
Concept explainers
(a)
The density of particles in the atmosphere of Titan.

Answer to Problem 115QAP
The density of particles in the atmosphere of Titan is
Explanation of Solution
Given info:
Temperature at Titan is,
Pressure at Titan is,
Mass of nitrogen molecule is,
Diameter of the sphere is,
Formula used:
Formula for the ideal gas equation is,
Calculation:
The density of particles can be calculated as,
Conclusion:
Thus, the density of particles in the atmosphere of Titan is
(b)
The body that have denser atmosphere, Titan or Earth.

Answer to Problem 115QAP
Titan has denser atmosphere.
Explanation of Solution
Given info:
Temperature at Titan is,
Pressure at Titan is,
Mass of nitrogen molecule is,
Diameter of the sphere is,
Temperature at Earth is,
Pressure at Earth is,
Formula used:
Formula for the ideal gas equation is,
Calculation:
The particle density on Titan can be calculated as,
The particle density on Earth can be calculated as,
Dividing equation (1) by equation (2), we get
So, the particle density on Titan is
Conclusion:
Thus, Titan has denser atmosphere.
(c)
The average distance that a nitrogen molecule travels between collisions on Titan and compare it with the distance for oxygen.

Answer to Problem 115QAP
The average distance that a nitrogen molecule travels between collisions on Titan is
Explanation of Solution
Given info:
Diameter of the sphere is,
Density of particle at Titan is,
Formula used:
The formula for the mean free path is given as,
Calculation:
The average distance that a nitrogen molecule travels between collisions can be calculated as,
The average distance for oxygen is
The average distance that a nitrogen molecule travels between collisions is not reasonable because it is more than the diameter of the sphere. It shows that there will be no collision between the particles in the atmosphere of Titan.
Conclusion:
Thus, the average distance that a nitrogen molecule travels between collisions on Titan is
Want to see more full solutions like this?
Chapter 14 Solutions
COLLEGE PHYSICS
- An amoeba is 0.309 cm away from the 0.304 cm focal length objective lens of a microscope.arrow_forwardTwo resistors of resistances R1 and R2, with R2>R1, are connected to a voltage source with voltage V0. When the resistors are connected in series, the current is Is. When the resistors are connected in parallel, the current Ip from the source is equal to 10Is. Let r be the ratio R1/R2. Find r. I know you have to find the equations for V for both situations and relate them, I'm just struggling to do so. Please explain all steps, thank you.arrow_forwardBheem and Ram, jump off either side of a bridge while holding opposite ends of a rope and swing back and forth under the bridge to save a child while avoiding a fire. Looking at the swing of just Bheem, we can approximate him as a simple pendulum with a period of motion of 5.59 s. How long is the pendulum ? When Bheem swings, he goes a full distance, from side to side, of 10.2 m. What is his maximum velocity? What is his maximum acceleration?arrow_forward
- The position of a 0.300 kg object attached to a spring is described by x=0.271 m ⋅ cos(0.512π⋅rad/s ⋅t) (Assume t is in seconds.) Find the amplitude of the motion. Find the spring constant. Find the position of the object at t = 0.324 s. Find the object's velocity at t = 0.324 s.arrow_forwardMin Min is hanging from her spring-arms off the edge of the level. Due to the spring like nature of her arms she is bouncing up and down in simple harmonic motion with a maximum displacement from equilibrium of 0.118 m. The spring constant of Min-Min’s arms is 9560. N/m and she has a mass of 87.5 kg. What is the period at which she oscillates? Find her maximum speed. Find her speed when she is located 5.00 cm from her equilibrium position.arrow_forward(a) What magnification in multiples is produced by a 0.150 cm focal length microscope objective that is 0.160 cm from the object being viewed? 15.9 (b) What is the overall magnification in multiples if an eyepiece that produces a magnification of 7.90x is used? 126 × ×arrow_forward
- Gravitational Potential Energyarrow_forwardE = кедо Xo A continuous line of charge lies along the x axis, extending from x = +x to positive infinity. The line carries positive charge with a uniform linear charge density 10. (a) What is the magnitude of the electric field at the origin? (Use the following as necessary: 10, Xo, and ke.) (b) What is the direction of the electric field at the origin? O O O O O O G -y +z ○ -z +x -x +yarrow_forwardInclude free body diagramarrow_forward
- 2 Spring 2025 -03 PITT Calculate the acceleration of a skier heading down a 10.0° slope, assuming the coefficient of cold coast at a constant velocity. You can neglect air resistance in both parts. friction for waxed wood on wet snow fly 0.1 (b) Find the angle of the slope down which this skier Given: 9 = ? 8=10° 4=0.1arrow_forwarddry 5. (a) When rebuilding her car's engine, a physics major must exert 300 N of force to insert a c piston into a steel cylinder. What is the normal force between the piston and cyli=030 What force would she have to exert if the steel parts were oiled? k F = 306N 2 =0.03 (arrow_forwardInclude free body diagramarrow_forward
- College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegePrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning





