A solid iron sphere and a solid lead sphere of the same size are each suspended by strings and are submerged in a tank of water. (Note that the density of lead is greater than that of iron.) Which of the following statements are valid? (Choose all correct statements.) (a) The buoyant force on each is the same. (b) The buoyant force on the lead sphere is greater than the buoyant force on the iron sphere because lead has the greater density. (c) The tension in the siring supporting the lead sphere is greater than the tension in the string supporting the iron sphere. (d) The buoyant force on the iron sphere is greater than the buoyant force on the lead sphere because lead displaces more water. (e) None of those statements is true.
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Chapter 14 Solutions
Bundle: Physics for Scientists and Engineers, Technology Update, 9th Loose-leaf Version + WebAssign Printed Access Card, Multi-Term
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- A 1.50 mLmL syringe has an inner diameter of 5.00 mmmm, a needle inner diameter of 0.270 mmmm, and a plunger pad diameter (where you place your finger) of 1.2 cmcm. A nurse uses the syringe to inject medicine into a patient whose blood pressure is 140/100. Part A What is the minimum force the nurse needs to apply to the syringe? Express your answer with the appropriate units. View Available Hint(s)for Part A Hint 1for Part A. How to approach the question The force the nurse applies to the syringe can be determined from the fluid pressure and the area of the plunger. The minimum force corresponds to the patient's lowest blood pressure. Use the following equality 760mmofHg=1atm=1.013×10^5Pa760mmofHg=1atm=1.013×10^5Pa.arrow_forwardA 1.50 mLmL syringe has an inner diameter of 5.00 mmmm, a needle inner diameter of 0.270 mmmm, and a plunger pad diameter (where you place your finger) of 1.2 cmcm. A nurse uses the syringe to inject medicine into a patient whose blood pressure is 140/100. Part A What is the minimum force the nurse needs to apply to the syringe? Express your answer with the appropriate units. View Available Hint(s)for Part A Hint 1for Part A. How to approach the question The force the nurse applies to the syringe can be determined from the fluid pressure and the area of the plunger. The minimum force corresponds to the patient's lowest blood pressure. Use the following equality 760mmofHg=1atm=1.013×10^5Pa760mmofHg=1atm=1.013×10^5Pa.arrow_forwardIs a scientific theory supposed to just be someone's idea about somethingarrow_forward
- what is the agenda of physicsarrow_forwardWatch the video of Cooper’s play, while conducting and documenting your observation using a chosen observation tool. Case Study 1b - Cooper Carol has asked you to support the babies and toddler’s room educators this week. She has requested that you complete an observation on Cooper, who is a 10-month-old toddler. Carol wants to see how well you conduct an observation and is interested in how you manage to communicate in any observations made, using a strengths-based, non-judgemental, anti-biased approach, as this is a fundamental part of creating a supportive and respectful culture at Little Catalysts ELC. Video: Cooper's play (6:45 min) Resources Module 7 eLearns Template: Learning story observation, Section 1 Template: Running record observation, Section 1 Template: Anecdotal record observation, Section 1 Video: Cooper's play (6:45 min) Complete and upload an observation of Cooper to support educators in future curriculum planning. Choose one (1) of the observation…arrow_forward1. An ideal gas is taken through a four process cycle abcda. State a has a pressure of 498,840 Pa. Complete the tables and plot/label all states and processes on the PV graph. Complete the states and process diagrams on the last page. Also, provide proper units for each column/row heading in the tables. Pressure (Pa) 500,000 450,000 400,000 350,000 300,000 250,000 200,000 150,000 100,000 Process ab bc cd da States P( ) V( ) 50,000 0 0.000 T = 500 K T= 200 K 0.001 0.002 0.003 0.004 0.005 Volume (m^3) Nature of Process isothermal expansion to Vb = 0.005 m³ (T = 500 K) isometric isothermal compression to V₁ = 0.003 m³ (T = 200 K) adiabatic compression to VA = 0.001 m³ b C a T() U ( ) Processes a-b Q( ) +802.852 W() AU ( ) b-c c→d +101.928 da Cyclearrow_forward
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