PHY F/SCIENTIST MOD MASTERING 24 MO
17th Edition
ISBN: 9780137319497
Author: Knight
Publisher: PEARSON
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Chapter 14, Problem 16EAP
A 6.00-cm-diameter sphere with a mass of 89.3 g is neutrally buoyant in a liquid. Identify the liquid.
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Chapter 14 Solutions
PHY F/SCIENTIST MOD MASTERING 24 MO
Ch. 14 - Prob. 1CQCh. 14 - Prob. 2CQCh. 14 - Prob. 3CQCh. 14 - Prob. 4CQCh. 14 - Prob. 5CQCh. 14 - Rank in order, from largest to smallest, the...Ch. 14 - a, b, and C in FIGURE Q14.7 have the same volume....Ch. 14 - a, b, and c in FIGURE Q14.7 have the same density....Ch. 14 - Prob. 9CQCh. 14 - Gas flows through the pipe of FIGURE Q14.10. You...
Ch. 14 - Prob. 11CQCh. 14 - Prob. 12CQCh. 14 - Prob. 13CQCh. 14 - What is the volume in mL of 55 g of a liquid with...Ch. 14 - Prob. 2EAPCh. 14 - Prob. 3EAPCh. 14 - A 6.0m12.0m swimming pool slopes linearly from a...Ch. 14 - A 1.0-m-diameter vat of liquid is 2.0 m deep. The...Ch. 14 - Prob. 6EAPCh. 14 - A 3.0-cm-diameter tube is held upright and filled...Ch. 14 - a. What volume of water has the same mass as 8.om3...Ch. 14 - A 50-cm-thick layer of oil floats on a...Ch. 14 - A research submarine has a 20-cm-diameter window...Ch. 14 - A 20-cm-diameter circular cover is placed over a...Ch. 14 - Prob. 12EAPCh. 14 - Prob. 13EAPCh. 14 - Prob. 14EAPCh. 14 - 15. How far must a 2.0-cm-diameter piston be...Ch. 14 - A 6.00-cm-diameter sphere with a mass of 89.3 g is...Ch. 14 - Prob. 17EAPCh. 14 - Prob. 18EAPCh. 14 - Prob. 19EAPCh. 14 - Prob. 20EAPCh. 14 - What is the tension of the string in FIGURE...Ch. 14 - 22. A 10-cm-diameter, 20-cm-tall steel cylinder (=...Ch. 14 - You need to determine the density of a ceramic...Ch. 14 - Prob. 24EAPCh. 14 - Prob. 25EAPCh. 14 - Prob. 26EAPCh. 14 - A long horizontal tube has a square cross section...Ch. 14 - Prob. 28EAPCh. 14 - Prob. 29EAPCh. 14 - Prob. 30EAPCh. 14 - A 2.0 mL syringe has an inner diameter of 6.0 mm,...Ch. 14 - Prob. 32EAPCh. 14 - Prob. 33EAPCh. 14 - Prob. 34EAPCh. 14 - Prob. 35EAPCh. 14 - Prob. 36EAPCh. 14 - Prob. 37EAPCh. 14 - Prob. 38EAPCh. 14 - Prob. 39EAPCh. 14 - Prob. 40EAPCh. 14 - 41. A friend asks you how much pressure is in your...Ch. 14 - Prob. 42EAPCh. 14 - Prob. 43EAPCh. 14 - 44. A U-shaped tube, open to the air on both ends,...Ch. 14 - Prob. 45EAPCh. 14 - Prob. 46EAPCh. 14 - An aquarium of length L, width (front to back) W,...Ch. 14 - Prob. 48EAPCh. 14 - Prob. 49EAPCh. 14 - 50. A cylinder with cross-section area A floats...Ch. 14 - Prob. 51EAPCh. 14 - Prob. 52EAPCh. 14 - Prob. 53EAPCh. 14 - Prob. 54EAPCh. 14 - A plastic "boat" with a square cross section...Ch. 14 - Prob. 56EAPCh. 14 - Prob. 57EAPCh. 14 - Prob. 58EAPCh. 14 - Prob. 59EAPCh. 14 - Prob. 60EAPCh. 14 - Prob. 61EAPCh. 14 - Prob. 62EAPCh. 14 - Prob. 63EAPCh. 14 - Prob. 64EAPCh. 14 - A hurricane wind blows across a 6.0m15.0m flat...Ch. 14 - Prob. 66EAPCh. 14 - Prob. 67EAPCh. 14 - A water tank of height h has a small hole at...Ch. 14 - Prob. 69EAPCh. 14 - Prob. 70EAPCh. 14 - 71. The bottom of a steel "boat" is a piece . The...Ch. 14 - Prob. 72EAPCh. 14 - Prob. 73EAPCh. 14 - Prob. 74EAPCh. 14 - Prob. 75EAP
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- No chatgpt pls will upvote instantarrow_forwardKirchoff's Laws. A circuit contains 3 known resistors, 2 known batteries, and 3 unknown currents as shown. Assume the current flows through the circuit as shown (this is our initial guess, the actual currents may be reverse). Use the sign convention that a potential drop is negative and a potential gain is positive. E₂ = 8V R₁₁ = 50 R₂ = 80 b с w 11 www 12 13 E₁ = 6V R3 = 20 a) Apply Kirchoff's Loop Rule around loop abefa in the clockwise direction starting at point a. (2 pt). b) Apply Kirchoff's Loop Rule around loop bcdeb in the clockwise direction starting at point b. (2 pt). c) Apply Kirchoff's Junction Rule at junction b (1 pt). d) Solve the above 3 equations for the unknown currents I1, 12, and 13 and specify the direction of the current around each loop. (5 pts) I1 = A 12 = A 13 = A Direction of current around loop abef Direction of current around loop bcde (CW or CCW) (CW or CCW)arrow_forwardNo chatgpt pls will upvotearrow_forward
- 4.) The diagram shows the electric field lines of a positively charged conducting sphere of radius R and charge Q. A B Points A and B are located on the same field line. A proton is placed at A and released from rest. The magnitude of the work done by the electric field in moving the proton from A to B is 1.7×10-16 J. Point A is at a distance of 5.0×10-2m from the centre of the sphere. Point B is at a distance of 1.0×10-1 m from the centre of the sphere. (a) Explain why the electric potential decreases from A to B. [2] (b) Draw, on the axes, the variation of electric potential V with distance r from the centre of the sphere. R [2] (c(i)) Calculate the electric potential difference between points A and B. [1] (c(ii)) Determine the charge Q of the sphere. [2] (d) The concept of potential is also used in the context of gravitational fields. Suggest why scientists developed a common terminology to describe different types of fields. [1]arrow_forward3.) The graph shows how current I varies with potential difference V across a component X. 904 80- 70- 60- 50- I/MA 40- 30- 20- 10- 0+ 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 VIV Component X and a cell of negligible internal resistance are placed in a circuit. A variable resistor R is connected in series with component X. The ammeter reads 20mA. 4.0V 4.0V Component X and the cell are now placed in a potential divider circuit. (a) Outline why component X is considered non-ohmic. [1] (b(i)) Determine the resistance of the variable resistor. [3] (b(ii)) Calculate the power dissipated in the circuit. [1] (c(i)) State the range of current that the ammeter can measure as the slider S of the potential divider is moved from Q to P. [1] (c(ii)) Describe, by reference to your answer for (c)(i), the advantage of the potential divider arrangement over the arrangement in (b).arrow_forward1.) Two long parallel current-carrying wires P and Q are separated by 0.10 m. The current in wire P is 5.0 A. The magnetic force on a length of 0.50 m of wire P due to the current in wire Q is 2.0 × 10-s N. (a) State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P. [2] (b) Calculate the current in wire Q. [2] (c) Another current-carrying wire R is placed parallel to wires P and Q and halfway between them as shown. wire P wire R wire Q 0.05 m 0.05 m The net magnetic force on wire Q is now zero. (c.i) State the direction of the current in R, relative to the current in P.[1] (c.ii) Deduce the current in R. [2]arrow_forward
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