The data in the table are for the reaction of NO and O2 at 660 K.
NO(g) + ½ O2(g) → NO2(g)
- (a) Determine the order of the reaction for each reactant.
- (b) Write the rate equation for the reaction.
- (c) Calculate the rate constant.
- (d) Calculate the rate (in mol/L · s) at the instant when [NO] = 0.015 mol/L and [O2] = 0.0050 mol/L.
- (e) At the instant when NO is reacting at the rate 1.0 × 10−4 mol/L · s, what is the rate at which O2 is reacting and NO2 is forming?
(a)

Interpretation:
The order of the reaction for each reactant has to be determined
Concept Introduction:
Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.
Order of a reaction: The order of a reaction with respect to a particular reactant is the exponent of its concentration term in the rate law expression, and the overall reaction order is the sum of the exponents on all concentration terms.
Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.
Answer to Problem 11PS
The order of
Explanation of Solution
The reaction rate of the chemical reaction is given as,
In order to figure out the reaction equation the order of the reactants needed, which is calculated by comparing any two experiments where the concentration of
(b)

Interpretation:
The rate equation for the reaction has to be written.
Concept Introduction:
Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.
Order of a reaction: The order of a reaction with respect to a particular reactant is the exponent of its concentration term in the rate law expression, and the overall reaction order is the sum of the exponents on all concentration terms.
Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.
Answer to Problem 11PS
The rate equation is
Explanation of Solution
The reaction rate is given as,
Hence, Rate equation is
(c)

Interpretation:
The rate constant has to be calculated.
Concept Introduction:
Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.
Order of a reaction: The order of a reaction with respect to a particular reactant is the exponent of its concentration term in the rate law expression, and the overall reaction order is the sum of the exponents on all concentration terms.
Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.
Answer to Problem 11PS
The value of rate constant is
Explanation of Solution
The rate constant is calculated as,
The rate constant value is obtained as shown above. By substituting the any one of the concentrations of reactants and the initial rate into the reaction equation obtained at first.
Hence, the value of rate constant is
(d)

Interpretation:
The rate in
Concept Introduction:
Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.
Order of a reaction: The order of a reaction with respect to a particular reactant is the exponent of its concentration term in the rate law expression, and the overall reaction order is the sum of the exponents on all concentration terms.
Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.
Answer to Problem 11PS
The instantaneous rate of the reaction is
Explanation of Solution
The rate is calculated as,
The instantaneous rate of the reaction is
(e)

Interpretation:
The rate at which
Concept Introduction:
Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.
Order of a reaction: The order of a reaction with respect to a particular reactant is the exponent of its concentration term in the rate law expression, and the overall reaction order is the sum of the exponents on all concentration terms.
Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.
Answer to Problem 11PS
The rate when oxygen reacting is
Explanation of Solution
The rate is calculated as,
The rate when oxygen reacting is
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