Chapter 14, Problem 14A.7BE

Interpretation Introduction

Interpretation:

The polarizability of a compound at the wavelength of $643\text{nm}$ is to be calculated.

Concept introduction:

When the molecules are polar or extremely polarizable, then the substance has large relative permittivity.  The interaction between the relative permittivity and the molecule’s electrical characteristic is acquired by considering a medium's polarization.  It is expressed by the Debye equation, as shown below.

    $\frac{{\epsilon }_{\text{r}}-1}{{\epsilon }_{\text{r}}+2}=\frac{\rho P_{\text{m}}}{M}$

The polarizability, $\alpha$ is calculated by using the formula shown below.

    $\frac{{\epsilon }_{\text{r}}-1}{{\epsilon }_{\text{r}}+2}=\frac{\rho N_{\text{A}}\alpha }{3M{\epsilon }_{\text{ο}}}$