(a) Interpretation: The reactant, acid and base, of salt potassium bromide, KBr ( a q ) are to be identified. Concept introduction: According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion ( OH − ) . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Question

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Answer 1

Question

Chapter 14, Problem 12E

Interpretation Introduction

(a)

Interpretation:

The reactant, acid and base, of salt potassium bromide, $KBr(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $KBr(aq)$ , potassium is the cation and bromide is the anion. The $HBr$ molecule always loses its proton and gives bromide as the anion. Therefore, $HBr$ acts as an acid. Base is a species which can release a $OH−$ ion and give its cationic part to the salt. In the given reaction, $KOH$ releases $OH−$ ion and potassium acts as a cation. Therefore, $HBr$ acts as an acid and $KOH$ acts as a base.

The chemical equation is given below.

$HBr(aq)+KOH(aq)→KBr(aq)+H2O(l)$ .

Conclusion

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Interpretation Introduction

(b)

Interpretation:

The reactant, acid and base, of salt barium chloride, $BaCl2(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $BaCl2(aq)$ , barium is the cation and chloride is the anion. The $HCl$ molecule always loses its proton and gives chloride as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt. In the given reaction, $Ba(OH)2$ releases the $OH−$ ion and barium as a cation. Therefore, $HCl$ acts as an acid and $Ba(OH)2$ acts as a base for salt $BaCl2(aq)$ .

The chemical equation is given below.

$2HCl(aq)+Ba(OH)2(aq)→BaCl2(aq)+2H2O(l)$ .

Conclusion

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Interpretation Introduction

(c)

Interpretation:

The reactant, acid and base, of salt cobalt (II) sulfate, $CoSO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $CoSO4(aq)$ , cobalt is the cation and sulphate is the anion. The $H2SO4$ molecule always loses its proton and gives sulphate as the anion. Oxides of metals are basic in nature. Metal of oxides reacts to give cation of the given salt. Therefore, $CoO$ acts as base and $H2SO4$ acts as an acid.

The chemical equation is given below.

$H2SO4(aq)+CoO(aq)→CoSO4(aq)+H2O(l)$ .

Conclusion

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Interpretation Introduction

(d)

Interpretation:

The reactant, acid and base, of salt sodium phosphate, $Na3PO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is $H3PO4$ and base is $NaOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $Na3PO4(aq)$ , sodium is the cation and phosphate is the anion. The $H3PO4$ molecule always loses its proton and gives phosphate as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt.. In the given reaction, $NaOH$ releases $OH−$ ion and gives sodium ion as a cation to salt. Therefore, $H3PO4$ acts as an acid and $NaOH$ acts as a base.

The chemical equation is given below.

$H3PO4(aq)+3 NaOH(aq)→Na3PO4(aq)(aq)+3 H2O(l)$ .

Conclusion

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is and base is $NaOH$ .

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Answer 2

Question

Chapter 14, Problem 12E

Interpretation Introduction

(a)

Interpretation:

The reactant, acid and base, of salt potassium bromide, $KBr(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $KBr(aq)$ , potassium is the cation and bromide is the anion. The $HBr$ molecule always loses its proton and gives bromide as the anion. Therefore, $HBr$ acts as an acid. Base is a species which can release a $OH−$ ion and give its cationic part to the salt. In the given reaction, $KOH$ releases $OH−$ ion and potassium acts as a cation. Therefore, $HBr$ acts as an acid and $KOH$ acts as a base.

The chemical equation is given below.

$HBr(aq)+KOH(aq)→KBr(aq)+H2O(l)$ .

Conclusion

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Interpretation Introduction

(b)

Interpretation:

The reactant, acid and base, of salt barium chloride, $BaCl2(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $BaCl2(aq)$ , barium is the cation and chloride is the anion. The $HCl$ molecule always loses its proton and gives chloride as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt. In the given reaction, $Ba(OH)2$ releases the $OH−$ ion and barium as a cation. Therefore, $HCl$ acts as an acid and $Ba(OH)2$ acts as a base for salt $BaCl2(aq)$ .

The chemical equation is given below.

$2HCl(aq)+Ba(OH)2(aq)→BaCl2(aq)+2H2O(l)$ .

Conclusion

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Interpretation Introduction

(c)

Interpretation:

The reactant, acid and base, of salt cobalt (II) sulfate, $CoSO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $CoSO4(aq)$ , cobalt is the cation and sulphate is the anion. The $H2SO4$ molecule always loses its proton and gives sulphate as the anion. Oxides of metals are basic in nature. Metal of oxides reacts to give cation of the given salt. Therefore, $CoO$ acts as base and $H2SO4$ acts as an acid.

The chemical equation is given below.

$H2SO4(aq)+CoO(aq)→CoSO4(aq)+H2O(l)$ .

Conclusion

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Interpretation Introduction

(d)

Interpretation:

The reactant, acid and base, of salt sodium phosphate, $Na3PO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is $H3PO4$ and base is $NaOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $Na3PO4(aq)$ , sodium is the cation and phosphate is the anion. The $H3PO4$ molecule always loses its proton and gives phosphate as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt.. In the given reaction, $NaOH$ releases $OH−$ ion and gives sodium ion as a cation to salt. Therefore, $H3PO4$ acts as an acid and $NaOH$ acts as a base.

The chemical equation is given below.

$H3PO4(aq)+3 NaOH(aq)→Na3PO4(aq)(aq)+3 H2O(l)$ .

Conclusion

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is and base is $NaOH$ .

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Answer 3

Question

Chapter 14, Problem 12E

Interpretation Introduction

(a)

Interpretation:

The reactant, acid and base, of salt potassium bromide, $KBr(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $KBr(aq)$ , potassium is the cation and bromide is the anion. The $HBr$ molecule always loses its proton and gives bromide as the anion. Therefore, $HBr$ acts as an acid. Base is a species which can release a $OH−$ ion and give its cationic part to the salt. In the given reaction, $KOH$ releases $OH−$ ion and potassium acts as a cation. Therefore, $HBr$ acts as an acid and $KOH$ acts as a base.

The chemical equation is given below.

$HBr(aq)+KOH(aq)→KBr(aq)+H2O(l)$ .

Conclusion

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Interpretation Introduction

(b)

Interpretation:

The reactant, acid and base, of salt barium chloride, $BaCl2(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $BaCl2(aq)$ , barium is the cation and chloride is the anion. The $HCl$ molecule always loses its proton and gives chloride as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt. In the given reaction, $Ba(OH)2$ releases the $OH−$ ion and barium as a cation. Therefore, $HCl$ acts as an acid and $Ba(OH)2$ acts as a base for salt $BaCl2(aq)$ .

The chemical equation is given below.

$2HCl(aq)+Ba(OH)2(aq)→BaCl2(aq)+2H2O(l)$ .

Conclusion

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Interpretation Introduction

(c)

Interpretation:

The reactant, acid and base, of salt cobalt (II) sulfate, $CoSO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $CoSO4(aq)$ , cobalt is the cation and sulphate is the anion. The $H2SO4$ molecule always loses its proton and gives sulphate as the anion. Oxides of metals are basic in nature. Metal of oxides reacts to give cation of the given salt. Therefore, $CoO$ acts as base and $H2SO4$ acts as an acid.

The chemical equation is given below.

$H2SO4(aq)+CoO(aq)→CoSO4(aq)+H2O(l)$ .

Conclusion

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Interpretation Introduction

(d)

Interpretation:

The reactant, acid and base, of salt sodium phosphate, $Na3PO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is $H3PO4$ and base is $NaOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $Na3PO4(aq)$ , sodium is the cation and phosphate is the anion. The $H3PO4$ molecule always loses its proton and gives phosphate as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt.. In the given reaction, $NaOH$ releases $OH−$ ion and gives sodium ion as a cation to salt. Therefore, $H3PO4$ acts as an acid and $NaOH$ acts as a base.

The chemical equation is given below.

$H3PO4(aq)+3 NaOH(aq)→Na3PO4(aq)(aq)+3 H2O(l)$ .

Conclusion

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is and base is $NaOH$ .

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Answer 4

Question

Chapter 14, Problem 12E

Interpretation Introduction

(a)

Interpretation:

The reactant, acid and base, of salt potassium bromide, $KBr(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $KBr(aq)$ , potassium is the cation and bromide is the anion. The $HBr$ molecule always loses its proton and gives bromide as the anion. Therefore, $HBr$ acts as an acid. Base is a species which can release a $OH−$ ion and give its cationic part to the salt. In the given reaction, $KOH$ releases $OH−$ ion and potassium acts as a cation. Therefore, $HBr$ acts as an acid and $KOH$ acts as a base.

The chemical equation is given below.

$HBr(aq)+KOH(aq)→KBr(aq)+H2O(l)$ .

Conclusion

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Interpretation Introduction

(b)

Interpretation:

The reactant, acid and base, of salt barium chloride, $BaCl2(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $BaCl2(aq)$ , barium is the cation and chloride is the anion. The $HCl$ molecule always loses its proton and gives chloride as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt. In the given reaction, $Ba(OH)2$ releases the $OH−$ ion and barium as a cation. Therefore, $HCl$ acts as an acid and $Ba(OH)2$ acts as a base for salt $BaCl2(aq)$ .

The chemical equation is given below.

$2HCl(aq)+Ba(OH)2(aq)→BaCl2(aq)+2H2O(l)$ .

Conclusion

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Interpretation Introduction

(c)

Interpretation:

The reactant, acid and base, of salt cobalt (II) sulfate, $CoSO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $CoSO4(aq)$ , cobalt is the cation and sulphate is the anion. The $H2SO4$ molecule always loses its proton and gives sulphate as the anion. Oxides of metals are basic in nature. Metal of oxides reacts to give cation of the given salt. Therefore, $CoO$ acts as base and $H2SO4$ acts as an acid.

The chemical equation is given below.

$H2SO4(aq)+CoO(aq)→CoSO4(aq)+H2O(l)$ .

Conclusion

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Interpretation Introduction

(d)

Interpretation:

The reactant, acid and base, of salt sodium phosphate, $Na3PO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is $H3PO4$ and base is $NaOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $Na3PO4(aq)$ , sodium is the cation and phosphate is the anion. The $H3PO4$ molecule always loses its proton and gives phosphate as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt.. In the given reaction, $NaOH$ releases $OH−$ ion and gives sodium ion as a cation to salt. Therefore, $H3PO4$ acts as an acid and $NaOH$ acts as a base.

The chemical equation is given below.

$H3PO4(aq)+3 NaOH(aq)→Na3PO4(aq)(aq)+3 H2O(l)$ .

Conclusion

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is and base is $NaOH$ .

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Answer 5

Chapter 14, Problem 12E

Interpretation Introduction

(a)

Interpretation:

The reactant, acid and base, of salt potassium bromide, $KBr(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $KBr(aq)$ , potassium is the cation and bromide is the anion. The $HBr$ molecule always loses its proton and gives bromide as the anion. Therefore, $HBr$ acts as an acid. Base is a species which can release a $OH−$ ion and give its cationic part to the salt. In the given reaction, $KOH$ releases $OH−$ ion and potassium acts as a cation. Therefore, $HBr$ acts as an acid and $KOH$ acts as a base.

The chemical equation is given below.

$HBr(aq)+KOH(aq)→KBr(aq)+H2O(l)$ .

Conclusion

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Interpretation Introduction

(b)

Interpretation:

The reactant, acid and base, of salt barium chloride, $BaCl2(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $BaCl2(aq)$ , barium is the cation and chloride is the anion. The $HCl$ molecule always loses its proton and gives chloride as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt. In the given reaction, $Ba(OH)2$ releases the $OH−$ ion and barium as a cation. Therefore, $HCl$ acts as an acid and $Ba(OH)2$ acts as a base for salt $BaCl2(aq)$ .

The chemical equation is given below.

$2HCl(aq)+Ba(OH)2(aq)→BaCl2(aq)+2H2O(l)$ .

Conclusion

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Interpretation Introduction

(c)

Interpretation:

The reactant, acid and base, of salt cobalt (II) sulfate, $CoSO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $CoSO4(aq)$ , cobalt is the cation and sulphate is the anion. The $H2SO4$ molecule always loses its proton and gives sulphate as the anion. Oxides of metals are basic in nature. Metal of oxides reacts to give cation of the given salt. Therefore, $CoO$ acts as base and $H2SO4$ acts as an acid.

The chemical equation is given below.

$H2SO4(aq)+CoO(aq)→CoSO4(aq)+H2O(l)$ .

Conclusion

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Interpretation Introduction

(d)

Interpretation:

The reactant, acid and base, of salt sodium phosphate, $Na3PO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is $H3PO4$ and base is $NaOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $Na3PO4(aq)$ , sodium is the cation and phosphate is the anion. The $H3PO4$ molecule always loses its proton and gives phosphate as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt.. In the given reaction, $NaOH$ releases $OH−$ ion and gives sodium ion as a cation to salt. Therefore, $H3PO4$ acts as an acid and $NaOH$ acts as a base.

The chemical equation is given below.

$H3PO4(aq)+3 NaOH(aq)→Na3PO4(aq)(aq)+3 H2O(l)$ .

Conclusion

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is and base is $NaOH$ .

Answer 6

Chapter 14, Problem 12E

Interpretation Introduction

(a)

Interpretation:

The reactant, acid and base, of salt potassium bromide, $KBr(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $KBr(aq)$ , potassium is the cation and bromide is the anion. The $HBr$ molecule always loses its proton and gives bromide as the anion. Therefore, $HBr$ acts as an acid. Base is a species which can release a $OH−$ ion and give its cationic part to the salt. In the given reaction, $KOH$ releases $OH−$ ion and potassium acts as a cation. Therefore, $HBr$ acts as an acid and $KOH$ acts as a base.

The chemical equation is given below.

$HBr(aq)+KOH(aq)→KBr(aq)+H2O(l)$ .

Conclusion

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Answer 7

Chapter 14, Problem 12E

Interpretation Introduction

(a)

Interpretation:

The reactant, acid and base, of salt potassium bromide, $KBr(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Answer 8

Expert Solution

Answer to Problem 12E

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $KBr(aq)$ , potassium is the cation and bromide is the anion. The $HBr$ molecule always loses its proton and gives bromide as the anion. Therefore, $HBr$ acts as an acid. Base is a species which can release a $OH−$ ion and give its cationic part to the salt. In the given reaction, $KOH$ releases $OH−$ ion and potassium acts as a cation. Therefore, $HBr$ acts as an acid and $KOH$ acts as a base.

The chemical equation is given below.

$HBr(aq)+KOH(aq)→KBr(aq)+H2O(l)$ .

Answer 13

Conclusion

In the formation of salt potassium bromide, $KBr(aq)$ , acid is $HBr$ and base is $KOH$ .

Answer 14

Interpretation Introduction

(b)

Interpretation:

The reactant, acid and base, of salt barium chloride, $BaCl2(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $BaCl2(aq)$ , barium is the cation and chloride is the anion. The $HCl$ molecule always loses its proton and gives chloride as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt. In the given reaction, $Ba(OH)2$ releases the $OH−$ ion and barium as a cation. Therefore, $HCl$ acts as an acid and $Ba(OH)2$ acts as a base for salt $BaCl2(aq)$ .

The chemical equation is given below.

$2HCl(aq)+Ba(OH)2(aq)→BaCl2(aq)+2H2O(l)$ .

Conclusion

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Answer 15

Interpretation Introduction

(b)

Interpretation:

The reactant, acid and base, of salt barium chloride, $BaCl2(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Answer 16

Expert Solution

Answer to Problem 12E

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $BaCl2(aq)$ , barium is the cation and chloride is the anion. The $HCl$ molecule always loses its proton and gives chloride as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt. In the given reaction, $Ba(OH)2$ releases the $OH−$ ion and barium as a cation. Therefore, $HCl$ acts as an acid and $Ba(OH)2$ acts as a base for salt $BaCl2(aq)$ .

The chemical equation is given below.

$2HCl(aq)+Ba(OH)2(aq)→BaCl2(aq)+2H2O(l)$ .

Answer 21

Conclusion

In the formation of salt barium chloride, $BaCl2(aq)$ , acid is $HCl$ and base is $Ba(OH)2$ .

Answer 22

Interpretation Introduction

(c)

Interpretation:

The reactant, acid and base, of salt cobalt (II) sulfate, $CoSO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $CoSO4(aq)$ , cobalt is the cation and sulphate is the anion. The $H2SO4$ molecule always loses its proton and gives sulphate as the anion. Oxides of metals are basic in nature. Metal of oxides reacts to give cation of the given salt. Therefore, $CoO$ acts as base and $H2SO4$ acts as an acid.

The chemical equation is given below.

$H2SO4(aq)+CoO(aq)→CoSO4(aq)+H2O(l)$ .

Conclusion

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Answer 23

Interpretation Introduction

(c)

Interpretation:

The reactant, acid and base, of salt cobalt (II) sulfate, $CoSO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Answer 24

Expert Solution

Answer to Problem 12E

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $CoSO4(aq)$ , cobalt is the cation and sulphate is the anion. The $H2SO4$ molecule always loses its proton and gives sulphate as the anion. Oxides of metals are basic in nature. Metal of oxides reacts to give cation of the given salt. Therefore, $CoO$ acts as base and $H2SO4$ acts as an acid.

The chemical equation is given below.

$H2SO4(aq)+CoO(aq)→CoSO4(aq)+H2O(l)$ .

Answer 29

Conclusion

In the formation of salt cobalt (II) sulfate, $CoSO4(aq)$ , acid is $H2SO4$ and base is $CoO$ .

Answer 30

Interpretation Introduction

(d)

Interpretation:

The reactant, acid and base, of salt sodium phosphate, $Na3PO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Expert Solution

Answer to Problem 12E

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is $H3PO4$ and base is $NaOH$ .

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $Na3PO4(aq)$ , sodium is the cation and phosphate is the anion. The $H3PO4$ molecule always loses its proton and gives phosphate as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt.. In the given reaction, $NaOH$ releases $OH−$ ion and gives sodium ion as a cation to salt. Therefore, $H3PO4$ acts as an acid and $NaOH$ acts as a base.

The chemical equation is given below.

$H3PO4(aq)+3 NaOH(aq)→Na3PO4(aq)(aq)+3 H2O(l)$ .

Conclusion

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is and base is $NaOH$ .

Answer 31

Interpretation Introduction

(d)

Interpretation:

The reactant, acid and base, of salt sodium phosphate, $Na3PO4(aq)$ are to be identified.

Concept introduction:

According to Arrhenius theory, an acid is defined as a species which donates a proton. A base is defined as a species which can donate a hydroxide ion $(OH−)$ . Neutralization reaction is the reaction in which an acid and a base react to give water and salt of an acid and base.

Answer 32

Expert Solution

Answer to Problem 12E

In the formation of salt sodium phosphate, $Na3PO4(aq)$ , acid is $H3PO4$ and base is $NaOH$ .

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Explanation of Solution

Acids loses their $H+$ ion and give their anionic part to the salt. In the given salt, $Na3PO4(aq)$ , sodium is the cation and phosphate is the anion. The $H3PO4$ molecule always loses its proton and gives phosphate as the anion. Base is a species which can release a $OH−$ ion and gives cation to the salt.. In the given reaction, $NaOH$ releases $OH−$ ion and gives sodium ion as a cation to salt. Therefore, $H3PO4$ acts as an acid and $NaOH$ acts as a base.