Using Δ G ° rxn values from Appendix 2 , calculate the standard free-energy change of the following reaction at 25.0°C. C 4 H 10 ( g ) + O 2 ( g ) → CO 2 ( g ) + H 2 O( l ) (You must first balance the equation.) (a) + 615.9 kJ/mol (b) − 5495.8 kJ/mol (c) + 539.3 kJ/mol (d) − 615.9 kJ/mol (e) − 5511.5 kJ/mol
Using Δ G ° rxn values from Appendix 2 , calculate the standard free-energy change of the following reaction at 25.0°C. C 4 H 10 ( g ) + O 2 ( g ) → CO 2 ( g ) + H 2 O( l ) (You must first balance the equation.) (a) + 615.9 kJ/mol (b) − 5495.8 kJ/mol (c) + 539.3 kJ/mol (d) − 615.9 kJ/mol (e) − 5511.5 kJ/mol
Solution Summary: The author explains that the standard free energy change in the given reaction has to be calculated.
Vnk the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest bolling
point, choose 2 next to the substance with the next highest boiling point, and so on.
substance
C
D
chemical symbol,
chemical formula
or Lewis structure.
CH,-N-CH,
CH,
H
H 10: H
C-C-H
H H H
Cale
H 10:
H-C-C-N-CH,
Bri
CH,
boiling point
(C)
Сен
(C) B
(Choose
Please help me find the 1/Time, Log [I^-] Log [S2O8^2-], Log(time) on the data table. With calculation steps. And the average for runs 1a-1b. Please help me thanks in advance. Will up vote!
Q1: Answer the questions for the reaction below:
..!! Br
OH
a) Predict the product(s) of the reaction.
b) Is the substrate optically active? Are the product(s) optically active as a mix?
c) Draw the curved arrow mechanism for the reaction.
d) What happens to the SN1 reaction rate in each of these instances:
1. Change the substrate to
Br
"CI
2. Change the substrate to
3. Change the solvent from 100% CH3CH2OH to 10% CH3CH2OH + 90% DMF
4. Increase the substrate concentration by 3-fold.
Chapter 14 Solutions
GEN COMBO CHEMISTRY: ATOMS FIRST; ALEKS 360 2S ACCESS CARD CHEMISTRY:ATOMS FIRST
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The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY