(a) Step 1: Explanation The reaction of N 2 O 4 decomposing is shown below: N 2 O 4 ⇌ 2 N O 2 We are given the initial amount of N 2 O 4 which we can use to calculate the initial concentration of N 2 O 4 : 0.500 mol N 2 O 4 4.00 L = 0.125 M N 2 O 4 We can prepare an ICE table to write an expression for the equilibrium concentrations: N 2 O 4 NO 2 I 0.125 0 C - x + 2x E 0.125- x 2x We are also told that 79.3% of N 2 O 4 decomposes, so we already know the equilibrium concentration is 20.7% of the initial concentration: ( 0.125 M)(0 .207) = 0.0259 M N 2 O 4 0.0259 − x = 0.125 x = 0.099 M [ N O 2 ] = 2 x [ N O 2 ] = 2 ( 0 (b) Step 2: Interpretation Introduction To classify: The electron dot structures of each gas species.

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Chapter 14, Problem 14.148MP

(a)

Step 1:

Interpretation Introduction

To classify:

The values for K_cand K_p.

(b)

Step 2:

Interpretation Introduction

To classify:

The electron dot structures of each gas species.

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Chapter 14, Problem 14.147MP

Chapter 14, Problem 14.149MP

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Chapter 14 Solutions

Chemistry - Modified MasteringChemistry

Ch. 14 - Prob. 14.1P Ch. 14 - APPLY 14.2 Nitrogen dioxide, a pollutant that...Ch. 14 - Prob. 14.3P Ch. 14 - APPLY 14.4 Lactic acid, which builds up in muscle...Ch. 14 - Conceptual PRACTICE 14.5 The following pictures...Ch. 14 - Conceptual APPLY 14.6 The equilibrium constant...Ch. 14 - PRACTICE 14.7 In the industrial synthesis of...Ch. 14 - APPLY 14.8 At 25 °C, Kp = 25 for the reaction...Ch. 14 - Prob. 14.9P Ch. 14 - APPLY 14.10For the reaction...

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