Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781337516877
Author: Das
Publisher: Cengage
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Chapter 14, Problem 14.10P
To determine
Find the passive force
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Q1/ Find
1- Find principle stresses (61 and 62) angle of rotation and draw
2- Txy-max then draw the element with stresses
3- If the element is rotated in Ø find the stresses
and then draw the element with stresses
°X = 50
OX = 40
Txy = -20
8(cw) = 15
Txy
0x
Which one of the following statements is NOT true about this
graph?
E
F
D
Figure 1
There is a circuit.
A loop exists.
There are multiple edges.
It is a connected graph.
B
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2 points
graph has a degree 3 for each vertex, then how many
k 2 points
2. A site is underlain by a 5m-thick layer of clay. Below the layer of clay lies a 7m-thick layer of sand. The water table is
located 2m below the ground surface. Draw the profile. Then, calculate the vertical effective stress at a point located 6m
below the ground surface. Show your work and circle the answer.
Chapter 14 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
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- Using the graphic below, computer the bearings for courses AF, AB, and BC and azimuths for courses AF and BC. 128°28'58" 0.00 TRV-A 65°5'34" F 86°34'27" B 0.00 TRY-B • Azimuth AF: Bearing AF: Bearing AB: Azimuth BC: Bearing BC:arrow_forward4G 46:58 Problem 1 You are in the process of designing a water supply system for the whole Iligan City, and the design life of your system is to end in the year 2070. The population in the town has been measured every 10 years since 1980 by the Philippine Statistics Authority, and the reported populations are tabulated below. Estimate the population in the town using (a) arithmetic growth projection, (b) geometric growth projection (exponential formula), (c) declining growth projection (assuming a saturation concentration of 480,000 people), and (d) logistic curve projection. Population Year 1980 167,358 1990 226,568 2000 285,061 2010 322,821 2020 342,618 1.a) Arithmetic growth projection estimate Your answer * 5 points 1.b) Geometric growth * 5 points projection estimate Your answer 1.c) Declining growth projection estimate Your answer * 10 points כ 95arrow_forward2. Design a W section for a beam of A 36 steel Fy = 248 MPa to carry a uniform load of 293 kN/m on a simply supported span of 1.5 m. Assume lateral bracing is adequate for stability. Wt. of beam Area Depth (d) Properties of W sections available W 12 x 27 394.9 N/m Flange width (bf) Flange thickness (tf) Web thickness (tw) Moment of inertia (IX) Section modulus (SX) 5129 303.78 165.02 10.16 6.02 84.9 x 106 mm² 560.4 x 103 mm³ 3 W 12 x 31 453.4 N/m 5890 W 14 x 26 380.27 N/m 4948 307.09 352.81 165.74 127.64 11.81 10.62 6.73 6.48 99.5 x 106 mm² 101.56 x 106 mm4 674.3 x 103 mm³ 575.2 x 103 mm³arrow_forward
- ⚫ For the semi-circular arch shown in Fig.2, draw shear and bending moment diagram. 10 kN 5 m SkNarrow_forwardQ2: A 2 m X 3 m foundation is expected to carry a column load with eccentricities eB = 0.15 m and eL = 0.2 m. It is placed in a soil where e' = 10.0 kN/m2, 0'= 22°, and y = 18.0 kN/m², at 1.0 m depth. Determine the maximum load the foundation can carry with factor of safety of 3.arrow_forwardDetermine the forces in each member for the truss shown in using joint method and state if the member is in tension or compression. Wake table to show your final results. 24 kN 4 m 4 m 4 m SkN 3m shear Narrow_forward
- I need help calculating my VPC 0f 14+50, VPI 17+00 and VPT 19+50 elevations if I am given Sta 11+00 with elevation 5946.31. Problem 32 in the image below gives g1 and g2, k=64.arrow_forwardused to support the loads on the beam below. The moment of inertia of the section is |= 1384 in and distance of the centroid of the section from the bottom is y = 5.8 in. [MA 4000 lb-ft, w=900 lb/ft, P=1500 lb, a = 5 ft, b = 8 ft, c = 3 ft, d = 6 ft] Ma W a b B d P 1.5 in.k 1.5 in. 15 in. z- 2 in. 11 in. Cross section of the beam Construct the complete shear- force and bending-moment diagrams for the beam and determine the maximum positive bending moment in the beam.arrow_forwardThe cross-section shown is used to support the loads on the beam below. The moment of inertia of the section is |= 1384 in and distance of the centroid of the section from the bottom is y = 5.8 in. [MA-4000 lb-ft, w=900 lb/ft, P=1500 lb, a = 5 ft, b = 8 ft, c = 3 ft, d = 6 ft] Ma 15 in 1.5 in 13 in. 2 in 11 in. Cross section of the beam Determine the maximum tension bending stress at any location along the beam.arrow_forward
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