Consider a 100 mL of solution with 13.5% of NaCl by mass with a density of 1.12 g mL . What among solute and solvent and how much we need to add to given solution to make the boiling point of solution104.4°C (take i=1.8). Concept introduction: a) The percentage by mass means that that amount of solute is dissolved in 100 g of solution. b) The elevation in boiling point is a colligative property and is related to molality as ∆T b = i.K b .m where, ∆T b is change in boiling temperature i is Van’t Hoff factor K b is molal boiling-point elevation constant m is molality Given: The density of solution is 1.12 g mL Volume of solution is 100 mL Mass percentage of NaCl is 13.5 % Van’t Hoff factor = i = 1.8

Question

What spectral features allow you to differentiate the product from the starting material? Use four separate paragraphs for each set of comparisons. You should have one paragraph each devoted to MS, HNMR, CNMR and IR. 2) For MS, the differing masses of molecular ions are a popular starting point. Including a unique fragmentation is important, too. 3) For HNMR, CNMR and IR state the peaks that are different and what makes them different (usually the presence or absence of certain groups). See if you can find two differences (in each set of IR, HNMR and CNMR spectra) due to the presence or absence of a functional group. Include peak locations. Alternatively, you can state a shift of a peak due to a change near a given functional group. Including peak locations for shifted peaks, as well as what these peaks are due to. Ideally, your focus should be on not just identifying the differences but explaining them in terms of functional group changes.

Answer 1

Question

Chapter 14, Problem 119E

Interpretation Introduction

Interpretation:

Consider a 100 mL of solution with 13.5% of NaCl by mass with a density of 1.12 $\frac{g}{mL}$ . What among solute and solvent and how much we need to add to given solution to make the boiling point of solution104.4°C (take i=1.8).

Concept introduction:

a) The percentage by mass means that that amount of solute is dissolved in 100 g of solution.

b) The elevation in boiling point is a colligative property and is related to molality as

∆T_b = i.K_b.m

where,

∆T_b is change in boiling temperature

i is Van’t Hoff factor

K_b is molal boiling-point elevation constant

m is molality

Given:

The density of solution is 1.12 $\frac{g}{mL}$

Volume of solution is 100 mL

Mass percentage of NaCl is 13.5 %

Van’t Hoff factor = i = 1.8

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

What spectral features allow you to differentiate the product from the starting material? Use four separate paragraphs for each set of comparisons. You should have one paragraph each devoted to MS, HNMR, CNMR and IR. 2) For MS, the differing masses of molecular ions are a popular starting point. Including a unique fragmentation is important, too. 3) For HNMR, CNMR and IR state the peaks that are different and what makes them different (usually the presence or absence of certain groups). See if you can find two differences (in each set of IR, HNMR and CNMR spectra) due to the presence or absence of a functional group. Include peak locations. Alternatively, you can state a shift of a peak due to a change near a given functional group. Including peak locations for shifted peaks, as well as what these peaks are due to. Ideally, your focus should be on not just identifying the differences but explaining them in terms of functional group changes.

Question 6 What is the major product of the following Diels-Alder reaction? ? Aldy by day of A. H о B. C. D. E. OB OD Oc OE OA

None