Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 14, Problem 14.1P
To determine
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Two bars of different materials and same size
are subjected to the same tensile force. If the
bars have unit elongation in the ratio 2: 5, then
the ratio of modulus of elasticity of the two
materials will be
(a) 2:5
(c) 4 :3
(b) 5:2
(d) 3:4
An aluminum alloy [E = 70 GPa; v = 0.33; a = 23.0×10-6/°C] bar is subjected to a tensile load P. The bar has a depth of d = 260 mm, a
cross-sectional area of A = 14720 mm2, and a length of L = 5.5 m. The initial longitudinal normal strain in the bar is zero. After load P
is applied and the temperature of the bar has been increased by AT = 46°C, the longitudinal normal strain is found to be 1680 µɛ.
% D
Calculate the change in bar depth d after the load P has been applied and the temperature has been increased.
L
P
Answer:
Ad =
i
mm
An extruded polymer bear is subjected to a bending moment M. The length of the bear is L = 500 mm. The cross-sectional dimensions
of the bear are b₁ = 39 mm, d₁ = 95 mm, b₂ = 23 mm, d₂ = 23 mm, and a = 8 mm. For this material, the allowable tensile bending stress is
18 MPa, and the allowable compressive bending stress is 9 MPa. Determine the largest moment M that can be applied as shown to the
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M
A
Answer:
M =
L
B
N-m
↓
a
d₂
➡AK
b₂
b₁
yak
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Materials Science And Engineering Properties
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- In the figure shown below, determine: 1) The final temperature if the normal stress at aluminium is Oal = = -90 MPa and the initial temperature 20°C. 2) The final length of the aluminium member. Aluminum Bronze A=1800mm2 A=1500mm2 E=105GPA E=73GPA a=23.2x10-6/°C a=21.6x10-6/°C Gap=0.5mm 0.35m 0.45marrow_forwardNarrow bars of aluminum are bonded to the two sides of a thick steel plate as shown. Initially, at T₁ = 70°F, all stresses are zero. Knowing that the temperature will be slowly raised to T₂ and then reduced to T₁, determine (a) the highest temperature T₂ that does not result in residual stresses, (b) the temperature T₂ that will result in a residual stress in the aluminum equal to 58 ksi. Assume aa = 12.8 x 10-6/°F for the aluminum and a = 6.5 × 10-6/°F for the steel. Further assume that the aluminum is elastoplastic with E = 10.9 × 106 psi and ay = 58 ksi. (Hint: Neglect the small stresses in the plate.) Fig. P2.121arrow_forwardA steel bar has a length of 2.5 m and cross-section of 200-mm x 100-mm. The modulus of elasticity of this material is 210 GPa and Poison's Ratio is 0.3. The change in width after applying a tensile force of 150 kN is?arrow_forward
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