Chapter 14, Problem 1SAQ

Which compound is most soluble in octane (C₈H₁₈)?

• CBr₄
• H₂O
• NH₃
• CH₃OH

Interpretation Introduction

Interpretation: To find which compound is most soluble in octane ${\text{(C}}_{\text{8}}{\text{H}}_{\text{18}}\text{)}$ .

Concept introduction:

A chemical property which refers to the capability for a given substance such as solute to dissolve in the solvent is known as solubility. At equilibrium it is also measured in terms of the maximum amount of solute that is dissolved in specified amount of solvent.

Correct answer: Option (a) ${\text{CBr}}_4$ is the correct answer.

Explanation of Solution

Reason for the correct answer: The given compound octane is found to be a non-polar solvent. Generally, the non-polar solute or solvent will immediately get soluble in octane as the thumb rule of solubility is like dissolves like. Among the given compounds ${\text{CBr}}_4$ is the only compound which is non-polar so, ${\text{CBr}}_4$ is most soluble in octane.