Consider the reaction N 2 O 4 ( g ) ⇌ 2NO 2 ( g ) . Draw a graph illustrating the changes of concentrations of N 2 O 4 and NO 2 as equilibrium is approached. Describe how the rates of the forward and reverse reactions change as the mixture approaches dynamic equilibrium. Why is this called a dynamic equilibrium?
Consider the reaction N 2 O 4 ( g ) ⇌ 2NO 2 ( g ) . Draw a graph illustrating the changes of concentrations of N 2 O 4 and NO 2 as equilibrium is approached. Describe how the rates of the forward and reverse reactions change as the mixture approaches dynamic equilibrium. Why is this called a dynamic equilibrium?
Author: Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Consider the reaction
N
2
O
4
(
g
)
⇌
2NO
2
(
g
)
. Draw a graph illustrating the changes of concentrations of N2O4 and NO2 as equilibrium is approached. Describe how the rates of the forward and reverse reactions change as the mixture approaches dynamic equilibrium. Why is this called a dynamic equilibrium?
Expert Solution & Answer
Interpretation Introduction
Interpretation:
The graph representing the change in the concentrations of the reactant and product at equilibrium conditions for the given reaction has to be drawn and the term dynamic equilibrium has to be explained.
Concept introduction:
Dynamic equilibrium: When the rate of forward and reverse reactions of a chemical reaction occurs with the same rate, the system is said to be at dynamic equilibrium.
Answer to Problem 14.1QP
The graph representing the given reaction at dynamic equilibrium,
Figure 1
At dynamic equilibrium the reaction is not ceased instead both the forward and reverse reactions occurs with the same rate.
Explanation of Solution
N2O4⇌2NO2
The Graph representing the given reaction is given in figure 1. As the reaction proceeds, the concentration of the reactant N2O4 decreases and attains a constant value. The concentration of the product NO2 increases with time and attains a constant value. At equilibrium conditions the concentrations of the reactant and the products remains constant.
Figure 1
In a chemical reaction when the forward and the reverse reaction has the same rate the system is said to be at dynamic equilibrium. At dynamic equilibrium the reaction is not ceased instead both the reactions occurs with the same rate.
Conclusion
The graph representing the change in the concentrations of the reactant and product at equilibrium conditions for the given reaction was drawn and the term dynamic equilibrium has been explained.
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MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10
Consider the following reaction:
CH3OH(g)
CO(g) + 2H2(g)
(Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.)
Part A
Calculate AG for this reaction at 25 °C under the following conditions:
PCH₂OH
Pco
PH2
0.815 atm
=
0.140 atm
0.170 atm
Express your answer in kilojoules to three significant figures.
Ο ΑΣΦ
AG = -150
Submit
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kJ
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Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship:
AGrxn = AGrxn + RTInQ,
AGxn+RTInQ,
where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a
is the reaction quotient.
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Identify and provide a brief explanation of Gas Chromatography (GC) within the context of chemical analysis of food. Incorporate the specific application name, provide a concise overview of sample preparation methods, outline instrumental parameters and conditions ultilized, and summarise the outcomes and findings achieved through this analytical approach.
Chapter 14 Solutions
General Chemistry - Standalone book (MindTap Course List)
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