on the red submarine is

$5.30×103 Hz$ .

Explanation of Solution

Given Info:

The speed of the yellow submarine is $11.0 m/s$ .

The frequency of the sonar is $5.27×103 Hz$ .

The speed of the red submarine is $3.0 m/s$ relative to the water in the same direction.

The speed of the sound in sea water is $1533 m/s$ .

Formula to calculate the frequency of the crewman is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Substitute $5.27×103 Hz$ for $fs$ , $1533 m/s$ for v, $−3.0 m/s$ for $v0$ and $11.0 m/s$ for $vs$ to find the frequency of the crew man,

$f0=(5.27×103 Hz)(1533 m/s+(−3.0 m/s)1533 m/s−11.0 m/s)=5.30×103 Hz$

Thus, the frequency observed by the crewman on the red submarine is $5.30×103 Hz$

Conclusion:

The frequency observed by the crewman on the red submarine is $5.30×103 Hz$ .

Answer 58

(h)

Expert Solution

Answer 59

(h)

Expert Solution

Answer 60

Expert Solution

Answer 61

To determine

The frequency observed by the crewman on the red submarine.

Answer 62

Answer to Problem 36P

The frequency observed by the crewman on the red submarine is

$5.30×103 Hz$ .

Answer 63

Explanation of Solution

Given Info:

The speed of the yellow submarine is $11.0 m/s$ .

The frequency of the sonar is $5.27×103 Hz$ .

The speed of the red submarine is $3.0 m/s$ relative to the water in the same direction.

The speed of the sound in sea water is $1533 m/s$ .

Formula to calculate the frequency of the crewman is,

$f0=fs(v+v0v−vs)$

$fs$ is the frequency emitted by the source
$f0$ is the frequency detected by the observer
$v$ is the speed of the wave in the propagating medium
$v0$ is the velocity of the observer relative to the medium
$vs$ is the source’s velocity relative to the propagating medium

Substitute $5.27×103 Hz$ for $fs$ , $1533 m/s$ for v, $−3.0 m/s$ for $v0$ and $11.0 m/s$ for $vs$ to find the frequency of the crew man,

$f0=(5.27×103 Hz)(1533 m/s+(−3.0 m/s)1533 m/s−11.0 m/s)=5.30×103 Hz$

Thus, the frequency observed by the crewman on the red submarine is $5.30×103 Hz$

Conclusion:

The frequency observed by the crewman on the red submarine is $5.30×103 Hz$ .

Answer 64

Ch. 14.3 - Which of the following actions will increase the...Ch. 14.6 - Suppose youre on a hot air balloon ride, carrying...Ch. 14.6 - As an airplane flying with constant velocity moves...Ch. 14.8 - Which of the following frequencies are higher...Ch. 14.10 - Prob. 14.5QQ Ch. 14.10 - Prob. 14.6QQ Ch. 14.11 - You are tuning a guitar by comparing the sound of...Ch. 14 - (a) You are driving down the highway in your car...Ch. 14 - When dealing with sound intensities and decibel...Ch. 14 - Fill in the blanks with the correct values (to two...

Concept explainers

Videos

Answer to Problem 36P

Explanation of Solution

Answer to Problem 36P

Explanation of Solution

Answer to Problem 36P

Explanation of Solution

Answer to Problem 36P

Explanation of Solution

Answer to Problem 36P

Explanation of Solution

Answer to Problem 36P

Explanation of Solution

Answer to Problem 36P

Explanation of Solution

Answer to Problem 36P

Explanation of Solution

Want to see more full solutions like this?

Chapter 14 Solutions