Concept explainers
Answers to all problems are at the end of this book. Detailed solutions are available in the Student Solutions Manual. Study Guide, and Problems Book.
Assessing the-
Fructose-1.6-blsphosphate + H2O → Fmrlose-6-P + Pi
The human brain requires glucose as its only energy source, and the typical brain consumes about 120 g (or 480 kilocalories) of glucose dally. Ordinarily, two pieces of sausage pizza could provide more than enough potential glucose to feed the brain for a day. According to a national fast-food chain, two pieces of sausage pizza provide 1340 kilocalories. 48% of which is from fat. Fats cannot be converted to glucose in gluconeogenesis, so that leaves 697 kilocalories potentially available for glucose synthesis. The first-order rate constant for the hydrolysis of fructose-l.6-bispliosphate in the absence of enzyme is 2 × 10-20 /sec. Calculate how long it would take to provide enough glucose for one day of brain activity from two pieces of sausage pizza without the enzyme.
The following graphs show the temperature and pH dependencies of four enzymes, A, Î’, X, and Y. Problems 12 through IS refer to these graphs.

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Chapter 14 Solutions
BIOCHEM. II-EBOOK ACCESS>CUSTOM<
- The following data were recorded for the enzyme catalyzed conversion of S -> P. Question: Estimate the Vmax and Km. What would be the rate at 2.5 and 5.0 x 10-5 M [S] ?arrow_forwardPlease helparrow_forwardThe following data were recorded for the enzyme catalyzed conversion of S -> P Question: what would the rate be at 5.0 x 10-5 M [S] and the enzyme concentration was doubled? Also, the rate given in the table is from product accumulation after 10 minuets of reaction time. Verify these rates represent a true initial rate (less than 5% turnover). Please helparrow_forward
- The following data was obtained on isocitrate lyase from an algal species. Identify the reaction catalyzed by this enzyme, deduce the KM and Vmax , and determine the nature of the inhibition by oxaloacetate. Please helparrow_forwardIn the table below, there are sketches of four crystals made of positively-charged cations and negatively-charged anions. Rank these crystals in decreasing order of stability (or equivalently increasing order of energy). That is, select "1" below the most stable (lowest energy) crystal. Select "2" below the next most stable (next lowest energy) crystal, and so forth. A B 鹽 (Choose one) +2 C +2 +2 (Choose one) D 鹽雞 (Choose one) (Choose one)arrow_forward1. Draw the structures for the fats A. 16:2: w-3 and B. 18:3:49,12,15 2. Name each of the molecules below (image attached)arrow_forward
- draw the structures for the fats A. 16:2:w-3 B 18:3:9,12,15arrow_forward1. Below is a template strand of DNA. Show the mRNA and protein that would result. label the ends of the molecules ( refer to attached image)arrow_forwardAttach the followina labels to the diagram below: helicase, single stranded binding proteins, lagging strand, leading strand, DNA polymerase, primase, 5' ends (3), 3' ends (3) (image attached)arrow_forward
- 1. How much energy in terms of ATP can be obtained from tristearin (stearate is 18:0) Show steps pleasearrow_forwardMultiple choice urgent!!arrow_forward1. Write the transamination reaction for alanine. Indicate what happens next to each of the molecules in the reaction, and under what conditions it happens. 2.arrow_forward
- BiochemistryBiochemistryISBN:9781305577206Author:Reginald H. Garrett, Charles M. GrishamPublisher:Cengage Learning
