A mixture of 0.0565 mol phosphorus pentachloride, PCl 5 , and 0.0800 mol helium gas, He, was placed in a 1.000-L flask and heated to 250.0°C. The phosphorus pentachloride decomposes at this temperature to give phosphorus trichloride, PCl 3 , and chlorine gas, Cl 2 . The helium gas is inert. PCl 5 ( g ) ⇌ PCl 3 ( g ) + Cl 2 ( g ) What is the partial pressure of helium in this equilibrium mixture at 250.0°C? At equilibrium, the total pressure is found to be 6.505 atm. What is K c for the dissociation of PCl 5 ?
A mixture of 0.0565 mol phosphorus pentachloride, PCl 5 , and 0.0800 mol helium gas, He, was placed in a 1.000-L flask and heated to 250.0°C. The phosphorus pentachloride decomposes at this temperature to give phosphorus trichloride, PCl 3 , and chlorine gas, Cl 2 . The helium gas is inert. PCl 5 ( g ) ⇌ PCl 3 ( g ) + Cl 2 ( g ) What is the partial pressure of helium in this equilibrium mixture at 250.0°C? At equilibrium, the total pressure is found to be 6.505 atm. What is K c for the dissociation of PCl 5 ?
Solution Summary: The author explains the equilibrium constant, which is the ratio of the rate constants of forward and reverse reactions at a given temperature.
Author: Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
A mixture of 0.0565 mol phosphorus pentachloride, PCl5, and 0.0800 mol helium gas, He, was placed in a 1.000-L flask and heated to 250.0°C. The phosphorus pentachloride decomposes at this temperature to give phosphorus trichloride, PCl3, and chlorine gas, Cl2. The helium gas is inert.
PCl
5
(
g
)
⇌
PCl
3
(
g
)
+
Cl
2
(
g
)
What is the partial pressure of helium in this equilibrium mixture at 250.0°C? At equilibrium, the total pressure is found to be 6.505 atm. What is Kc for the dissociation of PCl5?
In the video, we looked at the absorbance of a certain substance and how it varies
depending on what wavelength of light we are looking at. Below is a similar scan of a
different substance. What color BEST describes how this substance will appear?
Absorbance (AU)
Violet
Blue
Green
Orange
1.2
1.0-
0.8-
0.6-
0.4-
0.2
0.0
450
500
550
600
650
700
Wavelength (nm)
violet
indigo
blue
green
yellow orange
red
Red
O Cannot tell from this information
In the above graph, what causes -450 nm wavelength of light to have a higher
absorbance than light with a -550 nm wavelength? Check all that are true.
The distance the light travels is different
The different data points are for different substances
The concentration is different at different times in the experiment
Epsilon (molar absortivity) is different at different wavelengths
5. a. Data were collected for Trial 1 to determine the molar mass of a nonvolatile solid solute when dissolved in cyclo-
hexane. Complete the table for the analysis (See Report Sheet). Record calculated values with the correct number
of significant figures.
B. Freezing Point of Cyclohexane plus
Calculation Zone
Unknown Solute
2. Mass of cyclohexane (g)
10.14
Part C.4
3. Mass of added solute (g)
0.255
C. Calculations
1. k; for cyclohexane (°C⚫ kg/mol)
20.0
2. Freezing point change, AT, (°C)
3.04
Part C.6
3. Mass of cyclohexane in solution (kg)
4. Moles of solute, total (mol)
Show calculation.
5. Mass of solute in solution, total (g)
6. Molar mass of solute (g/mol)
Show calculation.
Chapter 14 Solutions
General Chemistry - Standalone book (MindTap Course List)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY