Equations of lines Find both the parametric and the vector equations of the following lines. 26. The line that is perpendicular to the lines r = 〈 − 2 + 3 t , 2 t , 3 t 〉 and R = 〈 − 6 + s , − 8 + 2 s , − 12 + 3 s 〉 , and passes through the point of intersection of the lines r and R
Equations of lines Find both the parametric and the vector equations of the following lines. 26. The line that is perpendicular to the lines r = 〈 − 2 + 3 t , 2 t , 3 t 〉 and R = 〈 − 6 + s , − 8 + 2 s , − 12 + 3 s 〉 , and passes through the point of intersection of the lines r and R
Equations of lines Find both the parametric and the vector equations of the following lines.
26. The line that is perpendicular to the lines r =
〈
−
2
+
3
t
,
2
t
,
3
t
〉
and R =
〈
−
6
+
s
,
−
8
+
2
s
,
−
12
+
3
s
〉
, and passes through the point of intersection of the lines r and R
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
Describe the graph of the equation.
r= (7 - 21) i + 8rj
O Itis a line in 2-space through the point (7, 0) and parallel to the vector v = -2i+ 8 j.
O Itisa plane in 2-space through the point (-2, 8) and parallel to the vector v = 7i.
O Itis a plane in 2-space through the point (7, 0) and parallel to the vector v = -2i+ 8j.
O Itis a line in 2-space through the point (-2, 8) and parallel to the vector v = 7i.
O Itis a line in 2-space through the point (7, 2) and parallel to the vector v = 8j.
Find the component form of v and sketch the specified vector operations geometrically, where u = 3i − j, and w = i + 3j.
v = −u + w
1. (a) A vector in the plane is a line segment with an assigned
direction. In Figure I below, the vector u has initial point
. and terminal point .
vectors 2u and u + v.
Sketch the
(b) A vector in a coordinate plane is expressed by using
components. In Figure II below, the vector u has initial
point (,D and terminal point (.). In compo-
nent form we write u = (.), and v =
Then 2u = (. ) and u + v = (
D
B
u
I
II
Chapter 13 Solutions
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