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(a)
Interpretation:
The kekule structure should be drawn for the given molecule
Concept introduction:
- Lone-pair electrons are valence electrons that are not used in bonding.
- A proton is positively charged hydrogen ion. A hybrid ion is a negatively charged hydrogen ion.
- When the atom is neutral, C form 2 bonds, N forms 3 bonds O forms 2 bonds and H or a halogen forms 1 bond.
- A carbocation has a positively charge carbon, a carbon has a negatively charge carbon and a radical has an unpaired electron.
kekule structure:
Without lone pairs of electros in Lewis structures is known as kekule structure.
(b)
Interpretation:
The kekule structure should be drawn for the given molecule
Concept introduction:
- Lone-pair electrons are valence electrons that are not used in bonding.
- A proton is positively charged hydrogen ion. A hybrid ion is a negatively charged hydrogen ion.
- Formal charge = the number of valence electron – the number of electrons the atom has to itself (the entire lone pair electron and one – half of the bonding electrons).
- Lewis structure indicates which atom is bonded together and show lone pairs and formal charge.
- When the atom is neutral, C form 2 bonds, N forms 3 bonds O forms 2 bonds and H or a halogen forms 1 bond.
- A carbocation has a positively charge carbon, a carbon has a negatively charge carbon and a radical has an unpaired electron.
kekule structure:
Without lone pairs of electros in Lewis structures is known as kekule structure.
(c)
Interpretation:
The kekule structure should be drawn for the given molecule
Concept introduction:
- Lone-pair electrons are valence electrons that are not used in bonding.
- A proton is positively charged hydrogen ion. A hybrid ion is a negatively charged hydrogen ion.
- Formal charge = the number of valence electron – the number of electrons the atom has to itself (the entire lone pair electron and one – half of the bonding electrons).
- Lewis structure indicates which atom is bonded together and show lone pairs and formal charge.
- When the atom is neutral, C form 2 bonds, N forms 3 bonds O forms 2 bonds and H or a halogen forms 1 bond.
- A carbocation has a positively charge carbon, a carbon has a negatively charge carbon and a radical has an unpaired electron.
kekule structure:
Without lone pairs of electros in Lewis structures is known as kekule structure.
(d)
Interpretation:
The kekule structure should be drawn for the given molecule
Concept introduction:
- Lone-pair electrons are valence electrons that are not used in bonding.
- A proton is positively charged hydrogen ion. A hybrid ion is a negatively charged hydrogen ion.
- Formal charge = the number of valence electron – the number of electrons the atom has to itself (the entire lone pair electron and one – half of the bonding electrons).
- Lewis structure indicates which atom is bonded together and show lone pairs and formal charge.
- When the atom is neutral, C form 2 bonds, N forms 3 bonds O forms 2 bonds and H or a halogen forms 1 bond.
- A carbocation has a positively charge carbon, a carbon has a negatively charge carbon and a radical has an unpaired electron.
kekule structure:
Without lone pairs of electros in Lewis structures is known as kekule structure.
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Chapter 1 Solutions
ORGANIC CHEMISTRY-W/S.G+SOLN.MANUAL
- Deducing the reactants of a Diels-Alder reaction n the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. >arrow_forwardPredict the major products of the following organic reaction: + Some important notes: A ? • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure.arrow_forwardif the answer is no reaction than state that and please hand draw!arrow_forward
- reciprocal lattices rotates along with the real space lattices of the crystal. true or false?arrow_forwardDeducing the reactants of a Diels-Alder reaction vn the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ O If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Product can't be made in one step. Explanation Checkarrow_forwardPredict the major products of the following organic reaction: Δ ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. Larrow_forward
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
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