
Concept explainers
In this case, defining the function is a technique that can be reusable in JavaScript code.
Hence, the correct answer is option “A”.

Explanation of Solution
Defining a function:
It is a technique which is used to perform the particular task when the function is called by user using its name. The function can be used multiple times by calling the function in JavaScript. So, the defined function can be reused in JavaScript code.
Explanation for incorrect options:
Create a script block:
In this option, creating a script is a block of code with “<script>” element. This block is used to write the set of code and the block is cannot be reused by the user.
Hence, the option “B” is wrong.
Define an “if” statement:
In this option, “if” statement is a conditional statement which is used to check the value of variable with its appropriate condition. If the condition returns true, then it displays the “true” block, otherwise it executes “false” block. So, it cannot be reused by user.
Hence, the option “C” is wrong.
Use an onclick event handler:
“Onclick” is an event handler which is processed when the user clicks on the event. It is a predefined technique and used for “click” event.
Hence, the option “D” is wrong.
Want to see more full solutions like this?
Chapter 14 Solutions
Web Development and Design Foundations with HTML5 (8th Edition)
- My code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardI would like to know the main features about the following three concepts: 1. Default forwarded 2. WINS Server 3. IP Security (IPSec).arrow_forwardmap the following ER diagram into a relational database schema diagram. you should take into account all the constraints in the ER diagram. Underline the primary key of each relation, and show each foreign key as a directed arrow from the referencing attributes (s) to the referenced relation. NOTE: Need relational database schema diagramarrow_forward
- What is business intelligence? Share the Business intelligence (BI) tools you have used and explain what types of decisions you made.arrow_forwardI need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardTask 3. i) Compare your results from Tasks 1 and 2. j) Repeat Tasks 1 and 2 for 500 and 5,000 elements. k) Summarize run-time results in the following table: Time/size n String StringBuilder 50 500 5,000arrow_forward
- Can you please solve this without AIarrow_forward1. Create a Vehicle.java file. Implement the public Vehicle and Car classes in Vehicle.java, including all the variables and methods in the UMLS. Vehicle - make: String model: String -year: int + Vehicle(String make, String, model, int, year) + getMake(): String + setMake(String make): void + getModel(): String + setModel(String model): void + getYear(): int + set Year(int year): void +toString(): String Car - numDoors: int + numberOfCar: int + Car(String make, String, model, int, year, int numDoors) + getNumDoors(): int + setNumDoors (int num Doors): void + toString(): String 2. Create a CarTest.java file. Implement a public CarTest class with a main method. In the main method, create one Car object and print the object using System.out.println(). Then, print the numberOfCar. Your printing result must follow the example output: make Toyota, model=Camry, year=2022 numDoors=4 1 Hint: You need to modify the toString methods in the Car class and Vehicle class!arrow_forwardCHATGPT GAVE ME WRONG ANSWER PLEASE HELParrow_forward
- HELP CHAT GPT GAVE ME WRONG ANSWER Consider the following implementation of a container that will be used in a concurrent environment. The container is supposed to be used like an indexed array, but provide thread-safe access to elements. struct concurrent_container { // Assume it’s called for any new instance soon before it’s ever used void concurrent_container() { init_mutex(&lock); } ~concurrent_container() { destroy_mutex(&lock); } // Returns element by its index. int get(int index) { lock.acquire(); if (index < 0 || index >= size) { return -1; } int result = data[index]; lock.release(); return result; } // Sets element by its index. void set(int index, int value) { lock.acquire(); if (index < 0 || index >= size) { resize(size); } data[index] = value; lock.release(); } // Extend maximum capacity of the…arrow_forwardWrite a C program using embedded assembler in which you use your own function to multiply by two without using the product. Tip: Just remember that multiplying by two in binary means shifting the number one place to the left. You can use the sample program from the previous exercise as a basis, which increments a variable. Just replace the INC instruction with SHL.arrow_forwardusing r languagearrow_forward
- New Perspectives on HTML5, CSS3, and JavaScriptComputer ScienceISBN:9781305503922Author:Patrick M. CareyPublisher:Cengage LearningEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENT
- Microsoft Visual C#Computer ScienceISBN:9781337102100Author:Joyce, Farrell.Publisher:Cengage Learning,Programming Logic & Design ComprehensiveComputer ScienceISBN:9781337669405Author:FARRELLPublisher:CengageCOMPREHENSIVE MICROSOFT OFFICE 365 EXCEComputer ScienceISBN:9780357392676Author:FREUND, StevenPublisher:CENGAGE L


