The steady-state temperature u ( x , t ) for the boundary-value problem k ∂ 2 u ∂ x 2 = ∂ u ∂ t , 0 < x < 1 , t > 0 , u ( 0 , t ) = 0 , ∂ u ∂ t | x = 1 = − h ( u ( 1 , t ) − u 0 ) , h > 0 , t > 0 and u ( x , 0 ) = f ( x ) , 0 < x < 1 .

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Chapter 13.7, Problem 2E

To determine

The steady-state temperature u(x,t) for the boundary-value problem k∂2u∂x2=∂u∂t, 0<x<1, t>0, u(0,t)=0, ∂u∂t|x=1=−h(u(1,t)−u0), h>0,t>0 and u(x,0)=f(x), 0<x<1.

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[) Hwk 25 4. [-/4 Points] Hwk 25 - (MA 244-03) (SP25) || X Answered: Homework#7 | bartle X + https://www.webassign.net/web/Student/Assignment-Responses/last?dep=36606604 DETAILS MY NOTES LARLINALG8 6.4.019. Use the matrix P to determine if the matrices A and A' are similar. -1 -1 12 9 '-[ ¯ ¯ ], ^ - [ _—2—2 _ ' ], ^' - [ ˜³ −10] P = 1 2 A = -20-11 A' -3-10 6 4 P-1 = Are they similar? Yes, they are similar. No, they are not similar. Need Help? Read It SUBMIT ANSWER P-1AP = 5. [-/4 Points] DETAILS MY NOTES LARLINALG8 6.4.023. Suppose A is the matrix for T: R³ - → R³ relative to the standard basis. Find the diagonal matrix A' for T relative to the basis B'. A' = -1 -2 0 A = -1 0 0 ' 0 02 B' = {(−1, 1, 0), (2, 1, 0), (0, 0, 1)} ☐☐☐ ↓ ↑ Need Help? Read It Update available →] - restart now ASK YOUR T Sync and save data { Sign In ill ↑ New tab HT New window N New private window +HP ASK YOUR T Bookmarks History Downloads > > HJ Passwords Add-ons and themes HA Print... HP Save page as... HS…

Clarification: 1. f doesn’t have REAL roots2. f is a quadratic, so a≠0

[J) Hwk 25 Hwk 25 - (MA 244-03) (SP25) || X Answered: Homework#7 | bartle X + https://www.webassign.net/web/Student/Assignment-Responses/last?dep=36606604 1. [-/4 Points] DETAILS MY NOTES Find the matrix A' for T relative to the basis B'. LARLINALG8 6.4.003. T: R² → R², T(x, y) = (x + y, 4y), B' = {(−4, 1), (1, −1)} A' = Need Help? Read It Watch It SUBMIT ANSWER 2. [-/4 Points] DETAILS MY NOTES LARLINALG8 6.4.007. Find the matrix A' for T relative to the basis B'. T: R³ → R³, T(x, y, z) = (x, y, z), B' = {(0, 1, 1), (1, 0, 1), (1, 1, 0)} A' = ↓ ↑ Need Help? Read It SUBMIT ANSWER 具⇧ ASK YOUR TEACHER PRACTICE ANOTHER ill ASK YOUR TEACHER PRACTICE ANOTHER 3. [-/4 Points] DETAILS MY NOTES LARLINALG8 6.4.013. ASK YOUR TEACHER PRACTICE ANOTHER

Answer 2

Question

Chapter 13.7, Problem 2E

To determine

The steady-state temperature u(x,t) for the boundary-value problem k∂2u∂x2=∂u∂t, 0<x<1, t>0, u(0,t)=0, ∂u∂t|x=1=−h(u(1,t)−u0), h>0,t>0 and u(x,0)=f(x), 0<x<1.

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Answer 3

Question

Chapter 13.7, Problem 2E

To determine

The steady-state temperature u(x,t) for the boundary-value problem k∂2u∂x2=∂u∂t, 0<x<1, t>0, u(0,t)=0, ∂u∂t|x=1=−h(u(1,t)−u0), h>0,t>0 and u(x,0)=f(x), 0<x<1.

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Answer 4

Question

Chapter 13.7, Problem 2E

To determine

The steady-state temperature u(x,t) for the boundary-value problem k∂2u∂x2=∂u∂t, 0<x<1, t>0, u(0,t)=0, ∂u∂t|x=1=−h(u(1,t)−u0), h>0,t>0 and u(x,0)=f(x), 0<x<1.

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Answer 5

Chapter 13.7, Problem 2E

To determine

The steady-state temperature u(x,t) for the boundary-value problem k∂2u∂x2=∂u∂t, 0<x<1, t>0, u(0,t)=0, ∂u∂t|x=1=−h(u(1,t)−u0), h>0,t>0 and u(x,0)=f(x), 0<x<1.

Answer 6

Chapter 13.7, Problem 2E

To determine

The steady-state temperature u(x,t) for the boundary-value problem k∂2u∂x2=∂u∂t, 0<x<1, t>0, u(0,t)=0, ∂u∂t|x=1=−h(u(1,t)−u0), h>0,t>0 and u(x,0)=f(x), 0<x<1.

Answer 7

Chapter 13.7, Problem 2E

To determine

The steady-state temperature u(x,t) for the boundary-value problem k∂2u∂x2=∂u∂t, 0<x<1, t>0, u(0,t)=0, ∂u∂t|x=1=−h(u(1,t)−u0), h>0,t>0 and u(x,0)=f(x), 0<x<1.

Answer 8

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Answer 10

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Answer 11

Ch. 13.1 - Prob. 1E Ch. 13.1 - Prob. 2E Ch. 13.1 - Prob. 3E Ch. 13.1 - Prob. 4E Ch. 13.1 - Prob. 5E Ch. 13.1 - Prob. 6E Ch. 13.1 - Prob. 7E Ch. 13.1 - Prob. 8E Ch. 13.1 - Prob. 9E Ch. 13.1 - Prob. 10E

The steady-state temperature u ( x , t ) for the boundary-value problem k ∂ 2 u ∂ x 2 = ∂ u ∂ t , 0 < x < 1 , t > 0 , u ( 0 , t ) = 0 , ∂ u ∂ t | x = 1 = − h ( u ( 1 , t ) − u 0 ) , h > 0 , t > 0 and u ( x , 0 ) = f ( x ) , 0 < x < 1 .

Solution Summary: The author explains the steady-state temperature u(x,t) for the boundary-value problem.

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The steady-state temperature u(x,t) for the boundary-value problem k∂2u∂x2=∂u∂t, 0<x<1, t>0, u(0,t)=0, ∂u∂t|x=1=−h(u(1,t)−u0), h>0,t>0 and u(x,0)=f(x), 0<x<1.

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Chapter 13 Solutions

The steady-state temperature u ( x , t ) for the boundary-value problem k ∂ 2 u ∂ x 2 = ∂ u ∂ t , 0 &lt; x &lt; 1 , t &gt; 0 , u ( 0 , t ) = 0 , ∂ u ∂ t | x = 1 = − h ( u ( 1 , t ) − u 0 ) , h &gt; 0 , t &gt; 0 and u ( x , 0 ) = f ( x ) , 0 &lt; x &lt; 1 .

Solution Summary: The author explains the steady-state temperature u(x,t) for the boundary-value problem.

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The steady-state temperature u(x,t) for the boundary-value problem k∂2u∂x2=∂u∂t, 0<x<1, t>0, u(0,t)=0, ∂u∂t|x=1=−h(u(1,t)−u0), h>0,t>0 and u(x,0)=f(x), 0<x<1.

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Chapter 13 Solutions

The steady-state temperature u ( x , t ) for the boundary-value problem k ∂ 2 u ∂ x 2 = ∂ u ∂ t , 0 < x < 1 , t > 0 , u ( 0 , t ) = 0 , ∂ u ∂ t | x = 1 = − h ( u ( 1 , t ) − u 0 ) , h > 0 , t > 0 and u ( x , 0 ) = f ( x ) , 0 < x < 1 .