Explanation Given: The integral: ∫ 1 49 ( 1 + x ) 4 3 x d x . Calculation: Let x 1 2 + 1 = t . Now, take derivative. 1 2 x 1 2 − 1 d x = d t 1 2 x − 1 2 d x = d t 1 x d x = 2 d t When x = 1 , x 1 2 + 1 = t t = ( 1 ) 1 2 + 1 t = 2 When x = 49 , x 1 2 + 1 = t t = ( 49 ) 1 2 + 1 = 7 + 1 t = 8 Replace 1 x d x = 2 d t and limits from t = 2 to t = 8 in ∫ 1 49 ( 1 + x ) 4 3 x d x , to get: ∫ 2 8 <

Pearson eText for Mathematics with Applications In the Management, Natural, and Social Sciences -- Instant Access (Pearson+)

12th Edition

ISBN: 9780137504381

Author: Margaret Lial, Thomas Hungerford

Publisher: PEARSON+

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Chapter 13.5, Problem 27E

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To calculate: The value of provided definite integral.

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Pearson eText for Mathematics with Applications In the Management, Natural, and Social Sciences -- Instant Access (Pearson+)

Ch. 13.1 - Checkpoint 1 Find an antiderivative for each of...Ch. 13.1 - Checkpoint 2 Find each of the...Ch. 13.1 - Prob. 3CP Ch. 13.1 - Prob. 4CP Ch. 13.1 - Prob. 5CP Ch. 13.1 - Prob. 6CP Ch. 13.1 - Prob. 7CP Ch. 13.1 - Checkpoint 8 The marginal cost at a level of...Ch. 13.1 - 1. What must be true of F(x) and G(x) if both are...Ch. 13.1 - 2. How is the antiderivative of a function related...

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