Chapter 14, Problem 112E

Interpretation Introduction

Interpretation: The pH of the solution is to be determined.

Concept Introduction: The pH scale tells about the acidity of solution.

The molarity of a substance is equal to the ratio of number of moles and the volume of a solution in litres and expressed as:

$\text{M}=\frac{n}{V}$ ...... (1)

Here, $\text{M}$ is the molarity, $V$ is the volume and $n$ is the number of moles

The pOH of a given solution is expressed by the formula as:

$\text{pOH}=-\text{log}\left[{\text{OH}}^{-}\right]$ ...... (2)

The pH of a given solution is expressed by the formula as follows:

$\text{pH}=-\text{log}\left[{\text{H}}_3{\text{O}}^{+}\right]$ ...... (3)

Also, the sum of pOH and pH of a solution is equal to 14.

$\text{pOH}+\text{pH}=14.0$ ...... (4)