Big Java Late Objects
2nd Edition
ISBN: 9781119330455
Author: Horstmann
Publisher: WILEY
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Expert Solution & Answer
Chapter 14, Problem 2RE
Explanation of Solution
Code walkthrough:
The below is the code walkthrough of the selection sort
Array length being 0 or 1:
- When the value of “i” is equal to “0” then “i<a.length-1” is not true.
- The “for” loop that is present in the sort method will never execute and the array will remain unchanged.
Array length being 2:
- The “for” loop that is present in the sort will execute once.
- When the value of “i=0” then “minimumPosition(a,0)” gets called.
- The “for” loop that is present gets executed from “=i” that is from 1 till less than 2, that is the loop will be executed once.
- The value of “minPos” is initially set to “0”.
- If the value of “a[1] is less than a[0]” then the value of “minPos” will be set to “1”.
- Finally when the method returns the values, two values will be swapped and that will make the array to be sorted...
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Students have asked these similar questions
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
how to read log logs
Discrete Mathematics for Computer Engineering
Chapter 14 Solutions
Big Java Late Objects
Ch. 14.1 - Prob. 1SCCh. 14.1 - Prob. 2SCCh. 14.1 - Prob. 3SCCh. 14.1 - Prob. 4SCCh. 14.2 - Prob. 5SCCh. 14.2 - Prob. 6SCCh. 14.3 - Prob. 7SCCh. 14.3 - Prob. 8SCCh. 14.3 - Prob. 9SCCh. 14.3 - Prob. 10SC
Ch. 14.3 - Prob. 11SCCh. 14.3 - Prob. 12SCCh. 14.4 - Prob. 13SCCh. 14.4 - Prob. 14SCCh. 14.4 - Prob. 15SCCh. 14.5 - Prob. 16SCCh. 14.5 - Prob. 17SCCh. 14.6 - Prob. 18SCCh. 14.6 - Prob. 19SCCh. 14.6 - Prob. 20SCCh. 14.7 - Prob. 21SCCh. 14.7 - Prob. 22SCCh. 14.7 - Prob. 23SCCh. 14.7 - Prob. 24SCCh. 14.7 - Prob. 25SCCh. 14.7 - Prob. 26SCCh. 14.8 - Prob. 27SCCh. 14.8 - Prob. 28SCCh. 14.8 - Prob. 29SCCh. 14.8 - Prob. 30SCCh. 14 - Prob. 1RECh. 14 - Prob. 2RECh. 14 - Prob. 3RECh. 14 - Prob. 4RECh. 14 - Prob. 5RECh. 14 - Prob. 6RECh. 14 - Prob. 7RECh. 14 - Prob. 8RECh. 14 - Prob. 9RECh. 14 - Prob. 10RECh. 14 - Prob. 11RECh. 14 - Prob. 12RECh. 14 - Prob. 13RECh. 14 - Prob. 14RECh. 14 - Prob. 15RECh. 14 - Prob. 16RECh. 14 - Prob. 17RECh. 14 - Prob. 18RECh. 14 - Prob. 19RECh. 14 - Prob. 20RECh. 14 - Prob. 21RECh. 14 - Prob. 22RECh. 14 - Prob. 23RECh. 14 - Prob. 24RECh. 14 - Prob. 25RECh. 14 - Prob. 26RECh. 14 - Prob. 27RECh. 14 - Prob. 28RECh. 14 - Prob. 29RECh. 14 - Prob. 30RECh. 14 - Prob. 1PECh. 14 - Prob. 2PECh. 14 - Prob. 3PECh. 14 - Prob. 4PECh. 14 - Prob. 5PECh. 14 - Prob. 6PECh. 14 - Prob. 7PECh. 14 - Prob. 8PECh. 14 - Prob. 9PECh. 14 - Prob. 10PECh. 14 - Prob. 11PECh. 14 - Prob. 12PECh. 14 - Prob. 13PECh. 14 - Prob. 14PECh. 14 - Prob. 15PECh. 14 - Prob. 16PECh. 14 - Prob. 17PECh. 14 - Prob. 18PECh. 14 - Prob. 1PPCh. 14 - Prob. 2PPCh. 14 - Prob. 3PPCh. 14 - Prob. 4PPCh. 14 - Prob. 5PPCh. 14 - Prob. 6PPCh. 14 - Prob. 7PPCh. 14 - Prob. 8PPCh. 14 - Prob. 9PP
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