Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN: 9781337399425
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Chapter 14, Problem 17QAP

The molar heats of fusion and vaporization for water are 6 .0 2 kJ / mol and 4 0. 6 kJ / mol respectively, and The specific heat capacity of liquid water is 4 . 18 J / ° C . What quantity of heat energy is required to melt 25 .0  g of ice at 0   ° C ? What quantity of heat is required for vaporize 37 . 5 g of liquid water at 1 00   ° C ? What quantity of heat is required to warm 55 . 2 g of liquid water from 0   ° C to 1 00   ° C ?

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Interpretation Introduction

Interpretation:

The heat required to melt 25g of ice at 00C, heat required to vaporize 37.5g liquid water at 1000C and heat required to warm 55.2g water from 00C to 1000C must be calculated.

Concept Introduction:

For melting and vaporization latent heat is used but for increasing temperature specific heat is used.

Answer to Problem 17QAP

The heat required to melt 25g of ice at 00C is 8.36kJ.

The heat required to vaporize 37.5g liquid water at 1000C is 84.583kJ.

The heat required to warm 55.2g water from 00C to 1000C is 23.073kJ.

Explanation of Solution

Given information:

Molar heat of fusion and vaporization of water is 6.02kJ/mol and 40.6kJ/mol respectively.

The specific heat capacity of water is 4.18J/g0C.

Heat of fusion of ice is 6.02kJ/mol

So fusion of 18g ice needs 6.02kJ heat energy.

Fusion of 1g ice needs 6.02kJ18 heat energy.

Fusion of 25g ice needs (6.02×25)kJ18 heat energy =150.5kJ18 heat energy = 8.36kJ

Heat of vaporization of water is 40.6kJ/mol

So vaporization of 18g water needs 40.6kJ heat energy.

Vaporization of 1g water needs 40.6kJ18 heat energy.

Vaporization of 37.5g water needs (40.6kJ×37.5)18 heat energy =1522.5kJ18

=84.583kJ

Heat required to warm 55.2g water from 00C to 1000C is H=m×s×t where m, s, t are mass of water, specific heat capacity of water and temperature rise of water respectively.

Now putting all the values we get H=55.2g×4.18J/g0C×(1000)0C=23.073kJ

Conclusion

The heat required to melt 25g of ice at 00C is 8.36kJ.

The heat required to vaporize 37.5g liquid water at 1000C is 84.583kJ.

The heat required to warm 55.2g water from 00C to 1000C is 23.073kJ.

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Chapter 14 Solutions

Introductory Chemistry: A Foundation

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