Using Δ G ° rxn values from Appendix 2 , calculate the standard free-energy change of the following reaction at 25.0°C. C 4 H 10 ( g ) + O 2 ( g ) → CO 2 ( g ) + H 2 O( l ) (You must first balance the equation.) (a) + 615.9 kJ/mol (b) − 5495.8 kJ/mol (c) + 539.3 kJ/mol (d) − 615.9 kJ/mol (e) − 5511.5 kJ/mol
Using Δ G ° rxn values from Appendix 2 , calculate the standard free-energy change of the following reaction at 25.0°C. C 4 H 10 ( g ) + O 2 ( g ) → CO 2 ( g ) + H 2 O( l ) (You must first balance the equation.) (a) + 615.9 kJ/mol (b) − 5495.8 kJ/mol (c) + 539.3 kJ/mol (d) − 615.9 kJ/mol (e) − 5511.5 kJ/mol
Solution Summary: The author explains that the standard free energy change in the given reaction has to be calculated.
How many signals do you expect in the H NMR spectrum for this molecule?
Br Br
Write the answer below.
Also, in each of the drawing areas below is a copy of the molecule, with Hs shown. In each copy, one of the H atoms is colored red. Highlight in red all other H
atoms that would contribute to the same signal as the H already highlighted red
Note for advanced students: In this question, any multiplet is counted as one signal.
1
Number of signals in the 'H NMR spectrum.
For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to
the same signal as the H atom already highlighted red.
If no other H atoms will contribute, check the box at right.
Check
For the molecule in the bottom drawing area, highlight in red any other H atoms that will contribute
to the same signal as the H atom already highlighted red.
If no other H atoms will contribute, check the box at right.
O
✓
No additional Hs to color in top
molecule
ง
No additional Hs to color in bottom…
in the kinetics experiment, what were the values calculated? Select all that apply.a) equilibrium constantb) pHc) order of reactiond) rate contstant
Chapter 14 Solutions
GEN COMBO CHEMISTRY: ATOMS FIRST; ALEKS 360 2S ACCESS CARD CHEMISTRY:ATOMS FIRST
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The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY