Explanation Given: The provided equations are: x = y 2 + 1 , x = 0 , y = 0 and y = 2 Formula used: The area of a region is given by A = ∫ x l x h ∫ y l y h d y d x Vertex form of parabola’s equation is given by ( x − h ) = a ( y − k ) 2 Here ( h , k ) is the vertex of the parabola Calculation: The equation x = y 2 + 1 is the equation of a parabola. Write it in its vertex form x = y 2 + 1 x − 1 = y 2 ( x − 1 ) = ( y − 0 ) 2 Vertex of this parabola is given by V = ( 1 , 0 ) The equation x = 0 represents y -axis. The equation y = 0 represents x -axis. The equation y = 2 is a straight line parallel to x -axis passing through y = 2 . Intersection of parabola and line y = 2 is: x = y 2 + 1 = 2 2 + 1 = 5 Therefore, the intersection point is ( 5 , 2 )

Student Solutions Manual For Larson/edwards? Multivariable Calculus, 11th

11th Edition

ISBN: 9781337275392

Author: Larson, Ron; Edwards, Bruce H.

Publisher: Cengage Learning

See similar textbooks

Videos

Question

Chapter 14, Problem 10RE

To determine

To calculate: The area of the region bounded by the graphs of given equation x=y2+1, x=0, y=0 and y=2.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 14, Problem 9RE

Chapter 14, Problem 11RE

Students have asked these similar questions

23. Network Analysis The figure shows the flow of traffic (in vehicles per hour) through a network of streets. 200 100- -100 200 (a) Solve this system for i = 1, 2, 3, 4. (b) Find the traffic flow when x = 0. (c) Find the traffic flow when x = 100. (d) Find the traffic flow when x, = 2x₂.

2\int_{-3/2}^{3/2} \sqrt{4u^2+2} du

2. Consider the following: Prove that x, x2, and 1/x are the solutions to the homogeneous equation corresponding to x³y"" + x²y" + 2xy' + 2y = 2x4. b. use variation of parameters to find a particular solution and complete the general solution to the differential equation. I am interested in process. You may use a computer for integration, finding determinants and doing Kramer's.

Chapter 14 Solutions

Student Solutions Manual For Larson/edwards? Multivariable Calculus, 11th

Ch. 14.1 - CONCEPT CHECK Iterated Integral Explain what is...Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E Ch. 14.1 - Prob. 5E Ch. 14.1 - Prob. 6E Ch. 14.1 - Evaluating an Integral In Exercises 3-10, evaluate...Ch. 14.1 - Prob. 8E Ch. 14.1 - Prob. 9E Ch. 14.1 - Evaluating an Integral In Exercises 3-10, evaluate...

Knowledge Booster

$Calculus$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.

The area of the region bounded by the graphs of given equation x = y 2 + 1 , x = 0 , y = 0 and y = 2 .

Solution Summary: The author explains how to calculate the area of a region bounded by the graphs of given equations.

Videos

To calculate: The area of the region bounded by the graphs of given equation x=y2+1, x=0, y=0 and y=2.

Want to see the full answer?

Chapter 14 Solutions