EBK ORGANIC CHEMISTRY AS A SECOND LANGU
EBK ORGANIC CHEMISTRY AS A SECOND LANGU
3rd Edition
ISBN: 9781118203774
Author: Klein
Publisher: YUZU
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Chapter 13.8, Problem 3LTS
Interpretation Introduction

Interpretation: Synthesis of Epoxides has to be discussed.

Concept Introduction:

Epoxides are obtained by the conversion of Alkene using Peroxy acids and Halohydrins

Epoxides from Peroxy acids:

The commonly used Peroxy acids are meta-Chloroperoxybenzoic acid (MCPBA) and Peroxyacetic acid. This process is stereospecific.

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 13.8, Problem 3LTS , additional homework tip  1

Specifically, the substituents are cis to each other in starting Alkene remains cis to each other in Epoxide, and the substituents are trans to each other in starting Alkene remains trans to each other in Epoxide.

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 13.8, Problem 3LTS , additional homework tip  2

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 13.8, Problem 3LTS , additional homework tip  3

Epoxides from Halohydrins:

Epoxides can be obtained by the conversion of Alkene to Halohydrins. Halohydrins are formed when an Alkene is treated with halogen in presence of Water. Halohydrins formed are later treated with strong base to from Epoxides.

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 13.8, Problem 3LTS , additional homework tip  4

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Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.
Part 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answer
Part 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00

Chapter 13 Solutions

EBK ORGANIC CHEMISTRY AS A SECOND LANGU

Ch. 13.5 - Prob. 9CCCh. 13.6 - Prob. 10CCCh. 13.7 - Prob. 11CCCh. 13.7 - Prob. 12CCCh. 13.8 - Prob. 3LTSCh. 13.8 - Prob. 13PTSCh. 13.8 - Prob. 14ATSCh. 13.9 - Prob. 15CCCh. 13.10 - Prob. 4LTSCh. 13.10 - Prob. 16PTSCh. 13.10 - Prob. 17ATSCh. 13.10 - Prob. 5LTSCh. 13.10 - Prob. 18PTSCh. 13.10 - The sequence below shows an enantioselective...Ch. 13.11 - Prob. 20CCCh. 13.11 - Prob. 21CCCh. 13.12 - Prob. 6LTSCh. 13.12 - Prob. 22PTSCh. 13.12 - Prob. 23ATSCh. 13.12 - Prob. 7LTSCh. 13.12 - Prob. 24PTSCh. 13.12 - Prob. 25ATSCh. 13 - Prob. 26PPCh. 13 - Prob. 27PPCh. 13 - Prob. 28PPCh. 13 - Prob. 29PPCh. 13 - Prob. 30PPCh. 13 - Prob. 31PPCh. 13 - Prob. 32PPCh. 13 - Methylmagnesium bromide reacts rapidly with...Ch. 13 - Prob. 34PPCh. 13 - Prob. 35PPCh. 13 - Prob. 36PPCh. 13 - Prob. 37PPCh. 13 - Prob. 38PPCh. 13 - Prob. 39PPCh. 13 - Prob. 40PPCh. 13 - Prob. 41PPCh. 13 - Prob. 42PPCh. 13 - Prob. 43PPCh. 13 - Prob. 44PPCh. 13 - Prob. 45PPCh. 13 - Prob. 46IPCh. 13 - Prob. 47IPCh. 13 - Prob. 48IPCh. 13 - Prob. 49IPCh. 13 - Prob. 50IPCh. 13 - Prob. 51IPCh. 13 - Prob. 52IPCh. 13 - Prob. 53IPCh. 13 - Prob. 54IPCh. 13 - Prob. 55IPCh. 13 - Prob. 56IPCh. 13 - Prob. 57IPCh. 13 - Prob. 58IPCh. 13 - Prob. 59IPCh. 13 - Prob. 60IPCh. 13 - Prob. 61IPCh. 13 - Prob. 62IPCh. 13 - Prob. 63IPCh. 13 - Prob. 64IPCh. 13 - Prob. 65IPCh. 13 - Prob. 66IPCh. 13 - Prob. 67IPCh. 13 - Prob. 68IPCh. 13 - Prob. 69IPCh. 13 - Prob. 70IPCh. 13 - The following procedure13 is part of a synthetic...Ch. 13 - Prob. 72CPCh. 13 - Prob. 73CPCh. 13 - Prob. 74CPCh. 13 - Prob. 75CP
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