The Basic Practice of Statistics
The Basic Practice of Statistics
7th Edition
ISBN: 9781464142536
Author: David S. Moore, William I. Notz, Michael A. Fligner
Publisher: W. H. Freeman
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Chapter 14, Problem 14.24E

(a)

To determine

The distribution of the case resistant to at least one of the three major antibiotics.

(b)

To determine

To find: The probability that exactly one out of the 10 cases was resistant to at least one of the three major antibiotics.

To calculate: The probability that exactly two out of the 10 cases was resistant to at least one of the three major antibiotics.

(c)

To determine

To find: The probability that one or more out of the 10 cases were resistant to at least one of the three major antibiotics.

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Please conduct a step by step of these statistical tests on separate sheets of Microsoft Excel. If the calculations in Microsoft Excel are incorrect, the null and alternative hypotheses, as well as the conclusions drawn from them, will be meaningless and will not receive any points. 4. One-Way ANOVA: Analyze the customer satisfaction scores across four different product categories to determine if there is a significant difference in means.  (Hints: The null can be about maintaining status-quo or no difference among groups)   H0 =   H1=
Please conduct a step by step of these statistical tests on separate sheets of Microsoft Excel. If the calculations in Microsoft Excel are incorrect, the null and alternative hypotheses, as well as the conclusions drawn from them, will be meaningless and will not receive any points                                                                                                                          2. Two-Sample T-Test: Compare the average sales revenue of two different regions to determine if there is a significant difference.  (Hints: The null can be about maintaining status-quo or no difference among groups; if alternative hypothesis is non-directional use the two-tailed p-value from excel file to make a decision about rejecting or not rejecting null)   H0 =   H1=
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