Explanation Given Information: The provided area is 30 .8m 2 and one length is 12.8 m. The second length is 42.5. Formula used: The direct variation of the quantities x and y is, y 1 x 1 = y 2 x 2 Calculation: According to the provided variation; The width varies directly as its length, Thus, the direct variation is, A 1 l 1 = A 2 l 2 Substitute 42

Bundle: Elementary Technical Mathematics, Loose-leaf Version, 12th + WebAssign Printed Access Card, Single-Term

12th Edition

ISBN: 9781337890199

Author: Dale Ewen

Publisher: Cengage Learning

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Chapter 14, Problem 10CR

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To calculate: The area of a rectangle when the length is 42.5 m if the area of a rectangle with constant width varies directly as its length and area are 30.8 m2 when the length is 12.8 m.

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Chapter 14, Problem 9CR

Chapter 14, Problem 11CR

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Chapter 14 Solutions

Bundle: Elementary Technical Mathematics, Loose-leaf Version, 12th + WebAssign Printed Access Card, Single-Term

Ch. 14.1 - Find each value rounded to four significant...Ch. 14.1 - Find each value rounded to four significant...Ch. 14.1 - Find each value rounded to four significant...Ch. 14.1 - Find each value rounded to four significant...Ch. 14.1 - Prob. 5E Ch. 14.1 - Find each value rounded to four significant...Ch. 14.1 - Find each value rounded to four significant...Ch. 14.1 - Find each value rounded to four significant...Ch. 14.1 - Prob. 9E Ch. 14.1 - Find each value rounded to four significant...

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The area of a rectangle when the length is 42.5 m if the area of a rectangle with constant width varies directly as its length and area are 30.8 m 2 when the length is 12.8 m.

Solution Summary: The author calculates the area of a rectangle when the length is 42.5 m if the rectangle's width varies directly as its length.

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To calculate: The area of a rectangle when the length is 42.5 m if the area of a rectangle with constant width varies directly as its length and area are 30.8 m2 when the length is 12.8 m.

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Chapter 14 Solutions